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Question Number 202773 Answers: 0 Comments: 9

Question Number 202771 Answers: 1 Comments: 0

determine whether this signal is periodic or not if it′s periodic specify it′s faundemwntal period y(n)=cos((n/8))cos(((nπ)/8))

$${determine}\:{whether}\:{this}\:{signal}\:{is}\:{periodic} \\ $$$${or}\:{not}\:{if}\:{it}'{s}\:{periodic}\:{specify}\:{it}'{s}\: \\ $$$${faundemwntal}\:{period} \\ $$$${y}\left({n}\right)={cos}\left(\frac{{n}}{\mathrm{8}}\right){cos}\left(\frac{{n}\pi}{\mathrm{8}}\right)\: \\ $$

Question Number 202796 Answers: 1 Comments: 0

[2^(8÷2−1) +4÷{2+2^(4÷(1+1)) ÷(6÷3−1)}]÷[6÷{(3^(4÷2) +5÷5)÷2−6÷(5−2)}]

$$\left[\mathrm{2}^{\mathrm{8}\boldsymbol{\div}\mathrm{2}−\mathrm{1}} +\mathrm{4}\boldsymbol{\div}\left\{\mathrm{2}+\mathrm{2}^{\mathrm{4}\boldsymbol{\div}\left(\mathrm{1}+\mathrm{1}\right)} \boldsymbol{\div}\left(\mathrm{6}\boldsymbol{\div}\mathrm{3}−\mathrm{1}\right)\right\}\right]\boldsymbol{\div}\left[\mathrm{6}\boldsymbol{\div}\left\{\left(\mathrm{3}^{\mathrm{4}\boldsymbol{\div}\mathrm{2}} +\mathrm{5}\boldsymbol{\div}\mathrm{5}\right)\boldsymbol{\div}\mathrm{2}−\mathrm{6}\boldsymbol{\div}\left(\mathrm{5}−\mathrm{2}\right)\right\}\right] \\ $$

Question Number 202795 Answers: 3 Comments: 0

if f(−1)=f(0)=f(2)=0 and f(1)=6 then find f(x)=?

$${if}\:{f}\left(−\mathrm{1}\right)={f}\left(\mathrm{0}\right)={f}\left(\mathrm{2}\right)=\mathrm{0}\:{and}\:{f}\left(\mathrm{1}\right)=\mathrm{6} \\ $$$${then}\:{find}\:{f}\left({x}\right)=? \\ $$

Question Number 202765 Answers: 2 Comments: 0

Question Number 202762 Answers: 1 Comments: 0

Question Number 202761 Answers: 1 Comments: 0

Question Number 202760 Answers: 1 Comments: 0

Question Number 202759 Answers: 0 Comments: 0

Let A={x∣x^2 −4x+3<0,x∈R},B={x∣2^(1−x) +a≤0,x^2 −2(a+7)x+5≤0,x∈R} If A⊆B Find the range of real number a

$${Let}\:{A}=\left\{{x}\mid{x}^{\mathrm{2}} −\mathrm{4}{x}+\mathrm{3}<\mathrm{0},{x}\in{R}\right\},{B}=\left\{{x}\mid\mathrm{2}^{\mathrm{1}−{x}} +{a}\leqslant\mathrm{0},{x}^{\mathrm{2}} −\mathrm{2}\left({a}+\mathrm{7}\right){x}+\mathrm{5}\leqslant\mathrm{0},{x}\in{R}\right\} \\ $$$${If}\:{A}\subseteq{B}\:{Find}\:{the}\:{range}\:{of}\:{real}\:{number}\:{a} \\ $$

Question Number 202750 Answers: 2 Comments: 1

place(1→25) in table(5×5)in such away that the sum is constant in all directions. [ ∣×_− ^− ∣ ]→(direction)

$${place}\left(\mathrm{1}\rightarrow\mathrm{25}\right) \\ $$$${in}\:{table}\left(\mathrm{5}×\mathrm{5}\right){in}\:{such}\:{away}\:{that} \\ $$$${the}\:{sum}\:{is}\:{constant}\:{in}\:{all}\:{directions}. \\ $$$$\left[\:\mid\underset{−} {\overset{−} {×}}\mid\:\right]\rightarrow\left({direction}\right) \\ $$

Question Number 202749 Answers: 1 Comments: 3

Question Number 202747 Answers: 1 Comments: 0

Series Σ (((−1)^(h−1) )/p_h ) is Converge?? h∈Z^+ , p_h ∈P^+ P^+ = 2 , 3 , 5 , 7 , 11 , 13 , ....

$$\mathrm{Series}\:\:\Sigma\:\frac{\left(−\mathrm{1}\right)^{{h}−\mathrm{1}} }{{p}_{{h}} }\:\mathrm{is}\:\mathrm{Converge}??\:{h}\in\mathbb{Z}^{+} \:,\:{p}_{{h}} \in\mathbb{P}^{+} \\ $$$$\mathbb{P}^{+} =\:\mathrm{2}\:,\:\mathrm{3}\:,\:\mathrm{5}\:,\:\mathrm{7}\:,\:\mathrm{11}\:,\:\mathrm{13}\:,\:....\: \\ $$

Question Number 202740 Answers: 0 Comments: 0

Question Number 202737 Answers: 1 Comments: 0

determinant (((H^(A^(P^(P^(Y^(N^E W) Y) E) A) R) !_(24^(0^2 ) ) )))

$$\:\:\:\:\:\:\:\:\:\begin{array}{|c|}{\underset{\overset{\overset{\mathrm{2}} {\mathrm{0}}} {\mathrm{24}}} {\mathbb{H}^{\mathbb{A}^{\mathbb{P}^{\mathbb{P}^{\mathbb{Y}^{\mathbb{N}^{\mathbb{E}} \mathbb{W}} \mathbb{Y}} \mathbb{E}} \mathbb{A}} \mathbb{R}} \:!}}\\\hline\end{array} \\ $$

