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AllQuestion and Answers: Page 1701
Question Number 32441 Answers: 1 Comments: 0
Question Number 32440 Answers: 1 Comments: 0
Question Number 32524 Answers: 0 Comments: 0
$$\frac{\mathrm{1}}{\mathrm{2}}{x}^{\mathrm{2}} +\sqrt{\mathrm{2}}= \\ $$
Question Number 32425 Answers: 0 Comments: 0
$$\left(\:\frac{\mathrm{1}}{\mathrm{99}}\:−\:\mathrm{1}\right)^{\mathrm{108}} \:+\:\left(\frac{\mathrm{2}}{\mathrm{99}}\:−\:\mathrm{1}\right)^{\mathrm{107}} \:+\:\left(\frac{\mathrm{3}}{\mathrm{99}}\:−\:\mathrm{1}\right)^{\mathrm{106}} \:+\:...\:+\:\left(\frac{\mathrm{107}}{\mathrm{99}}\:−\:\mathrm{1}\right)^{\mathrm{2}} \:+\:\left(\frac{\mathrm{108}}{\mathrm{99}}\:−\:\mathrm{1}\right)\:\:=\:\:\:.... \\ $$
Question Number 32424 Answers: 1 Comments: 0
Question Number 32423 Answers: 0 Comments: 0
Question Number 32420 Answers: 0 Comments: 0
Question Number 32419 Answers: 0 Comments: 0
$$ \\ $$
Question Number 32418 Answers: 0 Comments: 1
$$\mathrm{The}\:\mathrm{number}\:\mathrm{of}\:\mathrm{real}\:\mathrm{roots}\:\mathrm{or} \\ $$$${x}^{\mathrm{8}} −\:{x}^{\mathrm{5}} −\:{x}\:+\:\mathrm{1}\:=\:\mathrm{0}\:\mathrm{is}\:\mathrm{equal}\:\mathrm{to} \\ $$
Question Number 32409 Answers: 1 Comments: 0
Question Number 32407 Answers: 0 Comments: 1
$$\underset{{x}\rightarrow\mathrm{0}} {\mathrm{lim}}\frac{\mathrm{1}−\mathrm{cos}\:\left(\mathrm{1}−\mathrm{cos}\:\boldsymbol{\mathrm{x}}\right)}{\boldsymbol{\mathrm{x}}×\boldsymbol{\mathrm{x}}×\boldsymbol{\mathrm{x}}×\boldsymbol{\mathrm{x}}} \\ $$
Question Number 32402 Answers: 0 Comments: 1
$$\int\frac{{x}+\mathrm{2}}{\mathrm{1}−{x}} \\ $$
Question Number 32401 Answers: 0 Comments: 0
Question Number 32399 Answers: 0 Comments: 0
Question Number 32396 Answers: 1 Comments: 0
$${roots} \\ $$$$\mathrm{2}{x}×\boldsymbol{{x}}+\boldsymbol{{x}}+\mathrm{3} \\ $$
Question Number 32395 Answers: 0 Comments: 1
$$\mathrm{1}+\mathrm{1} \\ $$
Question Number 32382 Answers: 2 Comments: 2
$$\mathrm{If}\:\mathrm{the}\:\mathrm{equation}\:{ax}^{\mathrm{2}} +\mathrm{2}{bx}−\mathrm{3}{c}=\mathrm{0}\:\mathrm{has} \\ $$$$\mathrm{no}\:\mathrm{real}\:\mathrm{roots}\:\mathrm{and}\:\left(\frac{\mathrm{3}{c}}{\mathrm{4}}\right)<\:{a}+{b},\:\mathrm{then} \\ $$
Question Number 32380 Answers: 1 Comments: 2
Question Number 32379 Answers: 1 Comments: 0
Question Number 32376 Answers: 4 Comments: 1
Question Number 32369 Answers: 0 Comments: 0
$${prove}\:{that}\:\:{n}^{−\alpha} \:\sim\:\int_{{n}} ^{{n}+\mathrm{1}} \:{t}^{−\alpha} {dt} \\ $$$$\left.\mathrm{2}\right)\:{prove}\:{that}\:\:\sum_{{k}=\mathrm{1}} ^{{n}} \:\:\frac{\mathrm{1}}{{k}^{\alpha} }\:\sim\:\:\frac{{n}^{\mathrm{1}−\alpha} }{\mathrm{1}−\alpha}\:{if}\:\:\alpha<\mathrm{1}\:{and} \\ $$$$\sum_{{k}=\mathrm{1}} ^{{n}} \:\:\frac{\mathrm{1}}{{k}^{\alpha} }\:\sim\:{ln}\left({n}\right)\:{if}\:\alpha=\mathrm{1}\:. \\ $$
Question Number 32367 Answers: 0 Comments: 0
$${let}\:\alpha\in{R}\:{and}\:{x}^{\mathrm{2}} \neq\mathrm{1}\:\:{find}\:{the}\:{value}\:{of} \\ $$$${f}\left({x}\right)\:=\:\int_{\mathrm{0}} ^{\pi} \:{ln}\left({x}^{\mathrm{2}} −\mathrm{2}{x}\:{cost}\:+\mathrm{1}\right){dt} \\ $$$${calculate}\:{f}\left({x}\right). \\ $$
Question Number 32365 Answers: 0 Comments: 3
$${let}\:{F}\left({x}\right)\:=\:\int_{\mathrm{0}} ^{\pi} \:{ln}\left(\mathrm{1}+{xcos}\theta\right){d}\theta\:.{with}\:\mid{x}\mid<\mathrm{1} \\ $$$${find}\:{F}\left({x}\right)\:. \\ $$
Question Number 32364 Answers: 0 Comments: 1
$${let}\:\:{u}_{{n}} =\:\left({e}\:−\left(\mathrm{1}+\frac{\mathrm{1}}{{n}}\right)^{{n}} \right)^{\sqrt{{n}^{\mathrm{2}} \:+\mathrm{2}}\:\:−\sqrt{{n}^{\mathrm{2}} \:+\mathrm{1}}} \\ $$$${find}\:\:{lim}\:{u}_{{n}} \\ $$
Question Number 32363 Answers: 0 Comments: 1
$${let}\:{consider}\:{the}\:{function} \\ $$$${f}\left({x},\theta\right)\:=\:\:\int_{{x}} ^{{x}^{\mathrm{2}} } {ln}\left(\:\mathrm{2}+{sin}\theta\:{cost}\right){dt} \\ $$$${calculate}\:\frac{\partial{f}}{\partial{x}}\left({x},\theta\right)\:{and}\:\:\frac{\partial{f}}{\partial\theta}\left({x},\theta\right)\:. \\ $$
Question Number 32362 Answers: 1 Comments: 0
$${calculate}\:\int_{\mathrm{0}} ^{\infty} \:\:\:\:\:\frac{{dx}}{\left(\mathrm{2}{x}+\mathrm{1}\right)\left(\mathrm{2}{x}+\mathrm{3}\right)\left(\mathrm{2}{x}+\mathrm{5}\right)}\:. \\ $$
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