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Question Number 22881    Answers: 0   Comments: 3

which is your favourite subject?

$${which}\:{is}\:{your}\:{favourite}\:{subject}? \\ $$

Question Number 22879    Answers: 1   Comments: 0

The Enthalpy of neutralization of acetic acid and sodium hydroxide is −55.4 kJ. What is the enthalpy of ionisation of acetic acid?

$$\mathrm{The}\:\mathrm{Enthalpy}\:\mathrm{of}\:\mathrm{neutralization}\:\mathrm{of} \\ $$$$\mathrm{acetic}\:\mathrm{acid}\:\mathrm{and}\:\mathrm{sodium}\:\mathrm{hydroxide}\:\mathrm{is} \\ $$$$−\mathrm{55}.\mathrm{4}\:\mathrm{kJ}.\:\mathrm{What}\:\mathrm{is}\:\mathrm{the}\:\mathrm{enthalpy}\:\mathrm{of} \\ $$$$\mathrm{ionisation}\:\mathrm{of}\:\mathrm{acetic}\:\mathrm{acid}? \\ $$

Question Number 22872    Answers: 1   Comments: 4

Question Number 22856    Answers: 0   Comments: 1

solve: sin(x)=2, x∈C

$$\mathrm{solve}:\:\mathrm{sin}\left({x}\right)=\mathrm{2},\:\:\:{x}\in\mathbb{C} \\ $$

Question Number 22855    Answers: 1   Comments: 1

Equal forces act on two bodies which are initially at rest,for equal times.If the ratio of the masses is 4:3,What is the ratio of the distance covered?

$${Equal}\:{forces}\:{act}\:{on}\:{two}\:{bodies} \\ $$$${which}\:{are}\:{initially}\:{at}\:{rest},{for} \\ $$$${equal}\:{times}.{If}\:{the}\:{ratio}\:{of}\:{the}\: \\ $$$${masses}\:{is}\:\mathrm{4}:\mathrm{3},{What}\:{is}\:{the}\:{ratio} \\ $$$${of}\:{the}\:{distance}\:{covered}? \\ $$

Question Number 22884    Answers: 1   Comments: 0

A body of mass 0.3 kg is taken up an inclined plane of length 10 m and height 5 m, and then allowed to slide down to the bottom again. The coefficient of friction between the body and the plane is 0.15. What is the kinetic energy of the body at the end of the trip?

$$\mathrm{A}\:\mathrm{body}\:\mathrm{of}\:\mathrm{mass}\:\mathrm{0}.\mathrm{3}\:\mathrm{kg}\:\mathrm{is}\:\mathrm{taken}\:\mathrm{up}\:\mathrm{an} \\ $$$$\mathrm{inclined}\:\mathrm{plane}\:\mathrm{of}\:\mathrm{length}\:\mathrm{10}\:\mathrm{m}\:\mathrm{and} \\ $$$$\mathrm{height}\:\mathrm{5}\:\mathrm{m},\:\mathrm{and}\:\mathrm{then}\:\mathrm{allowed}\:\mathrm{to}\:\mathrm{slide} \\ $$$$\mathrm{down}\:\mathrm{to}\:\mathrm{the}\:\mathrm{bottom}\:\mathrm{again}.\:\mathrm{The} \\ $$$$\mathrm{coefficient}\:\mathrm{of}\:\mathrm{friction}\:\mathrm{between}\:\mathrm{the}\:\mathrm{body} \\ $$$$\mathrm{and}\:\mathrm{the}\:\mathrm{plane}\:\mathrm{is}\:\mathrm{0}.\mathrm{15}.\:\mathrm{What}\:\mathrm{is}\:\mathrm{the} \\ $$$$\mathrm{kinetic}\:\mathrm{energy}\:\mathrm{of}\:\mathrm{the}\:\mathrm{body}\:\mathrm{at}\:\mathrm{the}\:\mathrm{end}\:\mathrm{of} \\ $$$$\mathrm{the}\:\mathrm{trip}? \\ $$

