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Question Number 43452 Answers: 1 Comments: 0

prove that tanhx=itanx

$$\mathrm{prove}\:\mathrm{that} \\ $$$$\boldsymbol{\mathrm{tanh}{x}}=\boldsymbol{{i}\mathrm{tan}{x}} \\ $$

Question Number 43449 Answers: 1 Comments: 0

Question Number 43446 Answers: 0 Comments: 0

Question Number 43441 Answers: 0 Comments: 0

Question Number 43438 Answers: 2 Comments: 0

Question Number 43434 Answers: 0 Comments: 1

Let P and Q be statements. If (∼P) ∨ Q is true, then P ∨ Q is false. True or False?

$$\mathrm{Let}\:{P}\:\mathrm{and}\:{Q}\:\mathrm{be}\:\mathrm{statements}.\:\mathrm{If}\:\left(\sim{P}\right)\:\vee\:{Q}\:\mathrm{is}\:\mathrm{true}, \\ $$$$\mathrm{then}\:{P}\:\:\vee\:{Q}\:\mathrm{is}\:\mathrm{false}. \\ $$$$\mathrm{True}\:\mathrm{or}\:\mathrm{False}? \\ $$

Question Number 43419 Answers: 0 Comments: 2

Question Number 43418 Answers: 1 Comments: 0

Question Number 43417 Answers: 1 Comments: 2

Question Number 43416 Answers: 0 Comments: 1

Question Number 43404 Answers: 1 Comments: 0

Question Number 43398 Answers: 0 Comments: 0

Question Number 43395 Answers: 1 Comments: 2

Question Number 43393 Answers: 0 Comments: 0

Question Number 43391 Answers: 1 Comments: 0

x^2 +x=y^4 +y^3 +y^2 +y x^4 +(x+1)^4 =y^2 +(y+1)^2 find x and y of is…

$${x}^{\mathrm{2}} +{x}={y}^{\mathrm{4}} +{y}^{\mathrm{3}} +{y}^{\mathrm{2}} +{y} \\ $$$${x}^{\mathrm{4}} +\left({x}+\mathrm{1}\right)^{\mathrm{4}} ={y}^{\mathrm{2}} +\left({y}+\mathrm{1}\right)^{\mathrm{2}} \\ $$$$\mathrm{find}\:{x}\:\mathrm{and}\:{y}\:\:\mathrm{of}\:\mathrm{is}\ldots \\ $$$$ \\ $$

Question Number 43386 Answers: 4 Comments: 4

Question Number 43384 Answers: 1 Comments: 0

Question Number 43374 Answers: 1 Comments: 0

A drawer contains 5 brown socks and 4 blue socks well mixed. A man reaches the drawer and pulls out 2 socks at random. What is the probability that they match?

$$\mathrm{A}\:\mathrm{drawer}\:\mathrm{contains}\:\mathrm{5}\:\mathrm{brown}\:\mathrm{socks}\:\mathrm{and}\:\mathrm{4} \\ $$$$\mathrm{blue}\:\mathrm{socks}\:\mathrm{well}\:\mathrm{mixed}.\:\mathrm{A}\:\mathrm{man}\:\mathrm{reaches} \\ $$$$\mathrm{the}\:\mathrm{drawer}\:\mathrm{and}\:\mathrm{pulls}\:\mathrm{out}\:\mathrm{2}\:\mathrm{socks}\:\mathrm{at} \\ $$$$\mathrm{random}.\:\mathrm{What}\:\mathrm{is}\:\mathrm{the}\:\mathrm{probability}\:\mathrm{that} \\ $$$$\mathrm{they}\:\mathrm{match}? \\ $$

Question Number 43365 Answers: 0 Comments: 0

Question Number 43363 Answers: 3 Comments: 1

If z= cos θ + isin θ , 0<θ<(π/6) , then prove that argument of 1−z^4 = 2θ − (π/2) .

$$\mathrm{If}\:\mathrm{z}=\:\mathrm{cos}\:\theta\:+\:\mathrm{isin}\:\theta\:,\:\mathrm{0}<\theta<\frac{\pi}{\mathrm{6}}\:,\:\mathrm{then}\:\mathrm{prove} \\ $$$$\mathrm{that}\:\mathrm{argument}\:\mathrm{of}\:\:\mathrm{1}−\mathrm{z}^{\mathrm{4}} \:=\:\mathrm{2}\theta\:−\:\frac{\pi}{\mathrm{2}}\:. \\ $$

Question Number 43360 Answers: 0 Comments: 9

Question Number 43354 Answers: 1 Comments: 0

A particle starts from rest with acceleration(30+6t) ms^(−2) at time t. Where will the particle come to rest again?

$$\mathrm{A}\:\mathrm{particle}\:\mathrm{starts}\:\mathrm{from}\:\mathrm{rest}\:\mathrm{with}\:\mathrm{acceleration}\left(\mathrm{30}+\mathrm{6t}\right) \\ $$$$\mathrm{ms}^{−\mathrm{2}} \:\mathrm{at}\:\mathrm{time}\:\mathrm{t}.\:\mathrm{Where}\:\mathrm{will}\:\mathrm{the}\:\mathrm{particle}\:\mathrm{come}\:\mathrm{to}\:\mathrm{rest} \\ $$$$\mathrm{again}? \\ $$

Question Number 43353 Answers: 2 Comments: 1

Given the functions f(x)=2x−1 and f•g(x)=x^2 −x+2, find g(x)

$$\mathrm{Given}\:\mathrm{the}\:\mathrm{functions}\:\mathrm{f}\left(\mathrm{x}\right)=\mathrm{2x}−\mathrm{1}\:\mathrm{and}\:\mathrm{f}\bullet\mathrm{g}\left(\mathrm{x}\right)=\mathrm{x}^{\mathrm{2}} −\mathrm{x}+\mathrm{2}, \\ $$$$\mathrm{find}\:\mathrm{g}\left(\mathrm{x}\right) \\ $$

Question Number 43351 Answers: 0 Comments: 0

Question Number 43350 Answers: 1 Comments: 2

Question Number 43349 Answers: 2 Comments: 0

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