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AllQuestion and Answers: Page 1778

Question Number 29347    Answers: 0   Comments: 0

y^((1)) +((2/(xln x))+(((1−4x^2 ln x))/(x(1−2xln x))))y=0

$${y}^{\left(\mathrm{1}\right)} +\left(\frac{\mathrm{2}}{{x}\mathrm{ln}\:{x}}+\frac{\left(\mathrm{1}−\mathrm{4}{x}^{\mathrm{2}} \mathrm{ln}\:{x}\right)}{{x}\left(\mathrm{1}−\mathrm{2}{x}\mathrm{ln}\:{x}\right)}\right){y}=\mathrm{0} \\ $$

Question Number 29345    Answers: 1   Comments: 0

solve simultanrodly x+y=5.....(1) x^y +y^x =17.....(2)

$$\mathrm{solve}\:\mathrm{simultanrodly} \\ $$$$ \\ $$$$\mathrm{x}+\mathrm{y}=\mathrm{5}.....\left(\mathrm{1}\right) \\ $$$$\mathrm{x}^{\mathrm{y}} +\mathrm{y}^{\mathrm{x}} =\mathrm{17}.....\left(\mathrm{2}\right) \\ $$

Question Number 29423    Answers: 0   Comments: 1

Question Number 29332    Answers: 1   Comments: 0

Question Number 29326    Answers: 1   Comments: 0

The unit digit of the square of a number and the units digit of the cube of the number are equal to the unit digit of the number. How many values are possible for the units digits of such numbers?

$$\mathrm{The}\:\mathrm{unit}\:\mathrm{digit}\:\mathrm{of}\:\mathrm{the}\:\mathrm{square}\:\mathrm{of}\:\mathrm{a}\:\mathrm{number} \\ $$$$\mathrm{and}\:\mathrm{the}\:\mathrm{units}\:\mathrm{digit}\:\mathrm{of}\:\mathrm{the}\:\mathrm{cube}\:\mathrm{of}\:\mathrm{the}\: \\ $$$$\mathrm{number}\:\mathrm{are}\:\mathrm{equal}\:\mathrm{to}\:\mathrm{the}\:\mathrm{unit}\:\mathrm{digit}\:\mathrm{of} \\ $$$$\mathrm{the}\:\mathrm{number}.\:\mathrm{How}\:\mathrm{many}\:\mathrm{values}\:\mathrm{are}\: \\ $$$$\mathrm{possible}\:\mathrm{for}\:\mathrm{the}\:\mathrm{units}\:\mathrm{digits}\:\mathrm{of}\:\mathrm{such} \\ $$$$\mathrm{numbers}? \\ $$

Question Number 29324    Answers: 1   Comments: 0

Question Number 29322    Answers: 0   Comments: 5

Question Number 29321    Answers: 0   Comments: 1

is it possible to divide an angle into three equal parts?

$$\mathrm{is}\:\mathrm{it}\:\mathrm{possible}\:\mathrm{to}\:\mathrm{divide}\:\mathrm{an}\:\mathrm{angle}\:\mathrm{into}\:\mathrm{three}\:\mathrm{equal}\:\mathrm{parts}? \\ $$

Question Number 29320    Answers: 0   Comments: 1

Find the principal argument of ((−1+2i)/(1−3i)) .

$$\mathrm{Find}\:\mathrm{the}\:\mathrm{principal}\:\mathrm{argument}\:\mathrm{of}\:\frac{−\mathrm{1}+\mathrm{2i}}{\mathrm{1}−\mathrm{3i}}\:. \\ $$

Question Number 29319    Answers: 0   Comments: 0

mxmz]33]2n3xmxksnd

$$\left.{m}\left.{xmz}\right]\mathrm{33}\right]\mathrm{2}{n}\mathrm{3}{xmxksnd} \\ $$

