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AllQuestion and Answers: Page 183

Question Number 200859    Answers: 0   Comments: 1

(x)^(1/0) =?

$$\sqrt[{\mathrm{0}}]{{x}}=? \\ $$

Question Number 200930    Answers: 0   Comments: 1

If I_n =∫_0 ^1 (1−x^4 )^n dx and (I_n /I_(n−1) )=((λn)/(λn+1)) then find λ

$${If}\:{I}_{{n}} =\int_{\mathrm{0}} ^{\mathrm{1}} \left(\mathrm{1}−{x}^{\mathrm{4}} \right)^{{n}} {dx}\:\:{and}\:\:\frac{{I}_{{n}} }{{I}_{{n}−\mathrm{1}} }=\frac{\lambda{n}}{\lambda{n}+\mathrm{1}} \\ $$$${then}\:{find}\:\:\lambda \\ $$

Question Number 200856    Answers: 0   Comments: 1

Question Number 200844    Answers: 2   Comments: 2

Question Number 200840    Answers: 2   Comments: 0

lim_(x→a) ((x^n sin a−a^n sin x)/(x−a))

$$\underset{{x}\rightarrow{a}} {\mathrm{lim}}\frac{{x}^{{n}} \mathrm{sin}\:{a}−{a}^{{n}} \mathrm{sin}\:{x}}{{x}−{a}} \\ $$

Question Number 200836    Answers: 1   Comments: 4

Let abc ^(−) + bca ^(−) + cab ^(−) = defg ^(−) where a,b,...,g are decimal digits (may be equal to 0) Show that (i) dg ^(−) =a+b+c (ii) e=f=d+g

$$ \\ $$$$\mathcal{L}{et}\overline {\:{abc}\:}+\overline {\:{bca}\:}+\overline {\:{cab}\:}=\overline {\:{defg}\:} \\ $$$${where}\:{a},{b},...,{g}\:{are}\:{decimal}\:{digits} \\ $$$$\left({may}\:{be}\:{equal}\:{to}\:\mathrm{0}\right)\: \\ $$$${Show}\:{that} \\ $$$$\left({i}\right)\overline {\:{dg}\:}={a}+{b}+{c} \\ $$$$\left({ii}\right)\:{e}={f}={d}+{g} \\ $$

Question Number 200834    Answers: 1   Comments: 0

Show that abc ^(−) + bca ^(−) + cab ^(−) is divisible by 37

$${Show}\:{that}\:\:\:\overline {\:\:{abc}\:}+\overline {\:{bca}\:}+\overline {\:{cab}\:} \\ $$$${is}\:{divisible}\:{by}\:\mathrm{37} \\ $$

Question Number 200833    Answers: 0   Comments: 4

Advance question A phone mistakenly got locked with the pattern of 3 × 3 form, in how many attempts person can try before he can eventually get it right ? Thank you

$$\mathrm{Advance}\:\mathrm{question} \\ $$$$ \\ $$$$\mathrm{A}\:\mathrm{phone}\:\mathrm{mistakenly}\:\mathrm{got}\:\mathrm{locked}\:\mathrm{with}\:\mathrm{the}\: \\ $$$$\mathrm{pattern}\:\mathrm{of}\:\:\mathrm{3}\:×\:\mathrm{3}\:\mathrm{form},\:\mathrm{in}\:\mathrm{how}\:\mathrm{many}\:\mathrm{attempts} \\ $$$$\mathrm{person}\:\mathrm{can}\:\mathrm{try}\:\mathrm{before}\:\mathrm{he}\:\mathrm{can}\:\mathrm{eventually}\:\mathrm{get} \\ $$$$\mathrm{it}\:\mathrm{right}\:? \\ $$$$ \\ $$$$\mathrm{Thank}\:\mathrm{you} \\ $$

Question Number 200831    Answers: 0   Comments: 1

Question Number 200823    Answers: 1   Comments: 0

cos20∙cos40+cos^2 80=?

$${cos}\mathrm{20}\centerdot{cos}\mathrm{40}+{cos}^{\mathrm{2}} \mathrm{80}=? \\ $$

Question Number 200821    Answers: 1   Comments: 0

Question Number 200816    Answers: 2   Comments: 3

Question Number 200802    Answers: 1   Comments: 0

Question Number 200801    Answers: 1   Comments: 0

Question Number 200797    Answers: 0   Comments: 0

Question Number 200795    Answers: 1   Comments: 0

lim_(x→sin1) ((1−x^2 )/(1+cosx))=?

$$\underset{{x}\rightarrow{sin}\mathrm{1}} {\mathrm{lim}}\:\frac{\mathrm{1}−{x}^{\mathrm{2}} }{\mathrm{1}+{cosx}}=? \\ $$

Question Number 200792    Answers: 1   Comments: 4

Question Number 200788    Answers: 1   Comments: 0

sinx + cosx = tgx x = ?

$$\mathrm{sin}\boldsymbol{\mathrm{x}}\:\:\:+\:\:\:\mathrm{cos}\boldsymbol{\mathrm{x}}\:\:\:=\:\:\:\mathrm{tg}\boldsymbol{\mathrm{x}} \\ $$$$\mathrm{x}\:=\:? \\ $$

Question Number 200787    Answers: 0   Comments: 0

Question Number 200786    Answers: 0   Comments: 0

Question Number 200785    Answers: 1   Comments: 0

Question Number 200778    Answers: 1   Comments: 0

Question Number 200773    Answers: 2   Comments: 0

Question Number 200768    Answers: 2   Comments: 0

Question Number 200761    Answers: 1   Comments: 5

Determiner r et R (voir figure ) Sachant aue:∡C=120 :AB=12

$$\boldsymbol{\mathrm{Determiner}}\:\:\boldsymbol{\mathrm{r}}\:\:\mathrm{et}\:\:\boldsymbol{\mathrm{R}}\:\:\left({voir}\:{figure}\:\right) \\ $$$$\:\mathrm{Sachant}\:\mathrm{aue}:\measuredangle\boldsymbol{\mathrm{C}}=\mathrm{120}\:\::\boldsymbol{{AB}}=\mathrm{12} \\ $$

Question Number 200748    Answers: 2   Comments: 0

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