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Question Number 37071 Answers: 2 Comments: 1

find the value of ∫_0 ^(π/2) ((xdx)/(1+cosx))

$${find}\:{the}\:{value}\:{of}\:\int_{\mathrm{0}} ^{\frac{\pi}{\mathrm{2}}} \:\:\:\frac{{xdx}}{\mathrm{1}+{cosx}} \\ $$

Question Number 37067 Answers: 2 Comments: 1

find ∫ (dx/((x+1)(√(1+x^2 ))))

$${find}\:\int\:\:\:\:\:\frac{{dx}}{\left({x}+\mathrm{1}\right)\sqrt{\mathrm{1}+{x}^{\mathrm{2}} }} \\ $$

Question Number 37059 Answers: 0 Comments: 0

Question Number 37058 Answers: 1 Comments: 0

Question Number 37048 Answers: 0 Comments: 2

to everybody: if you solved an integral, please test your solution by differentiating. I′m doing the same. thank you so much! MJS

$$\mathrm{to}\:\mathrm{everybody}: \\ $$$$\mathrm{if}\:\mathrm{you}\:\mathrm{solved}\:\mathrm{an}\:\mathrm{integral},\:\mathrm{please}\:\mathrm{test}\:\mathrm{your} \\ $$$$\mathrm{solution}\:\mathrm{by}\:\mathrm{differentiating}.\:\mathrm{I}'\mathrm{m}\:\mathrm{doing}\:\mathrm{the} \\ $$$$\mathrm{same}.\:\mathrm{thank}\:\mathrm{you}\:\mathrm{so}\:\mathrm{much}! \\ $$$${MJS} \\ $$

Question Number 37045 Answers: 1 Comments: 1

Question Number 37037 Answers: 4 Comments: 0

If ((a+b−c)/(a+b)) = ((b+c−a)/(b+c)) =((c+a−b)/(c+a)) and a+b+c ≠ 0 then which of the following is true 1) a=−b=c 2)−a=−b=c 3) a=b=c 4) a=b≠c

$${If}\:\frac{{a}+{b}−{c}}{{a}+{b}}\:=\:\frac{{b}+{c}−{a}}{{b}+{c}}\:=\frac{{c}+{a}−{b}}{{c}+{a}}\:{and}\: \\ $$$$\mathrm{a}+\mathrm{b}+\mathrm{c}\:\neq\:\mathrm{0}\:{then}\:{which}\:{of}\:{the}\:{following} \\ $$$$\left.{i}\left.{s}\:{true}\:\mathrm{1}\right)\:{a}=−{b}={c}\:\mathrm{2}\right)−{a}=−{b}={c}\: \\ $$$$\left.\mathrm{3}\left.\right)\:\mathrm{a}=\mathrm{b}=\mathrm{c}\:\mathrm{4}\right)\:\mathrm{a}=\mathrm{b}\neq{c} \\ $$

Question Number 37036 Answers: 0 Comments: 3

∫_0 ^( a) (1−((b−x)/(√((b−x)^2 +cx)))) dx = ?

$$\int_{\mathrm{0}} ^{\:\:{a}} \left(\mathrm{1}−\frac{{b}−{x}}{\sqrt{\left({b}−{x}\right)^{\mathrm{2}} +{cx}}}\right)\:{dx}\:=\:? \\ $$

Question Number 37032 Answers: 1 Comments: 1

Question Number 37028 Answers: 1 Comments: 0

∫((2x−1)/(5x^2 −x+2)) dx = ?

$$\int\frac{\mathrm{2}{x}−\mathrm{1}}{\mathrm{5}{x}^{\mathrm{2}} −{x}+\mathrm{2}}\:{dx}\:\:=\:\:? \\ $$

Question Number 37026 Answers: 0 Comments: 0

Question Number 37023 Answers: 0 Comments: 0

Question Number 37022 Answers: 0 Comments: 0

Question Number 37021 Answers: 0 Comments: 0

Question Number 37020 Answers: 0 Comments: 0

Question Number 37018 Answers: 3 Comments: 3

Question Number 37010 Answers: 0 Comments: 0

Question Number 37009 Answers: 0 Comments: 0

Question Number 37008 Answers: 0 Comments: 0

Question Number 37005 Answers: 0 Comments: 0

Question Number 37004 Answers: 3 Comments: 0

Question Number 36997 Answers: 2 Comments: 1

∫ (√(((1+x)/x) ))dx = ?

$$\int\:\sqrt{\frac{\mathrm{1}+{x}}{{x}}\:}{dx}\:=\:? \\ $$

Question Number 36990 Answers: 0 Comments: 0

Question Number 36986 Answers: 0 Comments: 0

Question Number 36985 Answers: 0 Comments: 0

Question Number 36978 Answers: 1 Comments: 1

if (a^2 /(b+c)) = (b^2 /(c+a)) = (c^2 /(a+b)) = 1 then find the value of (1/(1+a)) + (1/(1+b)) + (1/(1+c))

$${if}\:\:\frac{{a}^{\mathrm{2}} }{{b}+{c}}\:=\:\frac{{b}^{\mathrm{2}} }{{c}+{a}}\:=\:\frac{{c}^{\mathrm{2}} }{{a}+{b}}\:=\:\mathrm{1}\:{then}\:{find}\:{the}\:{value}\:{of}\: \\ $$$$\frac{\mathrm{1}}{\mathrm{1}+{a}}\:+\:\frac{\mathrm{1}}{\mathrm{1}+{b}}\:+\:\frac{\mathrm{1}}{\mathrm{1}+{c}} \\ $$

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