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Question Number 25600 Answers: 1 Comments: 0

A block pulled along a horizontal floo by a horizontal rope. The tension in the rope is 500N and the blocks moves at a constant speed of 2.75ms^(−1.) Find the work done by the tension in 40s and also find the power applied by the tension. GUYS PLS HELP

$$\mathrm{A}\:\mathrm{block}\:\mathrm{pulled}\:\mathrm{along}\:\mathrm{a}\:\mathrm{horizontal}\:\mathrm{floo} \\ $$$$\mathrm{by}\:\mathrm{a}\:\mathrm{horizontal}\:\mathrm{rope}. \\ $$$$\mathrm{The}\:\mathrm{tension}\:\mathrm{in}\:\mathrm{the}\:\mathrm{rope}\:\mathrm{is}\:\mathrm{500N}\:\mathrm{and}\:\mathrm{the} \\ $$$$\mathrm{blocks}\:\mathrm{moves}\:\mathrm{at}\:\mathrm{a}\:\mathrm{constant}\:\mathrm{speed}\:\mathrm{of}\:\mathrm{2}.\mathrm{75ms}^{−\mathrm{1}.} \\ $$$$\mathrm{Find}\:\mathrm{the}\:\mathrm{work}\:\mathrm{done}\:\mathrm{by}\:\mathrm{the}\:\mathrm{tension}\:\mathrm{in}\:\mathrm{40s} \\ $$$$\mathrm{and}\:\mathrm{also}\:\mathrm{find}\:\mathrm{the}\:\mathrm{power}\:\mathrm{applied}\:\mathrm{by}\:\mathrm{the}\:\mathrm{tension}. \\ $$$$\mathrm{GUYS}\:\mathrm{PLS}\:\mathrm{HELP} \\ $$

Question Number 25593 Answers: 1 Comments: 0

if : log_6 ^(45) =x , log_(18) ^(24) =y then : log _(12)^(25) =?(in terms of x,y)

$$\boldsymbol{{if}}\:\::\:\:\:\boldsymbol{{log}}_{\mathrm{6}} ^{\mathrm{45}} =\boldsymbol{{x}}\:\:,\:\:\:\boldsymbol{{log}}_{\mathrm{18}} ^{\mathrm{24}} =\boldsymbol{{y}} \\ $$$$\boldsymbol{{then}}\::\:\:\:\boldsymbol{{log}}\:_{\mathrm{12}} ^{\mathrm{25}} \:=?\left(\mathrm{in}\:\mathrm{terms}\:\mathrm{of}\:\mathrm{x},\mathrm{y}\right) \\ $$

Question Number 25611 Answers: 0 Comments: 0

if cosh(u+iv)=x+iy , show that (x^2 /(cosh^2 u))+(y^2 /(sinh^2 u))=1 and (x^2 /(cosh^2 v))−(y^2 /(sinh^2 v))=1 where sinhx and coshx hhyperbolcfunction

$${if}\:{cosh}\left({u}+{iv}\right)={x}+{iy}\:,\:{show}\:{that} \\ $$$$\frac{{x}^{\mathrm{2}} }{{cosh}^{\mathrm{2}} {u}}+\frac{{y}^{\mathrm{2}} }{{sinh}^{\mathrm{2}} {u}}=\mathrm{1}\:\:{and}\:\:\frac{{x}^{\mathrm{2}} }{{cosh}^{\mathrm{2}} {v}}−\frac{{y}^{\mathrm{2}} }{{sinh}^{\mathrm{2}} {v}}=\mathrm{1} \\ $$$$ \\ $$$${where}\:\:\:\:{sinhx}\:{and}\:{coshx}\:\:\:\:{hhyperbolcfunction} \\ $$

Question Number 25589 Answers: 0 Comments: 3

possible or not ? a^a +b^b > a^b +b^a with below conditions: case 1) a>b>1 case 2) 0<b<a<1

$$\boldsymbol{{possible}}\:\boldsymbol{{or}}\:\boldsymbol{{not}}\:? \\ $$$$\:\:\:\:\:\:\:\:\boldsymbol{{a}}^{\boldsymbol{{a}}} +\boldsymbol{{b}}^{\boldsymbol{{b}}} >\:\boldsymbol{{a}}^{\boldsymbol{{b}}} +\boldsymbol{{b}}^{\boldsymbol{{a}}} \\ $$$$\boldsymbol{{with}}\:\boldsymbol{{below}}\:\boldsymbol{{conditions}}: \\ $$$$\left.\:\boldsymbol{{case}}\:\mathrm{1}\right)\:\:\boldsymbol{{a}}>\boldsymbol{{b}}>\mathrm{1} \\ $$$$\left.\boldsymbol{{case}}\:\mathrm{2}\right)\:\:\:\:\mathrm{0}<\boldsymbol{{b}}<\boldsymbol{{a}}<\mathrm{1} \\ $$

