Question and Answers Forum

AllQuestion and Answers: Page 1857

Question Number 22959 Answers: 0 Comments: 0

Question Number 22947 Answers: 0 Comments: 0

lim_(x→π/2) (1^(sec^2 x) +2^(sec^2 x) +3^(sec^2 x) +.... ...+n^(sec^2 x) )^(cos^2 x) = ?

$$\underset{{x}\rightarrow\pi/\mathrm{2}} {\mathrm{lim}}\:\left(\mathrm{1}^{\mathrm{sec}\:^{\mathrm{2}} {x}} +\mathrm{2}^{\mathrm{sec}\:^{\mathrm{2}} {x}} +\mathrm{3}^{\mathrm{sec}\:^{\mathrm{2}} {x}} +....\right. \\ $$$$\left.\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:...+{n}^{\mathrm{sec}\:^{\mathrm{2}} {x}} \right)^{\mathrm{cos}\:^{\mathrm{2}} {x}} \:=\:? \\ $$$$ \\ $$

Question Number 22946 Answers: 2 Comments: 0

∫_1 ^3 ((4x+1)/(2x^2 +x−2))dx ?solve

$$\underset{\mathrm{1}} {\overset{\mathrm{3}} {\int}}\frac{\mathrm{4}\boldsymbol{\mathrm{x}}+\mathrm{1}}{\mathrm{2}\boldsymbol{\mathrm{x}}^{\mathrm{2}} +\boldsymbol{\mathrm{x}}−\mathrm{2}}\boldsymbol{\mathrm{dx}}\:\:\:?\boldsymbol{\mathrm{solve}} \\ $$

Question Number 22945 Answers: 0 Comments: 0

Question Number 22940 Answers: 0 Comments: 1

Question Number 22939 Answers: 1 Comments: 0

Question Number 22937 Answers: 0 Comments: 0

Question Number 22930 Answers: 1 Comments: 0

Question Number 22929 Answers: 1 Comments: 0

Question Number 22928 Answers: 1 Comments: 0

Question Number 22956 Answers: 1 Comments: 4

Question Number 22923 Answers: 1 Comments: 0

Question Number 22922 Answers: 0 Comments: 0

Question Number 22896 Answers: 0 Comments: 1

how can demonstred 17^(4n+1) +3×9^(2n+1) ≡0[11]

$${how}\:{can}\:{demonstred} \\ $$$$\mathrm{17}^{\mathrm{4}{n}+\mathrm{1}} +\mathrm{3}×\mathrm{9}^{\mathrm{2}{n}+\mathrm{1}} \equiv\mathrm{0}\left[\mathrm{11}\right] \\ $$

Question Number 22941 Answers: 1 Comments: 3

Question Number 22893 Answers: 1 Comments: 0

A wedge has two equally rough faces each inclined at 30° to the horizontal.Masses of 5kg and 2kg ,one on each face,are connected by a light string passing over a smooth pulley at the top of the wedge.The coefficient of friction μ, between each masses and the surface of the wedge is 0.2.Find the acceleration of the masses when they are released.

$${A}\:{wedge}\:{has}\:{two}\:{equally}\:{rough} \\ $$$${faces}\:{each}\:{inclined}\:{at}\:\mathrm{30}°\:{to}\:{the} \\ $$$${horizontal}.{Masses}\:{of}\:\mathrm{5}{kg}\:{and}\:\mathrm{2}{kg} \\ $$$$,{one}\:{on}\:{each}\:{face},{are}\:{connected} \\ $$$${by}\:{a}\:{light}\:{string}\:{passing}\:{over}\:{a} \\ $$$${smooth}\:{pulley}\:{at}\:{the}\:{top}\:{of}\:{the} \\ $$$${wedge}.{The}\:{coefficient}\:{of}\:{friction}\: \\ $$$$\mu,\:{between}\:{each}\:{masses}\:{and}\:{the} \\ $$$${surface}\:{of}\:{the}\:{wedge}\:{is}\:\mathrm{0}.\mathrm{2}.{Find} \\ $$$${the}\:{acceleration}\:{of}\:{the}\:{masses} \\ $$$${when}\:{they}\:{are}\:{released}. \\ $$

Question Number 22892 Answers: 0 Comments: 3

A horizontal force of 10N just prevents a mass of 2kg from sliding down a rough plane inclined at 45° to the horizontal. Find the coefficient of friction.

$${A}\:{horizontal}\:{force}\:{of}\:\mathrm{10}{N}\:{just} \\ $$$${prevents}\:{a}\:{mass}\:{of}\:\mathrm{2}{kg}\:{from} \\ $$$${sliding}\:{down}\:{a}\:{rough}\:{plane} \\ $$$${inclined}\:{at}\:\mathrm{45}°\:{to}\:{the}\:{horizontal}. \\ $$$${Find}\:{the}\:{coefficient}\:{of}\:{friction}. \\ $$

Question Number 22883 Answers: 1 Comments: 1

The correct order of second ionisation energy in the following : (a) F > O > N > C (b) O > F > N > C (c) O > N > F > C (d) C > N > O > F

$$\mathrm{The}\:\mathrm{correct}\:\mathrm{order}\:\mathrm{of}\:\mathrm{second}\:\mathrm{ionisation} \\ $$$$\mathrm{energy}\:\mathrm{in}\:\mathrm{the}\:\mathrm{following}\:: \\ $$$$\left({a}\right)\:\mathrm{F}\:>\:\mathrm{O}\:>\:\mathrm{N}\:>\:\mathrm{C} \\ $$$$\left({b}\right)\:\mathrm{O}\:>\:\mathrm{F}\:>\:\mathrm{N}\:>\:\mathrm{C} \\ $$$$\left({c}\right)\:\mathrm{O}\:>\:\mathrm{N}\:>\:\mathrm{F}\:>\:\mathrm{C} \\ $$$$\left({d}\right)\:\mathrm{C}\:>\:\mathrm{N}\:>\:\mathrm{O}\:>\:\mathrm{F} \\ $$

