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AllQuestion and Answers: Page 1778

Question Number 30990 Answers: 1 Comments: 0

Question Number 30984 Answers: 0 Comments: 3

Question Number 30986 Answers: 1 Comments: 0

Question Number 30961 Answers: 0 Comments: 13

Question Number 30958 Answers: 1 Comments: 4

Question Number 30957 Answers: 1 Comments: 0

Question Number 30956 Answers: 1 Comments: 0

Question Number 30939 Answers: 1 Comments: 0

If x^2 +y^2 +z^2 = r^2 , then tan^(−1) (((xy)/(zr)))+tan^(−1) (((yz)/(xr)))+tan^(−1) (((xz)/(yr))) =

$$\mathrm{If}\:\:{x}^{\mathrm{2}} +{y}^{\mathrm{2}} +{z}^{\mathrm{2}} =\:{r}^{\mathrm{2}} \:,\:\mathrm{then} \\ $$$$\mathrm{tan}^{−\mathrm{1}} \left(\frac{{xy}}{{zr}}\right)+\mathrm{tan}^{−\mathrm{1}} \left(\frac{{yz}}{{xr}}\right)+\mathrm{tan}^{−\mathrm{1}} \left(\frac{{xz}}{{yr}}\right)\:= \\ $$

Question Number 30936 Answers: 0 Comments: 0

find ∫^a _0 ((sinx)/(√(1+x^2 )))dx .

$${find}\:\:\:\underset{\mathrm{0}} {\int}^{{a}} \:\:\frac{{sinx}}{\sqrt{\mathrm{1}+{x}^{\mathrm{2}} }}{dx}\:. \\ $$

Question Number 30933 Answers: 1 Comments: 0

Question Number 30929 Answers: 2 Comments: 1

Σ_(n=0) ^∞ tan^(−1) (n+(1/2))−tan^(−1) (n−(1/2))= ?

$$\underset{{n}=\mathrm{0}} {\overset{\infty} {\sum}}\:\mathrm{tan}^{−\mathrm{1}} \left({n}+\frac{\mathrm{1}}{\mathrm{2}}\right)−\mathrm{tan}^{−\mathrm{1}} \left({n}−\frac{\mathrm{1}}{\mathrm{2}}\right)=\:? \\ $$

Question Number 30918 Answers: 1 Comments: 0

Question Number 30917 Answers: 0 Comments: 0

Question Number 30916 Answers: 1 Comments: 1

Question Number 30913 Answers: 0 Comments: 0

Question Number 30897 Answers: 1 Comments: 1

(44x+28y)2

$$\left(\mathrm{44}{x}+\mathrm{28}{y}\right)\mathrm{2} \\ $$

Question Number 30875 Answers: 1 Comments: 1

Question Number 30871 Answers: 1 Comments: 2

If 2f(x)+f(−x)=(1/x)sin (x−(1/x)) Find ∫_(1/e) ^( e) f(x)dx .

$${If}\:\:\:\mathrm{2}{f}\left({x}\right)+{f}\left(−{x}\right)=\frac{\mathrm{1}}{{x}}\mathrm{sin}\:\left({x}−\frac{\mathrm{1}}{{x}}\right) \\ $$$${Find}\:\:\:\int_{\mathrm{1}/{e}} ^{\:\:{e}} {f}\left({x}\right){dx}\:\:. \\ $$

Question Number 30866 Answers: 0 Comments: 8

Question Number 30858 Answers: 2 Comments: 0

∫_0 ^1 x∣x−4∣dx

$$\int_{\mathrm{0}} ^{\mathrm{1}} \mathrm{x}\mid\mathrm{x}−\mathrm{4}\mid\mathrm{dx} \\ $$

Question Number 30862 Answers: 1 Comments: 0

Question Number 30861 Answers: 1 Comments: 0

A wave of frequency 10hz forms a stationery wave pattern in a medium where the velocity is 20cms^(−1) what is the distance between the adjacent nodes? pls help..

$$\mathrm{A}\:\mathrm{wave}\:\mathrm{of}\:\mathrm{frequency}\:\mathrm{10hz}\:\mathrm{forms} \\ $$$$\mathrm{a}\:\mathrm{stationery}\:\mathrm{wave}\:\mathrm{pattern}\:\mathrm{in}\:\mathrm{a}\:\mathrm{medium} \\ $$$$\mathrm{where}\:\mathrm{the}\:\mathrm{velocity}\:\mathrm{is}\:\mathrm{20cms}^{−\mathrm{1}} \\ $$$$\mathrm{what}\:\mathrm{is}\:\mathrm{the}\:\mathrm{distance}\:\mathrm{between}\:\mathrm{the}\:\mathrm{adjacent}\:\mathrm{nodes}? \\ $$$$ \\ $$$$\mathrm{pls}\:\mathrm{help}.. \\ $$

Question Number 30860 Answers: 1 Comments: 0

S= 3(1!)−4(2!)+5(3!)−6(4!)+.... .....−(2008)(2006!)+2007! Find value of S.

$${S}=\:\mathrm{3}\left(\mathrm{1}!\right)−\mathrm{4}\left(\mathrm{2}!\right)+\mathrm{5}\left(\mathrm{3}!\right)−\mathrm{6}\left(\mathrm{4}!\right)+.... \\ $$$$\:\:\:\:.....−\left(\mathrm{2008}\right)\left(\mathrm{2006}!\right)+\mathrm{2007}! \\ $$$${Find}\:{value}\:{of}\:{S}. \\ $$

Question Number 30856 Answers: 1 Comments: 1

Question Number 30855 Answers: 1 Comments: 0

∫((cosec^2 (x))/(√(cosecx+cotx)))dx

$$\int\frac{\mathrm{cosec}^{\mathrm{2}} \left(\mathrm{x}\right)}{\sqrt{\mathrm{cosecx}+\mathrm{cotx}}}\mathrm{dx} \\ $$

Question Number 30849 Answers: 0 Comments: 5

x^7 +x^6 +x^5 +x^4 +x^3 +x^2 +x+1=0 Σ_(k=1) ^7 [ℜ(x_k )]^2 = ? x_k = k^( th) root of the equation ℜ(x_k ) = real part of the root

$${x}^{\mathrm{7}} +{x}^{\mathrm{6}} +{x}^{\mathrm{5}} +{x}^{\mathrm{4}} +{x}^{\mathrm{3}} +{x}^{\mathrm{2}} +{x}+\mathrm{1}=\mathrm{0} \\ $$$$\: \\ $$$$\underset{{k}=\mathrm{1}} {\overset{\mathrm{7}} {\sum}}\left[\Re\left({x}_{{k}} \right)\right]^{\mathrm{2}} \:=\:? \\ $$$${x}_{{k}} \:=\:{k}^{\:\mathrm{th}} \:\mathrm{root}\:\mathrm{of}\:\mathrm{the}\:\mathrm{equation} \\ $$$$\Re\left({x}_{{k}} \right)\:=\:\mathrm{real}\:\mathrm{part}\:\mathrm{of}\:\mathrm{the}\:\mathrm{root} \\ $$

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