Question Number 25588 Answers: 1 Comments: 1

lim_(x→0) (((x−tgx)/(x−sinx)))=? l′hopital role not allowed!

$$\underset{{x}\rightarrow\mathrm{0}} {\mathrm{lim}}\left(\frac{\boldsymbol{{x}}−\boldsymbol{{tgx}}}{\boldsymbol{{x}}−\boldsymbol{{sinx}}}\right)=? \\ $$$$\boldsymbol{{l}}'\boldsymbol{{hopital}}\:\boldsymbol{{role}}\:\boldsymbol{{not}}\:\boldsymbol{{allowed}}! \\ $$

Question Number 25587 Answers: 0 Comments: 0

∫ (dx/(1+lnx))=?

$$\int\:\:\frac{\boldsymbol{{dx}}}{\mathrm{1}+\boldsymbol{{lnx}}}=? \\ $$

Question Number 25578 Answers: 0 Comments: 0

3 men A,B and C can complete a work in such a way that A works for all the days, B works for 1st and 2nd day and C works for 3rd, 4th and 5th day. If B and C can do as much work in two days as a alone does in 3 days. If B and C can complete the work without tbe help of A in 6 days then how many dahs A alone do the work?

$$\mathrm{3}\:\mathrm{men}\:\mathrm{A},\mathrm{B}\:\mathrm{and}\:\mathrm{C}\:\mathrm{can}\:\mathrm{complete}\:\mathrm{a} \\ $$$$\mathrm{work}\:\mathrm{in}\:\mathrm{such}\:\mathrm{a}\:\mathrm{way}\:\mathrm{that}\:\mathrm{A}\:\mathrm{works}\:\mathrm{for} \\ $$$$\mathrm{all}\:\mathrm{the}\:\mathrm{days},\:\mathrm{B}\:\mathrm{works}\:\mathrm{for}\:\mathrm{1st}\:\mathrm{and}\:\mathrm{2nd} \\ $$$$\mathrm{day}\:\mathrm{and}\:\mathrm{C}\:\mathrm{works}\:\mathrm{for}\:\mathrm{3rd},\:\mathrm{4th}\:\mathrm{and}\:\mathrm{5th} \\ $$$$\mathrm{day}.\:\mathrm{If}\:\mathrm{B}\:\mathrm{and}\:\mathrm{C}\:\mathrm{can}\:\mathrm{do}\:\mathrm{as}\:\mathrm{much}\:\mathrm{work} \\ $$$$\mathrm{in}\:\mathrm{two}\:\mathrm{days}\:\mathrm{as}\:\mathrm{a}\:\mathrm{alone}\:\mathrm{does}\:\mathrm{in}\:\mathrm{3}\:\mathrm{days}. \\ $$$$\mathrm{If}\:\mathrm{B}\:\mathrm{and}\:\mathrm{C}\:\mathrm{can}\:\mathrm{complete}\:\mathrm{the}\:\mathrm{work}\: \\ $$$$\mathrm{without}\:\mathrm{tbe}\:\mathrm{help}\:\mathrm{of}\:\mathrm{A}\:\mathrm{in}\:\mathrm{6}\:\mathrm{days}\:\mathrm{then}\: \\ $$$$\mathrm{how}\:\mathrm{many}\:\mathrm{dahs}\:\mathrm{A}\:\mathrm{alone}\:\mathrm{do}\:\mathrm{the}\:\mathrm{work}? \\ $$

Question Number 25572 Answers: 1 Comments: 0

Solve the differential equation: y′ = cosh(x+y)

$${Solve}\:{the}\:{differential}\:{equation}: \\ $$$${y}'\:=\:{cosh}\left({x}+{y}\right) \\ $$

Question Number 25569 Answers: 0 Comments: 8

if y =(sin^(−1) x)^2 ,check whether (1−x^2 )y_(n+2) −(2n+1)xy_(n+1) +n^2 y_n =0 or not.

$${if}\:{y}\:=\left({sin}^{−\mathrm{1}} {x}\right)^{\mathrm{2}} ,{check}\:{whether} \\ $$$$\left(\mathrm{1}−{x}^{\mathrm{2}} \right){y}_{{n}+\mathrm{2}} −\left(\mathrm{2}{n}+\mathrm{1}\right){xy}_{{n}+\mathrm{1}} +{n}^{\mathrm{2}} {y}_{{n}} =\mathrm{0} \\ $$$${or}\:{not}. \\ $$