Question Number 22837    Answers: 0   Comments: 0

The effective nuclear charge of N on its last electron is:−

$$\mathrm{The}\:\mathrm{effective}\:\mathrm{nuclear}\:\mathrm{charge}\:\mathrm{of}\:\mathrm{N}\:\mathrm{on}\:\mathrm{its} \\ $$$$\mathrm{last}\:\mathrm{electron}\:\mathrm{is}:− \\ $$

Question Number 22871    Answers: 1   Comments: 0

If f(n)=(1/n)[(n+1)(n+2)(n+3)...(n+n)]^(1/n) , then lim_(n→∞) f(n) =

$$\mathrm{If}\:\:{f}\left({n}\right)=\frac{\mathrm{1}}{{n}}\left[\left({n}+\mathrm{1}\right)\left({n}+\mathrm{2}\right)\left({n}+\mathrm{3}\right)...\left({n}+{n}\right)\right]^{\mathrm{1}/{n}} , \\ $$$$\mathrm{then}\:\:\:\underset{{n}\rightarrow\infty} {\mathrm{lim}}{f}\left({n}\right)\:= \\ $$

Question Number 22843    Answers: 1   Comments: 0

calculate the value of ∫_0 ^(1000) e^(x−[x]) dx =? where.... [x] is greatest integer functon

$${calculate}\:{the}\:{value}\:{of}\:\:\int_{\mathrm{0}} ^{\mathrm{1000}} {e}^{{x}−\left[{x}\right]} {dx}\:=? \\ $$$${where}....\:\left[{x}\right]\:{is}\:{greatest}\:{integer}\:{functon} \\ $$

Question Number 22820    Answers: 0   Comments: 2

total number of permutations of five abjects → A,A,A,B,B in a circle?

$${total}\:{number}\:{of}\:{permutations}\:{of} \\ $$$${five}\:{abjects}\:\rightarrow\:{A},{A},{A},{B},{B}\: \\ $$$${in}\:{a}\:{circle}? \\ $$

Question Number 22874    Answers: 4   Comments: 0

Question Number 22813    Answers: 1   Comments: 0

The nucleus Fe^(57) emits a γ-ray of energy 14.4 keV. If the mass of the nucleus is 56.935 u, calculate the recoil energy of nucleus.

$$\mathrm{The}\:\mathrm{nucleus}\:\mathrm{Fe}^{\mathrm{57}} \:\mathrm{emits}\:\mathrm{a}\:\gamma-\mathrm{ray}\:\mathrm{of}\:\mathrm{energy} \\ $$$$\mathrm{14}.\mathrm{4}\:\mathrm{keV}.\:\mathrm{If}\:\mathrm{the}\:\mathrm{mass}\:\mathrm{of}\:\mathrm{the}\:\mathrm{nucleus}\:\mathrm{is} \\ $$$$\mathrm{56}.\mathrm{935}\:\mathrm{u},\:\mathrm{calculate}\:\mathrm{the}\:\mathrm{recoil}\:\mathrm{energy}\:\mathrm{of} \\ $$$$\mathrm{nucleus}. \\ $$

Question Number 22797    Answers: 1   Comments: 0

He^+ in ground state is hit by photon thus exciting electron to second excited state. The energy absorbed in this process is (approx) (1) 2.18 × 10^(−14) J (2) 7.75 × 10^(−18) J (3) 4.5 × 10^(−18) J (4) 5 × 10^(−18) J