Question Number 202723 Answers: 0 Comments: 0

Question Number 202721 Answers: 0 Comments: 0

determinant (((2^2 +4^2 +6^2 +∙∙∙∙∙+22^2 =2024_(HAPPY NEW YEAR!) ))) determinant ((( May 2024 be { ((war-free!)),(&),((peaceful!)) :} )))

$$\:\:\:\begin{array}{|c|}{\underset{\mathcal{HAPPY}\:\mathcal{NEW}\:\mathcal{YEAR}!} {\mathrm{2}^{\mathrm{2}} +\mathrm{4}^{\mathrm{2}} +\mathrm{6}^{\mathrm{2}} +\centerdot\centerdot\centerdot\centerdot\centerdot+\mathrm{22}^{\mathrm{2}} =\mathrm{2024}}}\\\hline\end{array} \\ $$$$\begin{array}{|c|}{\:\:\:\mathrm{May}\:\mathrm{2024}\:\mathrm{be}\:\begin{cases}{\mathrm{war}-\mathrm{free}!}\\{\&}\\{{peaceful}!}\end{cases}\:\:\:}\\\hline\end{array} \\ $$$$ \\ $$

Question Number 202716 Answers: 1 Comments: 0

abcd ^(−) is a four digit number such that a^2 +b^2 +c^2 +d^2 = cd ^(−) and cd ^(−) − d ^(−) = ab ^(−) . Find the number.

$$\overline {\:\:{abcd}\:\:}{is}\:{a}\:{four}\:{digit}\:{number} \\ $$$${such}\:{that}\:{a}^{\mathrm{2}} +{b}^{\mathrm{2}} +{c}^{\mathrm{2}} +{d}^{\mathrm{2}} =\overline {\:{cd}\:} \\ $$$${and}\:\overline {\:{cd}\:}−\overline {\:{d}\:}=\overline {\:{ab}\:}. \\ $$$$\mathcal{F}{ind}\:{the}\:{number}. \\ $$

Question Number 202731 Answers: 1 Comments: 0

∫_0 ^1 ((ln(x)ln(1−x))/( x(√(1−x))))dx

$$\int_{\mathrm{0}} ^{\mathrm{1}} \frac{{ln}\left({x}\right){ln}\left(\mathrm{1}−{x}\right)}{\:{x}\sqrt{\mathrm{1}−{x}}}{dx} \\ $$

Question Number 202715 Answers: 2 Comments: 0

determinant ((( Square of mean of two numbers_(is 2025) ))) & determinant ((( mean of squares of the numbers_( is 2026) ))) determinant (((Find the product of the numbers.)))

$$\begin{array}{|c|}{\:\:\underset{\mathrm{is}\:\mathrm{2025}} {\mathrm{Square}\:\mathrm{of}\:\mathrm{mean}\:\mathrm{of}\:\mathrm{two}\:\mathrm{numbers}}\:\:}\\\hline\end{array}\: \\ $$$$\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\& \\ $$$$\begin{array}{|c|}{\:\:\underset{\:\mathrm{is}\:\mathrm{2026}} {\mathrm{mean}\:\mathrm{of}\:\mathrm{squares}\:\mathrm{of}\:\mathrm{the}\:\mathrm{numbers}}\:\:}\\\hline\end{array} \\ $$$$\:\:\:\:\: \\ $$$$\begin{array}{|c|}{\mathrm{Find}\:\mathrm{the}\:\mathrm{product}\:\mathrm{of}\:\mathrm{the}\:\mathrm{numbers}.}\\\hline\end{array}\: \\ $$

Question Number 202726 Answers: 0 Comments: 4

pk=b pq+sk=c sq=d (√t)=((t−q)/k)=((t−s)/p) Given are b, c, d. Find t.

$${pk}={b} \\ $$$${pq}+{sk}={c} \\ $$$${sq}={d} \\ $$$$\sqrt{{t}}=\frac{{t}−{q}}{{k}}=\frac{{t}−{s}}{{p}} \\ $$$${Given}\:{are}\:{b},\:{c},\:{d}.\:{Find}\:{t}. \\ $$

Question Number 202701 Answers: 0 Comments: 1

Question Number 202698 Answers: 1 Comments: 0

determine le reste de la division eucludienne de 2023^(2019) par 13

$${determine}\:{le}\:{reste}\:{de}\:{la}\:{division}\:{eucludienne}\:{de}\:\mathrm{2023}^{\mathrm{2019}} {par}\:\mathrm{13} \\ $$

Question Number 202694 Answers: 3 Comments: 0

Question Number 202684 Answers: 1 Comments: 0

Question Number 202679 Answers: 1 Comments: 0

Question Number 202677 Answers: 2 Comments: 0

If x^2 − y^2 = 2023^(2024) & x, y ∈ N how many set{x, y}

$$ \\ $$$$\mathrm{If}\:{x}^{\mathrm{2}} \:−\:{y}^{\mathrm{2}} \:=\:\mathrm{2023}^{\mathrm{2024}} \:\&\:{x},\:{y}\:\in\:\boldsymbol{\mathrm{N}} \\ $$$$\mathrm{how}\:\mathrm{many}\:\mathrm{set}\left\{{x},\:{y}\right\} \\ $$

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