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AllQuestion and Answers: Page 170

Question Number 204328 Answers: 0 Comments: 1

Question Number 204323 Answers: 0 Comments: 0

Question Number 204321 Answers: 0 Comments: 0

Question Number 204318 Answers: 1 Comments: 0

Question Number 204313 Answers: 1 Comments: 0

lim((3×^2 −8×−16)/(2×^2 9×+4))

$${lim}\frac{\mathrm{3}×^{\mathrm{2}} −\mathrm{8}×−\mathrm{16}}{\mathrm{2}×^{\mathrm{2}} \mathrm{9}×+\mathrm{4}} \\ $$$$ \\ $$

Question Number 204303 Answers: 1 Comments: 0

Question Number 204302 Answers: 1 Comments: 0

Question Number 204300 Answers: 1 Comments: 0

x^2 log_3 x^2 −(2x^2 +3)log_9 (2x+3)=3log_3 ((x/(2x+3)))

$${x}^{\mathrm{2}} \mathrm{log}_{\mathrm{3}} {x}^{\mathrm{2}} −\left(\mathrm{2}{x}^{\mathrm{2}} +\mathrm{3}\right)\mathrm{log}_{\mathrm{9}} \left(\mathrm{2}{x}+\mathrm{3}\right)=\mathrm{3log}_{\mathrm{3}} \left(\frac{{x}}{\mathrm{2}{x}+\mathrm{3}}\right) \\ $$

Question Number 204293 Answers: 1 Comments: 1

Prove the following trig identity: ((2sinα+sin3α+sin5α)/(cosα−2cos2α+cos3α))=((2cos2α)/(tan(α/2)))

$$\mathrm{Prove}\:\mathrm{the}\:\mathrm{following}\:\mathrm{trig}\:\mathrm{identity}: \\ $$$$\frac{\mathrm{2sin}\alpha+\mathrm{sin3}\alpha+\mathrm{sin5}\alpha}{\mathrm{cos}\alpha−\mathrm{2cos2}\alpha+\mathrm{cos3}\alpha}=\frac{\mathrm{2cos2}\alpha}{\mathrm{tan}\frac{\alpha}{\mathrm{2}}} \\ $$

Question Number 204279 Answers: 0 Comments: 1

Question Number 204278 Answers: 1 Comments: 3

cos x+cos 3x+cos 5x=(√2)+1 sin x+sin3x+ sin 5x=1 tan 3x=?

$$\mathrm{cos}\:{x}+\mathrm{cos}\:\mathrm{3}{x}+\mathrm{cos}\:\mathrm{5}{x}=\sqrt{\mathrm{2}}+\mathrm{1} \\ $$$$\mathrm{sin}\:{x}+\mathrm{sin3}{x}+\:\mathrm{sin}\:\mathrm{5}{x}=\mathrm{1} \\ $$$$\mathrm{tan}\:\mathrm{3}{x}=? \\ $$

Question Number 204276 Answers: 0 Comments: 0

Question Number 204275 Answers: 1 Comments: 0

Show that ∫_0 ^(π/4) (√(tan x)) (√(1−tan x)) dx=(((√((√2)−1))/( (√2)))−1)π

$$\mathrm{Show}\:\mathrm{that} \\ $$$$\underset{\mathrm{0}} {\overset{\frac{\pi}{\mathrm{4}}} {\int}}\sqrt{\mathrm{tan}\:{x}}\:\sqrt{\mathrm{1}−\mathrm{tan}\:{x}}\:{dx}=\left(\frac{\sqrt{\sqrt{\mathrm{2}}−\mathrm{1}}}{\:\sqrt{\mathrm{2}}}−\mathrm{1}\right)\pi \\ $$

Question Number 204273 Answers: 1 Comments: 0

f(x)=(1/((x−1)^(ln((2/4))) )) Domain f(x) =?

$$\mathrm{f}\left(\mathrm{x}\right)=\frac{\mathrm{1}}{\left(\mathrm{x}−\mathrm{1}\right)^{\mathrm{ln}\left(\frac{\mathrm{2}}{\mathrm{4}}\right)} } \\ $$$$\mathrm{Domain}\:\mathrm{f}\left(\mathrm{x}\right)\:=? \\ $$

Question Number 204262 Answers: 1 Comments: 0

Question Number 204264 Answers: 1 Comments: 0

∫_ ln(1−x^2 )dx

$$\underset{} {\int}{ln}\left(\mathrm{1}−{x}^{\mathrm{2}} \right){dx} \\ $$

Question Number 204250 Answers: 3 Comments: 0

Question Number 204249 Answers: 2 Comments: 1

Question Number 204310 Answers: 1 Comments: 0

Question Number 204244 Answers: 2 Comments: 0

Question Number 204236 Answers: 1 Comments: 1

Helpful questionfor Olympiads, Find Sol^n .

$$\boldsymbol{{Helpful}}\:\boldsymbol{{questionfor}}\:\boldsymbol{{Olympiads}},\:\boldsymbol{{Find}}\:\boldsymbol{{Sol}}^{\boldsymbol{{n}}} . \\ $$

Question Number 204233 Answers: 2 Comments: 0

Question Number 204230 Answers: 1 Comments: 10

what does mean that we say C^° =F^° in −40?

$${what}\:{does}\:{mean}\:{that}\:{we}\:{say}\:{C}^{°} ={F}^{°} \\ $$$${in}\:−\mathrm{40}? \\ $$

Question Number 204270 Answers: 2 Comments: 0

Question Number 204218 Answers: 2 Comments: 0

Question Number 204211 Answers: 2 Comments: 0

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