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Question Number 22937    Answers: 0   Comments: 0

Question Number 22930    Answers: 1   Comments: 0

Question Number 22929    Answers: 1   Comments: 0

Question Number 22928    Answers: 1   Comments: 0

Question Number 22956    Answers: 1   Comments: 4

Question Number 22923    Answers: 1   Comments: 0

Question Number 22922    Answers: 0   Comments: 0

Question Number 22896    Answers: 0   Comments: 1

how can demonstred 17^(4n+1) +3×9^(2n+1) ≡0[11]

$${how}\:{can}\:{demonstred} \\ $$$$\mathrm{17}^{\mathrm{4}{n}+\mathrm{1}} +\mathrm{3}×\mathrm{9}^{\mathrm{2}{n}+\mathrm{1}} \equiv\mathrm{0}\left[\mathrm{11}\right] \\ $$

Question Number 22941    Answers: 1   Comments: 3

Question Number 22893    Answers: 1   Comments: 0

A wedge has two equally rough faces each inclined at 30° to the horizontal.Masses of 5kg and 2kg ,one on each face,are connected by a light string passing over a smooth pulley at the top of the wedge.The coefficient of friction μ, between each masses and the surface of the wedge is 0.2.Find the acceleration of the masses when they are released.

$${A}\:{wedge}\:{has}\:{two}\:{equally}\:{rough} \\ $$$${faces}\:{each}\:{inclined}\:{at}\:\mathrm{30}°\:{to}\:{the} \\ $$$${horizontal}.{Masses}\:{of}\:\mathrm{5}{kg}\:{and}\:\mathrm{2}{kg} \\ $$$$,{one}\:{on}\:{each}\:{face},{are}\:{connected} \\ $$$${by}\:{a}\:{light}\:{string}\:{passing}\:{over}\:{a} \\ $$$${smooth}\:{pulley}\:{at}\:{the}\:{top}\:{of}\:{the} \\ $$$${wedge}.{The}\:{coefficient}\:{of}\:{friction}\: \\ $$$$\mu,\:{between}\:{each}\:{masses}\:{and}\:{the} \\ $$$${surface}\:{of}\:{the}\:{wedge}\:{is}\:\mathrm{0}.\mathrm{2}.{Find} \\ $$$${the}\:{acceleration}\:{of}\:{the}\:{masses} \\ $$$${when}\:{they}\:{are}\:{released}. \\ $$

Question Number 22892    Answers: 0   Comments: 3

A horizontal force of 10N just prevents a mass of 2kg from sliding down a rough plane inclined at 45° to the horizontal. Find the coefficient of friction.

$${A}\:{horizontal}\:{force}\:{of}\:\mathrm{10}{N}\:{just} \\ $$$${prevents}\:{a}\:{mass}\:{of}\:\mathrm{2}{kg}\:{from} \\ $$$${sliding}\:{down}\:{a}\:{rough}\:{plane} \\ $$$${inclined}\:{at}\:\mathrm{45}°\:{to}\:{the}\:{horizontal}. \\ $$$${Find}\:{the}\:{coefficient}\:{of}\:{friction}. \\ $$

Question Number 22883    Answers: 1   Comments: 1

The correct order of second ionisation energy in the following : (a) F > O > N > C (b) O > F > N > C (c) O > N > F > C (d) C > N > O > F

$$\mathrm{The}\:\mathrm{correct}\:\mathrm{order}\:\mathrm{of}\:\mathrm{second}\:\mathrm{ionisation} \\ $$$$\mathrm{energy}\:\mathrm{in}\:\mathrm{the}\:\mathrm{following}\:: \\ $$$$\left({a}\right)\:\mathrm{F}\:>\:\mathrm{O}\:>\:\mathrm{N}\:>\:\mathrm{C} \\ $$$$\left({b}\right)\:\mathrm{O}\:>\:\mathrm{F}\:>\:\mathrm{N}\:>\:\mathrm{C} \\ $$$$\left({c}\right)\:\mathrm{O}\:>\:\mathrm{N}\:>\:\mathrm{F}\:>\:\mathrm{C} \\ $$$$\left({d}\right)\:\mathrm{C}\:>\:\mathrm{N}\:>\:\mathrm{O}\:>\:\mathrm{F} \\ $$

Question Number 22881    Answers: 0   Comments: 3

which is your favourite subject?

$${which}\:{is}\:{your}\:{favourite}\:{subject}? \\ $$

Question Number 22879    Answers: 1   Comments: 0

The Enthalpy of neutralization of acetic acid and sodium hydroxide is −55.4 kJ. What is the enthalpy of ionisation of acetic acid?