$$\mathrm{He}^{+} \:\mathrm{in}\:\mathrm{ground}\:\mathrm{state}\:\mathrm{is}\:\mathrm{hit}\:\mathrm{by}\:\mathrm{photon} \\ $$$$\mathrm{thus}\:\mathrm{exciting}\:\mathrm{electron}\:\mathrm{to}\:\mathrm{second}\:\mathrm{excited} \\ $$$$\mathrm{state}.\:\mathrm{The}\:\mathrm{energy}\:\mathrm{absorbed}\:\mathrm{in}\:\mathrm{this} \\ $$$$\mathrm{process}\:\mathrm{is}\:\left(\mathrm{approx}\right) \\ $$$$\left(\mathrm{1}\right)\:\mathrm{2}.\mathrm{18}\:×\:\mathrm{10}^{−\mathrm{14}} \:\mathrm{J} \\ $$$$\left(\mathrm{2}\right)\:\mathrm{7}.\mathrm{75}\:×\:\mathrm{10}^{−\mathrm{18}} \:\mathrm{J} \\ $$$$\left(\mathrm{3}\right)\:\mathrm{4}.\mathrm{5}\:×\:\mathrm{10}^{−\mathrm{18}} \:\mathrm{J} \\ $$$$\left(\mathrm{4}\right)\:\mathrm{5}\:×\:\mathrm{10}^{−\mathrm{18}} \:\mathrm{J} \\ $$

Question Number 22787    Answers: 0   Comments: 2

sin^(−1) (sin 10)=10 or 3π−10 Ans is 3π−10 How

$$\mathrm{sin}^{−\mathrm{1}} \left(\mathrm{sin}\:\mathrm{10}\right)=\mathrm{10}\:\mathrm{or}\:\mathrm{3}\pi−\mathrm{10} \\ $$$$\mathrm{Ans}\:\mathrm{is}\:\mathrm{3}\pi−\mathrm{10}\:\:\:\mathrm{How} \\ $$

Question Number 22782    Answers: 0   Comments: 6

Successive ionisation energies of element is 738, 1450, 10540, 13630 kJ/mole respectively. The element is (1) Na (2) Mg (3) Al (4) K

$$\mathrm{Successive}\:\mathrm{ionisation}\:\mathrm{energies}\:\mathrm{of} \\ $$$$\mathrm{element}\:\mathrm{is}\:\mathrm{738},\:\mathrm{1450},\:\mathrm{10540},\:\mathrm{13630} \\ $$$$\mathrm{kJ}/\mathrm{mole}\:\mathrm{respectively}.\:\mathrm{The}\:\mathrm{element}\:\mathrm{is} \\ $$$$\left(\mathrm{1}\right)\:\mathrm{Na} \\ $$$$\left(\mathrm{2}\right)\:\mathrm{Mg} \\ $$$$\left(\mathrm{3}\right)\:\mathrm{Al} \\ $$$$\left(\mathrm{4}\right)\:\mathrm{K} \\ $$

Question Number 22778    Answers: 0   Comments: 2

Question Number 22769    Answers: 1   Comments: 0

write to geometry form (3/5)+(4/5)i help plz

$$\boldsymbol{\mathrm{write}}\:\boldsymbol{\mathrm{to}}\:\boldsymbol{\mathrm{geometry}}\:\boldsymbol{\mathrm{form}} \\ $$$$\:\frac{\mathrm{3}}{\mathrm{5}}+\frac{\mathrm{4}}{\mathrm{5}}\boldsymbol{\mathrm{i}} \\ $$$$ \\ $$$$\boldsymbol{\mathrm{help}}\:\boldsymbol{\mathrm{plz}}\: \\ $$

Question Number 22768    Answers: 1   Comments: 2

Question Number 22745    Answers: 1   Comments: 0

The number of solutions of the equation log_(101) log_7 ((√(x+7))+(√x))=0 is

$$\mathrm{The}\:\mathrm{number}\:\mathrm{of}\:\mathrm{solutions}\:\mathrm{of}\:\mathrm{the}\: \\ $$$$\mathrm{equation}\:\:\mathrm{log}_{\mathrm{101}} \mathrm{log}_{\mathrm{7}} \left(\sqrt{{x}+\mathrm{7}}+\sqrt{{x}}\right)=\mathrm{0}\:\mathrm{is} \\ $$