Question Number 29313    Answers: 0   Comments: 0

Question Number 29311    Answers: 0   Comments: 0

∫(2x^3 −3x^2 +3x−1)^(1/5) dx and limit is from 0 to 1

$$\int\left(\mathrm{2}{x}^{\mathrm{3}} −\mathrm{3}{x}^{\mathrm{2}} +\mathrm{3}{x}−\mathrm{1}\right)^{\frac{\mathrm{1}}{\mathrm{5}}} {dx}\:{and}\:{limit}\:{is}\:{from}\:\mathrm{0}\:{to}\:\mathrm{1} \\ $$

Question Number 29310    Answers: 0   Comments: 0

Show that the sequence: {1 + (1/2) + (1/4) + ... + (1/2^n )}_(n = 0) ^∞ is convergent.

$$\mathrm{Show}\:\mathrm{that}\:\mathrm{the}\:\mathrm{sequence}:\:\:\:\:\:\left\{\mathrm{1}\:+\:\frac{\mathrm{1}}{\mathrm{2}}\:+\:\frac{\mathrm{1}}{\mathrm{4}}\:+\:...\:+\:\frac{\mathrm{1}}{\mathrm{2}^{\mathrm{n}} }\right\}_{\mathrm{n}\:\:=\:\mathrm{0}} ^{\infty} \:\:\:\:\:\:\:\:\:\mathrm{is}\:\mathrm{convergent}. \\ $$

Question Number 29314    Answers: 0   Comments: 3

Question Number 29287    Answers: 0   Comments: 0

plz is there any app for medical forum just like this one

$${plz}\:{is}\:{there}\:{any}\:{app}\:{for}\:{medical} \\ $$$${forum}\:{just}\:{like}\:{this}\:{one} \\ $$

Question Number 29286    Answers: 0   Comments: 1

To Developer Tinku Tara: Since the recent updates, it is not more possible to change an existing image via Edit Post”. This was possible in earlier versions of the app. Can you please fix this problem? Thank you!

$${To}\:{Developer}\:{Tinku}\:{Tara}: \\ $$$${Since}\:{the}\:{recent}\:{updates},\:{it}\:{is}\:{not}\:{more} \\ $$$${possible}\:{to}\:{change}\:{an}\:{existing}\:{image}\:{via} \\ $$$${Edit}\:{Post}''.\:{This}\:{was}\:{possible}\:{in}\:{earlier} \\ $$$${versions}\:{of}\:{the}\:{app}.\:{Can}\:{you}\:{please} \\ $$$${fix}\:{this}\:{problem}?\:{Thank}\:{you}! \\ $$

Question Number 29276    Answers: 1   Comments: 0

if the (x/a)+(y/b)=1 passes through the point lf intersection of the lines x+y=3 and 2x−3y=1 and is parallel to the line y=x−6 then find the value of a and b.

$${if}\:{the}\:\frac{{x}}{{a}}+\frac{{y}}{{b}}=\mathrm{1}\:{passes}\:{through}\:{the}\:{point}\:{lf}\:{intersection}\:{of}\:{the}\:{lines}\:{x}+{y}=\mathrm{3}\:{and}\:\mathrm{2}{x}−\mathrm{3}{y}=\mathrm{1}\:{and}\:{is}\:{parallel}\:{to}\:{the}\:{line}\:{y}={x}−\mathrm{6}\:{then}\:{find}\:\:{the}\:{value}\:{of}\:{a}\:\:{and}\:{b}.\: \\ $$

Question Number 29275    Answers: 0   Comments: 0

x(1−2xln x)y^((2)) +(1−4x^2 ln x)y^((1)) −(2+4x)y=0 y_1 =ln x the public answer?