$$\mathrm{The}\:\mathrm{Enthalpy}\:\mathrm{of}\:\mathrm{neutralization}\:\mathrm{of} \\ $$$$\mathrm{acetic}\:\mathrm{acid}\:\mathrm{and}\:\mathrm{sodium}\:\mathrm{hydroxide}\:\mathrm{is} \\ $$$$−\mathrm{55}.\mathrm{4}\:\mathrm{kJ}.\:\mathrm{What}\:\mathrm{is}\:\mathrm{the}\:\mathrm{enthalpy}\:\mathrm{of} \\ $$$$\mathrm{ionisation}\:\mathrm{of}\:\mathrm{acetic}\:\mathrm{acid}? \\ $$

Question Number 22872    Answers: 1   Comments: 4

Question Number 22856    Answers: 0   Comments: 1

solve: sin(x)=2, x∈C

$$\mathrm{solve}:\:\mathrm{sin}\left({x}\right)=\mathrm{2},\:\:\:{x}\in\mathbb{C} \\ $$

Question Number 22855    Answers: 1   Comments: 1

Equal forces act on two bodies which are initially at rest,for equal times.If the ratio of the masses is 4:3,What is the ratio of the distance covered?

$${Equal}\:{forces}\:{act}\:{on}\:{two}\:{bodies} \\ $$$${which}\:{are}\:{initially}\:{at}\:{rest},{for} \\ $$$${equal}\:{times}.{If}\:{the}\:{ratio}\:{of}\:{the}\: \\ $$$${masses}\:{is}\:\mathrm{4}:\mathrm{3},{What}\:{is}\:{the}\:{ratio} \\ $$$${of}\:{the}\:{distance}\:{covered}? \\ $$

Question Number 22884    Answers: 1   Comments: 0

A body of mass 0.3 kg is taken up an inclined plane of length 10 m and height 5 m, and then allowed to slide down to the bottom again. The coefficient of friction between the body and the plane is 0.15. What is the kinetic energy of the body at the end of the trip?

$$\mathrm{A}\:\mathrm{body}\:\mathrm{of}\:\mathrm{mass}\:\mathrm{0}.\mathrm{3}\:\mathrm{kg}\:\mathrm{is}\:\mathrm{taken}\:\mathrm{up}\:\mathrm{an} \\ $$$$\mathrm{inclined}\:\mathrm{plane}\:\mathrm{of}\:\mathrm{length}\:\mathrm{10}\:\mathrm{m}\:\mathrm{and} \\ $$$$\mathrm{height}\:\mathrm{5}\:\mathrm{m},\:\mathrm{and}\:\mathrm{then}\:\mathrm{allowed}\:\mathrm{to}\:\mathrm{slide} \\ $$$$\mathrm{down}\:\mathrm{to}\:\mathrm{the}\:\mathrm{bottom}\:\mathrm{again}.\:\mathrm{The} \\ $$$$\mathrm{coefficient}\:\mathrm{of}\:\mathrm{friction}\:\mathrm{between}\:\mathrm{the}\:\mathrm{body} \\ $$$$\mathrm{and}\:\mathrm{the}\:\mathrm{plane}\:\mathrm{is}\:\mathrm{0}.\mathrm{15}.\:\mathrm{What}\:\mathrm{is}\:\mathrm{the} \\ $$$$\mathrm{kinetic}\:\mathrm{energy}\:\mathrm{of}\:\mathrm{the}\:\mathrm{body}\:\mathrm{at}\:\mathrm{the}\:\mathrm{end}\:\mathrm{of} \\ $$$$\mathrm{the}\:\mathrm{trip}? \\ $$

Question Number 22837    Answers: 0   Comments: 0

The effective nuclear charge of N on its last electron is:−

$$\mathrm{The}\:\mathrm{effective}\:\mathrm{nuclear}\:\mathrm{charge}\:\mathrm{of}\:\mathrm{N}\:\mathrm{on}\:\mathrm{its} \\ $$$$\mathrm{last}\:\mathrm{electron}\:\mathrm{is}:− \\ $$

Question Number 22871    Answers: 1   Comments: 0

If f(n)=(1/n)[(n+1)(n+2)(n+3)...(n+n)]^(1/n) , then lim_(n→∞) f(n) =

$$\mathrm{If}\:\:{f}\left({n}\right)=\frac{\mathrm{1}}{{n}}\left[\left({n}+\mathrm{1}\right)\left({n}+\mathrm{2}\right)\left({n}+\mathrm{3}\right)...\left({n}+{n}\right)\right]^{\mathrm{1}/{n}} , \\ $$$$\mathrm{then}\:\:\:\underset{{n}\rightarrow\infty} {\mathrm{lim}}{f}\left({n}\right)\:= \\ $$