Question Number 22744    Answers: 0   Comments: 1

How can i copy and paste from this keyboard to other apps in my mobile? i can copy but can not getting paste in other apps. what to do?

$$\mathrm{How}\:\mathrm{can}\:\mathrm{i}\:\mathrm{copy}\:\mathrm{and}\:\mathrm{paste}\:\mathrm{from}\:\mathrm{this}\: \\ $$$$\mathrm{keyboard}\:\mathrm{to}\:\mathrm{other}\:\mathrm{apps}\:\mathrm{in}\:\mathrm{my}\:\mathrm{mobile}?\:\mathrm{i}\:\mathrm{can}\:\mathrm{copy}\:\mathrm{but}\: \\ $$$$\mathrm{can}\:\mathrm{not}\:\mathrm{getting}\:\mathrm{paste}\:\mathrm{in}\:\mathrm{other}\:\mathrm{apps}.\: \\ $$$$\mathrm{what}\:\mathrm{to}\:\mathrm{do}? \\ $$$$ \\ $$

Question Number 22743    Answers: 1   Comments: 0

The Enthalpy of neutralization of acetic acid and sodium hydroxide is −55.4 kJ. What is the enthalpy of ionisation of acetic acid?

$$\mathrm{The}\:\mathrm{Enthalpy}\:\mathrm{of}\:\mathrm{neutralization}\:\mathrm{of} \\ $$$$\mathrm{acetic}\:\mathrm{acid}\:\mathrm{and}\:\mathrm{sodium}\:\mathrm{hydroxide}\:\mathrm{is} \\ $$$$−\mathrm{55}.\mathrm{4}\:\mathrm{kJ}.\:\mathrm{What}\:\mathrm{is}\:\mathrm{the}\:\mathrm{enthalpy}\:\mathrm{of} \\ $$$$\mathrm{ionisation}\:\mathrm{of}\:\mathrm{acetic}\:\mathrm{acid}? \\ $$

Question Number 22742    Answers: 2   Comments: 0

Question Number 22740    Answers: 0   Comments: 10

Which is the best book for +1 trigonometry?

$$\mathrm{Which}\:\mathrm{is}\:\mathrm{the}\:\mathrm{best}\:\mathrm{book}\:\mathrm{for} \\ $$$$+\mathrm{1}\:\mathrm{trigonometry}? \\ $$

Question Number 22739    Answers: 0   Comments: 0

If (1 + x)^n = C_0 + C_1 x + C_2 x^2 + C_3 x^3 + ... + C_n x^n , Prove that ΣΣ_(0≤i<j≤n) (i + j)C_i C_j = n(2^(2n−1) − (1/2)^(2n) C_n )

$${If}\:\left(\mathrm{1}\:+\:{x}\right)^{{n}} \:=\:{C}_{\mathrm{0}} \:+\:{C}_{\mathrm{1}} {x}\:+\:{C}_{\mathrm{2}} {x}^{\mathrm{2}} \:+\:{C}_{\mathrm{3}} {x}^{\mathrm{3}} \\ $$$$+\:...\:+\:{C}_{{n}} {x}^{{n}} , \\ $$$${Prove}\:{that}\:\underset{\mathrm{0}\leqslant{i}<{j}\leqslant{n}} {\Sigma\Sigma}\left({i}\:+\:{j}\right){C}_{{i}} {C}_{{j}} \:= \\ $$$${n}\left(\mathrm{2}^{\mathrm{2}{n}−\mathrm{1}} \:−\:\frac{\mathrm{1}}{\mathrm{2}}\:^{\mathrm{2}{n}} {C}_{{n}} \right) \\ $$

Question Number 22714    Answers: 1   Comments: 0

Question Number 22703    Answers: 1   Comments: 1

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