$${x}\left(\mathrm{1}−\mathrm{2}{x}\mathrm{ln}\:{x}\right){y}^{\left(\mathrm{2}\right)} +\left(\mathrm{1}−\mathrm{4}{x}^{\mathrm{2}} \mathrm{ln}\:{x}\right){y}^{\left(\mathrm{1}\right)} −\left(\mathrm{2}+\mathrm{4}{x}\right){y}=\mathrm{0} \\ $$$${y}_{\mathrm{1}} =\mathrm{ln}\:{x} \\ $$$${the}\:{public}\:{answer}? \\ $$

Question Number 29268    Answers: 0   Comments: 2

A man moves 20m North , then 12m East and finally 15m South.His displacement from the starting point is now (a) 13m (b) 27m (c) 47m (d) 23m

$$\mathrm{A}\:\mathrm{man}\:\mathrm{moves}\:\:\mathrm{20m}\:\:\mathrm{North}\:,\:\:\mathrm{then}\:\:\mathrm{12m}\:\mathrm{East}\:\:\mathrm{and}\:\:\mathrm{finally}\:\:\mathrm{15m}\:\:\mathrm{South}.\mathrm{His} \\ $$$$\mathrm{displacement}\:\mathrm{from}\:\mathrm{the}\:\mathrm{starting}\:\mathrm{point}\:\mathrm{is}\:\mathrm{now} \\ $$$$\left(\mathrm{a}\right)\:\mathrm{13m}\:\:\left(\mathrm{b}\right)\:\:\mathrm{27m}\:\:\left(\mathrm{c}\right)\:\:\mathrm{47m}\:\:\left(\mathrm{d}\right)\:\:\mathrm{23m} \\ $$

Question Number 29272    Answers: 0   Comments: 0

(2x−3x^3 )y^((2)) +4y^((1)) +6xy=0 this equation has an answer in the form of several sentences. get the public answer.

$$\left(\mathrm{2}{x}−\mathrm{3}{x}^{\mathrm{3}} \right){y}^{\left(\mathrm{2}\right)} +\mathrm{4}{y}^{\left(\mathrm{1}\right)} +\mathrm{6}{xy}=\mathrm{0} \\ $$$${this}\:{equation}\:{has}\:{an}\:{answer}\:{in}\:{the}\:{form}\:{of}\:{several}\:{sentences}. \\ $$$${get}\:{the}\:{public}\:{answer}. \\ $$

Question Number 29265    Answers: 0   Comments: 0

An electric pump with efficiency of 70% raises water to a height of 15m . If water is delivered at the rate of 350 dm^3 per minute. (i) what is the power rating of the pump ? (mass of 1 dm^3 = 1 kg) (ii) what is the energy lost by the pump ? (g = 10 m/s^2 ) (Answer: 1250W. 22.5 KJ)

$$\mathrm{An}\:\mathrm{electric}\:\mathrm{pump}\:\mathrm{with}\:\mathrm{efficiency}\:\mathrm{of}\:\:\:\mathrm{70\%}\:\:\mathrm{raises}\:\mathrm{water}\:\mathrm{to}\:\mathrm{a}\:\mathrm{height}\:\mathrm{of}\:\:\mathrm{15m} \\ $$$$.\:\mathrm{If}\:\mathrm{water}\:\mathrm{is}\:\mathrm{delivered}\:\mathrm{at}\:\mathrm{the}\:\mathrm{rate}\:\mathrm{of}\:\:\mathrm{350}\:\mathrm{dm}^{\mathrm{3}} \:\mathrm{per}\:\mathrm{minute}.\:\: \\ $$$$\left(\mathrm{i}\right)\:\mathrm{what}\:\mathrm{is}\:\mathrm{the}\:\mathrm{power}\:\mathrm{rating}\:\mathrm{of}\:\mathrm{the}\:\mathrm{pump}\:?\:\:\:\left(\mathrm{mass}\:\mathrm{of}\:\mathrm{1}\:\mathrm{dm}^{\mathrm{3}} \:=\:\mathrm{1}\:\mathrm{kg}\right) \\ $$$$\left(\mathrm{ii}\right)\:\:\mathrm{what}\:\mathrm{is}\:\mathrm{the}\:\mathrm{energy}\:\mathrm{lost}\:\mathrm{by}\:\mathrm{the}\:\mathrm{pump}\:?\:\:\:\left(\mathrm{g}\:=\:\mathrm{10}\:\mathrm{m}/\mathrm{s}^{\mathrm{2}} \right) \\ $$$$\left(\mathrm{Answer}:\:\:\:\mathrm{1250W}.\:\:\:\:\mathrm{22}.\mathrm{5}\:\mathrm{KJ}\right) \\ $$