Question Number 22843    Answers: 1   Comments: 0

calculate the value of ∫_0 ^(1000) e^(x−[x]) dx =? where.... [x] is greatest integer functon

$${calculate}\:{the}\:{value}\:{of}\:\:\int_{\mathrm{0}} ^{\mathrm{1000}} {e}^{{x}−\left[{x}\right]} {dx}\:=? \\ $$$${where}....\:\left[{x}\right]\:{is}\:{greatest}\:{integer}\:{functon} \\ $$

Question Number 22820    Answers: 0   Comments: 2

total number of permutations of five abjects → A,A,A,B,B in a circle?

$${total}\:{number}\:{of}\:{permutations}\:{of} \\ $$$${five}\:{abjects}\:\rightarrow\:{A},{A},{A},{B},{B}\: \\ $$$${in}\:{a}\:{circle}? \\ $$

Question Number 22874    Answers: 4   Comments: 0

Question Number 22813    Answers: 1   Comments: 0

The nucleus Fe^(57) emits a γ-ray of energy 14.4 keV. If the mass of the nucleus is 56.935 u, calculate the recoil energy of nucleus.

$$\mathrm{The}\:\mathrm{nucleus}\:\mathrm{Fe}^{\mathrm{57}} \:\mathrm{emits}\:\mathrm{a}\:\gamma-\mathrm{ray}\:\mathrm{of}\:\mathrm{energy} \\ $$$$\mathrm{14}.\mathrm{4}\:\mathrm{keV}.\:\mathrm{If}\:\mathrm{the}\:\mathrm{mass}\:\mathrm{of}\:\mathrm{the}\:\mathrm{nucleus}\:\mathrm{is} \\ $$$$\mathrm{56}.\mathrm{935}\:\mathrm{u},\:\mathrm{calculate}\:\mathrm{the}\:\mathrm{recoil}\:\mathrm{energy}\:\mathrm{of} \\ $$$$\mathrm{nucleus}. \\ $$

Question Number 22797    Answers: 1   Comments: 0

He^+ in ground state is hit by photon thus exciting electron to second excited state. The energy absorbed in this process is (approx) (1) 2.18 × 10^(−14) J (2) 7.75 × 10^(−18) J (3) 4.5 × 10^(−18) J (4) 5 × 10^(−18) J

$$\mathrm{He}^{+} \:\mathrm{in}\:\mathrm{ground}\:\mathrm{state}\:\mathrm{is}\:\mathrm{hit}\:\mathrm{by}\:\mathrm{photon} \\ $$$$\mathrm{thus}\:\mathrm{exciting}\:\mathrm{electron}\:\mathrm{to}\:\mathrm{second}\:\mathrm{excited} \\ $$$$\mathrm{state}.\:\mathrm{The}\:\mathrm{energy}\:\mathrm{absorbed}\:\mathrm{in}\:\mathrm{this} \\ $$$$\mathrm{process}\:\mathrm{is}\:\left(\mathrm{approx}\right) \\ $$$$\left(\mathrm{1}\right)\:\mathrm{2}.\mathrm{18}\:×\:\mathrm{10}^{−\mathrm{14}} \:\mathrm{J} \\ $$$$\left(\mathrm{2}\right)\:\mathrm{7}.\mathrm{75}\:×\:\mathrm{10}^{−\mathrm{18}} \:\mathrm{J} \\ $$$$\left(\mathrm{3}\right)\:\mathrm{4}.\mathrm{5}\:×\:\mathrm{10}^{−\mathrm{18}} \:\mathrm{J} \\ $$$$\left(\mathrm{4}\right)\:\mathrm{5}\:×\:\mathrm{10}^{−\mathrm{18}} \:\mathrm{J} \\ $$

Question Number 22787    Answers: 0   Comments: 2

sin^(−1) (sin 10)=10 or 3π−10 Ans is 3π−10 How

$$\mathrm{sin}^{−\mathrm{1}} \left(\mathrm{sin}\:\mathrm{10}\right)=\mathrm{10}\:\mathrm{or}\:\mathrm{3}\pi−\mathrm{10} \\ $$$$\mathrm{Ans}\:\mathrm{is}\:\mathrm{3}\pi−\mathrm{10}\:\:\:\mathrm{How} \\ $$

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