Question Number 25567 Answers: 2 Comments: 1

if y( sinx)^((sinx)^((sinx).^.^.^(.∞) ) ) find dy/dx.

$${if}\:{y}\left(\:{sinx}\right)^{\left({sinx}\right)^{\left({sinx}\right).^{.^{.^{.\infty} } } } } \\ $$$${find}\:{dy}/{dx}. \\ $$

Question Number 25559 Answers: 0 Comments: 2

(1) In a single throw of three dice,find the probability of getting a total of (i) 4 (ii) at most 4 (iii) atleast 4

$$\left(\mathrm{1}\right)\:\mathrm{In}\:\mathrm{a}\:\mathrm{single}\:\mathrm{throw}\:\mathrm{of}\:\mathrm{three}\: \\ $$$$\mathrm{dice},\mathrm{find}\:\mathrm{the}\:\mathrm{probability}\:\mathrm{of}\:\mathrm{getting} \\ $$$$\mathrm{a}\:\mathrm{total}\:\mathrm{of} \\ $$$$\left(\mathrm{i}\right)\:\mathrm{4} \\ $$$$\left(\mathrm{ii}\right)\:\mathrm{at}\:\mathrm{most}\:\mathrm{4} \\ $$$$\left(\mathrm{iii}\right)\:\mathrm{atleast}\:\mathrm{4} \\ $$

Question Number 25549 Answers: 1 Comments: 0

The mean weights of three groups of students consisting of 16, 18 and 20 students are 40.5kg, 42.50kg and 45.00kg respectively. What is the mean weight of all the students?

$$\mathrm{The}\:\mathrm{mean}\:\mathrm{weights}\:\mathrm{of}\:\mathrm{three}\:\mathrm{groups}\:\mathrm{of}\:\mathrm{students} \\ $$$$\mathrm{consisting}\:\mathrm{of}\:\mathrm{16},\:\mathrm{18}\:\mathrm{and}\:\mathrm{20}\:\mathrm{students}\:\mathrm{are}\:\mathrm{40}.\mathrm{5kg},\:\mathrm{42}.\mathrm{50kg} \\ $$$$\mathrm{and}\:\mathrm{45}.\mathrm{00kg}\:\mathrm{respectively}.\:\mathrm{What}\:\mathrm{is}\:\mathrm{the}\:\mathrm{mean}\:\mathrm{weight} \\ $$$$\mathrm{of}\:\mathrm{all}\:\mathrm{the}\:\mathrm{students}? \\ $$

Question Number 25543 Answers: 2 Comments: 4

Question Number 25536 Answers: 1 Comments: 0

If x = 2sec(3t) and y = 4tan(3t), Show that y = 4(x^2 − 4)

$$\mathrm{If}\:\:\:\mathrm{x}\:=\:\mathrm{2sec}\left(\mathrm{3t}\right)\:\:\mathrm{and}\:\:\mathrm{y}\:=\:\mathrm{4tan}\left(\mathrm{3t}\right),\:\:\:\mathrm{Show}\:\mathrm{that}\:\:\:\:\mathrm{y}\:=\:\mathrm{4}\left(\mathrm{x}^{\mathrm{2}} \:−\:\mathrm{4}\right) \\ $$

Question Number 25533 Answers: 1 Comments: 0

Three sets of beans l, m, and n are sold for5 for $5.00, $15.00 and $17.50 respectively per kg. If they are mixed in the ratio of 1:3:2, what is the cost per kg of the mixture?×

$${Three}\:{sets}\:{of}\:{beans}\:{l},\:{m},\:{and}\:{n}\:{are}\:{sold}\:{for}\mathrm{5} \\ $$$${for}\:\$\mathrm{5}.\mathrm{00},\:\$\mathrm{15}.\mathrm{00}\:{and}\:\$\mathrm{17}.\mathrm{50}\:{respectively} \\ $$$${per}\:{kg}.\:{If}\:{they}\:{are}\:{mixed}\:{in}\:{the}\:{ratio}\:{of} \\ $$$$\mathrm{1}:\mathrm{3}:\mathrm{2},\:{what}\:{is}\:{the}\:{cost}\:{per}\:{kg}\:{of}\:{the}\:{mixture}?× \\ $$

Question Number 25716 Answers: 0 Comments: 0