Question Number 29264    Answers: 1   Comments: 0

there are 25 persons in a conical tent every person needs an area of 4 sq m on the ground under the tent. if height if the tent is 18m.find the volume of the tent.

$$\mathrm{there}\:\mathrm{are}\:\mathrm{25}\:\mathrm{persons}\:\mathrm{in}\:\mathrm{a}\:\mathrm{conical}\:\mathrm{tent} \\ $$$$\mathrm{every}\:\mathrm{person}\:\mathrm{needs}\:\mathrm{an}\:\mathrm{area}\:\mathrm{of}\:\mathrm{4}\:\mathrm{sq}\:\mathrm{m}\: \\ $$$$\mathrm{on}\:\mathrm{the}\:\mathrm{ground}\:\mathrm{under}\:\mathrm{the}\:\mathrm{tent}.\:\mathrm{if} \\ $$$$\mathrm{height}\:\mathrm{if}\:\mathrm{the}\:\mathrm{tent}\:\mathrm{is}\:\mathrm{18m}.\mathrm{find}\:\mathrm{the}\:\mathrm{volume} \\ $$$$\mathrm{of}\:\mathrm{the}\:\mathrm{tent}. \\ $$

Question Number 29273    Answers: 0   Comments: 4

Question Number 29260    Answers: 0   Comments: 0

The eriodic time of a simple pendulum is given by T=2π(√(L/g)). if L=100±0.1cm(s.e) and the time s for 10 ossilations are: 48.2,48.2,48.7,48.5,48.4,48.2,48.4, 48.6,48.5,48.2. calcukate g and the standard error involved.

$${The}\:{eriodic}\:{time}\:{of}\:{a}\:{simple} \\ $$$${pendulum}\:{is}\:{given}\:{by}\:{T}=\mathrm{2}\pi\sqrt{\frac{{L}}{{g}}}. \\ $$$${if}\:{L}=\mathrm{100}\pm\mathrm{0}.\mathrm{1}{cm}\left({s}.{e}\right)\:{and}\:{the} \\ $$$${time}\:{s}\:{for}\:\mathrm{10}\:{ossilations}\:{are}: \\ $$$$\mathrm{48}.\mathrm{2},\mathrm{48}.\mathrm{2},\mathrm{48}.\mathrm{7},\mathrm{48}.\mathrm{5},\mathrm{48}.\mathrm{4},\mathrm{48}.\mathrm{2},\mathrm{48}.\mathrm{4}, \\ $$$$\mathrm{48}.\mathrm{6},\mathrm{48}.\mathrm{5},\mathrm{48}.\mathrm{2}. \\ $$$${calcukate}\:{g}\:{and}\:{the}\:{standard} \\ $$$${error}\:{involved}. \\ $$

Question Number 29259    Answers: 1   Comments: 0

solve the equation 2x+3y=5 3x+4y=4

$${solve}\:{the}\:{equation} \\ $$$$\mathrm{2}{x}+\mathrm{3}{y}=\mathrm{5} \\ $$$$\mathrm{3}{x}+\mathrm{4}{y}=\mathrm{4}\: \\ $$

Question Number 29308    Answers: 2   Comments: 0

Solve: w^3 = − 16

$$\mathrm{Solve}:\:\:\:\mathrm{w}^{\mathrm{3}} \:=\:−\:\mathrm{16} \\ $$

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