Question Number 22881 Answers: 0 Comments: 3

which is your favourite subject?

$${which}\:{is}\:{your}\:{favourite}\:{subject}? \\ $$

Question Number 22879 Answers: 1 Comments: 0

The Enthalpy of neutralization of acetic acid and sodium hydroxide is −55.4 kJ. What is the enthalpy of ionisation of acetic acid?

$$\mathrm{The}\:\mathrm{Enthalpy}\:\mathrm{of}\:\mathrm{neutralization}\:\mathrm{of} \\ $$$$\mathrm{acetic}\:\mathrm{acid}\:\mathrm{and}\:\mathrm{sodium}\:\mathrm{hydroxide}\:\mathrm{is} \\ $$$$−\mathrm{55}.\mathrm{4}\:\mathrm{kJ}.\:\mathrm{What}\:\mathrm{is}\:\mathrm{the}\:\mathrm{enthalpy}\:\mathrm{of} \\ $$$$\mathrm{ionisation}\:\mathrm{of}\:\mathrm{acetic}\:\mathrm{acid}? \\ $$

Question Number 22872 Answers: 1 Comments: 4

Question Number 22856 Answers: 0 Comments: 1

solve: sin(x)=2, x∈C

$$\mathrm{solve}:\:\mathrm{sin}\left({x}\right)=\mathrm{2},\:\:\:{x}\in\mathbb{C} \\ $$

Question Number 22855 Answers: 1 Comments: 1

Equal forces act on two bodies which are initially at rest,for equal times.If the ratio of the masses is 4:3,What is the ratio of the distance covered?

$${Equal}\:{forces}\:{act}\:{on}\:{two}\:{bodies} \\ $$$${which}\:{are}\:{initially}\:{at}\:{rest},{for} \\ $$$${equal}\:{times}.{If}\:{the}\:{ratio}\:{of}\:{the}\: \\ $$$${masses}\:{is}\:\mathrm{4}:\mathrm{3},{What}\:{is}\:{the}\:{ratio} \\ $$$${of}\:{the}\:{distance}\:{covered}? \\ $$

Question Number 22884 Answers: 1 Comments: 0

A body of mass 0.3 kg is taken up an inclined plane of length 10 m and height 5 m, and then allowed to slide down to the bottom again. The coefficient of friction between the body and the plane is 0.15. What is the kinetic energy of the body at the end of the trip?

$$\mathrm{A}\:\mathrm{body}\:\mathrm{of}\:\mathrm{mass}\:\mathrm{0}.\mathrm{3}\:\mathrm{kg}\:\mathrm{is}\:\mathrm{taken}\:\mathrm{up}\:\mathrm{an} \\ $$$$\mathrm{inclined}\:\mathrm{plane}\:\mathrm{of}\:\mathrm{length}\:\mathrm{10}\:\mathrm{m}\:\mathrm{and} \\ $$$$\mathrm{height}\:\mathrm{5}\:\mathrm{m},\:\mathrm{and}\:\mathrm{then}\:\mathrm{allowed}\:\mathrm{to}\:\mathrm{slide} \\ $$$$\mathrm{down}\:\mathrm{to}\:\mathrm{the}\:\mathrm{bottom}\:\mathrm{again}.\:\mathrm{The} \\ $$$$\mathrm{coefficient}\:\mathrm{of}\:\mathrm{friction}\:\mathrm{between}\:\mathrm{the}\:\mathrm{body} \\ $$$$\mathrm{and}\:\mathrm{the}\:\mathrm{plane}\:\mathrm{is}\:\mathrm{0}.\mathrm{15}.\:\mathrm{What}\:\mathrm{is}\:\mathrm{the} \\ $$$$\mathrm{kinetic}\:\mathrm{energy}\:\mathrm{of}\:\mathrm{the}\:\mathrm{body}\:\mathrm{at}\:\mathrm{the}\:\mathrm{end}\:\mathrm{of} \\ $$$$\mathrm{the}\:\mathrm{trip}? \\ $$

Question Number 22837 Answers: 0 Comments: 0

The effective nuclear charge of N on its last electron is:−

$$\mathrm{The}\:\mathrm{effective}\:\mathrm{nuclear}\:\mathrm{charge}\:\mathrm{of}\:\mathrm{N}\:\mathrm{on}\:\mathrm{its} \\ $$$$\mathrm{last}\:\mathrm{electron}\:\mathrm{is}:− \\ $$

Question Number 22871 Answers: 1 Comments: 0

If f(n)=(1/n)[(n+1)(n+2)(n+3)...(n+n)]^(1/n) , then lim_(n→∞) f(n) =

$$\mathrm{If}\:\:{f}\left({n}\right)=\frac{\mathrm{1}}{{n}}\left[\left({n}+\mathrm{1}\right)\left({n}+\mathrm{2}\right)\left({n}+\mathrm{3}\right)...\left({n}+{n}\right)\right]^{\mathrm{1}/{n}} , \\ $$$$\mathrm{then}\:\:\:\underset{{n}\rightarrow\infty} {\mathrm{lim}}{f}\left({n}\right)\:= \\ $$

Pg 1852 Pg 1853 Pg 1854 Pg 1855 Pg 1856 Pg 1857 Pg 1858 Pg 1859 Pg 1860 Pg 1861

Contact: info@tinkutara.com