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Question Number 203047 Answers: 0 Comments: 0

Question Number 203045 Answers: 0 Comments: 1

very old q Q.2

$${very}\:{old}\:{q}\:{Q}.\mathrm{2} \\ $$

Question Number 203035 Answers: 0 Comments: 3

e=2 Proof: Let x=((e+2)/2) 2x=e+2 2x(e−2)=(e+2)(e−2) 2ex−4x=e^2 −4 −4x+4=−2ex+e^2 x^2 −4x+4=x^2 −2ex+e^2 (x−2)^2 =(x−e)^2 (√((x−2)^2 ))=(√((x−e)^2 )) x−2=x−e −2=−e e=2

$$\mathrm{e}=\mathrm{2} \\ $$$$\mathrm{Proof}: \\ $$$$\mathrm{Let}\:{x}=\frac{\mathrm{e}+\mathrm{2}}{\mathrm{2}} \\ $$$$\mathrm{2}{x}=\mathrm{e}+\mathrm{2} \\ $$$$\mathrm{2}{x}\left(\mathrm{e}−\mathrm{2}\right)=\left(\mathrm{e}+\mathrm{2}\right)\left(\mathrm{e}−\mathrm{2}\right) \\ $$$$\mathrm{2e}{x}−\mathrm{4}{x}=\mathrm{e}^{\mathrm{2}} −\mathrm{4} \\ $$$$−\mathrm{4}{x}+\mathrm{4}=−\mathrm{2e}{x}+\mathrm{e}^{\mathrm{2}} \\ $$$${x}^{\mathrm{2}} −\mathrm{4}{x}+\mathrm{4}={x}^{\mathrm{2}} −\mathrm{2e}{x}+\mathrm{e}^{\mathrm{2}} \\ $$$$\left({x}−\mathrm{2}\right)^{\mathrm{2}} =\left({x}−\mathrm{e}\right)^{\mathrm{2}} \\ $$$$\sqrt{\left({x}−\mathrm{2}\right)^{\mathrm{2}} }=\sqrt{\left({x}−\mathrm{e}\right)^{\mathrm{2}} } \\ $$$${x}−\mathrm{2}={x}−\mathrm{e} \\ $$$$−\mathrm{2}=−\mathrm{e} \\ $$$$\mathrm{e}=\mathrm{2} \\ $$

Question Number 203031 Answers: 1 Comments: 0

Question Number 203018 Answers: 1 Comments: 3

Question Number 203017 Answers: 2 Comments: 0

Question Number 203011 Answers: 0 Comments: 1

∫(u/du)=? Is this question correct?

$$\int\frac{{u}}{{du}}=? \\ $$$${Is}\:{this}\:{question}\:{correct}? \\ $$

Question Number 203009 Answers: 1 Comments: 0

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Question Number 203002 Answers: 3 Comments: 0

Solve for x∈R x^4 +4x−3=0

$${Solve}\:{for}\:{x}\in{R} \\ $$$${x}^{\mathrm{4}} +\mathrm{4}{x}−\mathrm{3}=\mathrm{0} \\ $$

Question Number 202988 Answers: 1 Comments: 1

Question Number 202984 Answers: 2 Comments: 2

If x^x^3 = 3 Find x = ?

$$\mathrm{If}\:\:\:\mathrm{x}^{\boldsymbol{\mathrm{x}}^{\mathrm{3}} } \:=\:\mathrm{3} \\ $$$$\mathrm{Find}\:\:\:\mathrm{x}\:=\:? \\ $$

Question Number 202970 Answers: 0 Comments: 0

Help me 𝛔 𝛔 Find all the Ideals of the quotient Ring Z/18Z of the integer ring Z

$$\mathrm{Help}\:\mathrm{me}\:\boldsymbol{\sigma}\: \:\boldsymbol{\sigma} \\ $$$$\mathrm{Find}\:\mathrm{all}\:\mathrm{the}\:\mathrm{Ideals}\:\mathrm{of}\:\mathrm{the}\:\mathrm{quotient}\:\mathrm{Ring}\: \\ $$$$\mathbb{Z}/\mathrm{18}\mathbb{Z}\:\mathrm{of}\:\mathrm{the}\:\mathrm{integer}\:\mathrm{ring}\:\mathbb{Z}\: \\ $$

Question Number 202976 Answers: 2 Comments: 1

Question Number 202967 Answers: 1 Comments: 0

Question Number 202964 Answers: 0 Comments: 0

just the exact real root please: (x^6 −1)(x^4 +3x^2 −3)+2x(3x^4 −1)=0

$${just}\:{the}\:{exact}\:{real}\:{root}\:{please}: \\ $$$$\left({x}^{\mathrm{6}} −\mathrm{1}\right)\left({x}^{\mathrm{4}} +\mathrm{3}{x}^{\mathrm{2}} −\mathrm{3}\right)+\mathrm{2}{x}\left(\mathrm{3}{x}^{\mathrm{4}} −\mathrm{1}\right)=\mathrm{0} \\ $$

Question Number 202962 Answers: 0 Comments: 5

Please fix the bug. ∐_(k=1) ^(10) sin(90°+k) Hint: Make the bar disappear.

$$\mathrm{Please}\:\mathrm{fix}\:\mathrm{the}\:\mathrm{bug}. \\ $$$$\underset{{k}=\mathrm{1}} {\overset{\mathrm{10}} {\coprod}}\mathrm{sin}\left(\mathrm{90}°+{k}\right) \\ $$$$\mathrm{Hint}:\:\mathrm{Make}\:\mathrm{the}\:\mathrm{bar}\:\mathrm{disappear}. \\ $$

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Question Number 202911 Answers: 2 Comments: 0

Question Number 202938 Answers: 1 Comments: 3

Question Number 202894 Answers: 1 Comments: 5

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Question Number 202882 Answers: 3 Comments: 0

⇃

$$\:\:\:\:\downharpoonleft\underline{\:} \\ $$

Question Number 202876 Answers: 0 Comments: 3

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