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Question Number 43625 Answers: 1 Comments: 0

∫_( 0) ^(π/4) ((√(tan x))/(sin x cos x)) dx = 2

$$\underset{\:\mathrm{0}} {\overset{\pi/\mathrm{4}} {\int}}\:\:\frac{\sqrt{\mathrm{tan}\:{x}}}{\mathrm{sin}\:{x}\:\mathrm{cos}\:{x}}\:{dx}\:=\:\mathrm{2} \\ $$

Question Number 43624 Answers: 1 Comments: 1

∫_( 0) ^1 ((tan^(−1) x)/(1+x^2 )) dx =

$$\underset{\:\mathrm{0}} {\overset{\mathrm{1}} {\int}}\:\:\:\frac{\mathrm{tan}^{−\mathrm{1}} {x}}{\mathrm{1}+{x}^{\mathrm{2}} }\:{dx}\:= \\ $$

Question Number 43623 Answers: 1 Comments: 3

let f(x)=∫_0 ^x (dt/(1+t^4 )) 1) find a explicit form of f(x) 2) calculate ∫_0 ^∞ (dt/(1+t^4 ))

$${let}\:{f}\left({x}\right)=\int_{\mathrm{0}} ^{{x}} \:\frac{{dt}}{\mathrm{1}+{t}^{\mathrm{4}} } \\ $$$$\left.\mathrm{1}\right)\:{find}\:\:{a}\:{explicit}\:{form}\:{of}\:{f}\left({x}\right) \\ $$$$\left.\mathrm{2}\right)\:{calculate}\:\int_{\mathrm{0}} ^{\infty} \:\:\frac{{dt}}{\mathrm{1}+{t}^{\mathrm{4}} } \\ $$

Question Number 43621 Answers: 1 Comments: 2

Question Number 43616 Answers: 1 Comments: 0

Solve: x^2 y′′ + xy′ − y = x , y_1 = x

$$\mathrm{Solve}:\:\:\:\mathrm{x}^{\mathrm{2}} \mathrm{y}''\:\:+\:\:\mathrm{xy}'\:\:−\:\mathrm{y}\:=\:\mathrm{x}\:,\:\:\:\:\:\:\:\:\mathrm{y}_{\mathrm{1}} \:=\:\mathrm{x} \\ $$

Question Number 43613 Answers: 0 Comments: 0

Be the vectors a^→ = (1, −1, 2), b^→ = (−5, k, k) and c^→ = (3, 1, 2) in the rectangular Cartesian coordinate system. For any vector r^→ , the equation r^→ ×a^→ + kb^→ = c^→ has a solution when k is equal to?

Question Number 43599 Answers: 0 Comments: 0

(dy/dx)(x^2 y^2 +xy)=1 Solve differential equation Thanks

$$\frac{{dy}}{{dx}}\left({x}^{\mathrm{2}} {y}^{\mathrm{2}} +{xy}\right)=\mathrm{1} \\ $$$$\mathrm{Solve}\:\mathrm{differential}\:\mathrm{equation} \\ $$$$\mathrm{Thanks} \\ $$

Question Number 43608 Answers: 0 Comments: 3

MJS [ 12/9/18 ] Code − 43569 I solved one of these , where and how do i get the prize ? the google+ page doesn′t really tell. i cannot see where to send my solution and I can′t see any guarantee to keep my copyright LYCON TRIX − Gentlemen , Download Slack app then provide your email , further regime will be operated there we won′t trouble you either , we care for your comfort level I′m the general manager of NS7UC initiave , LYCON TRIX

$$\mathrm{MJS}\:\left[\:\:\mathrm{12}/\mathrm{9}/\mathrm{18}\:\right]\:\mathrm{Code}\:−\:\mathrm{43569}\: \\ $$$$\mathrm{I}\:\mathrm{solved}\:\mathrm{one}\:\mathrm{of}\:\mathrm{these}\:,\:\mathrm{where}\:\mathrm{and}\:\mathrm{how}\:\mathrm{do} \\ $$$$\mathrm{i}\:\mathrm{get}\:\mathrm{the}\:\mathrm{prize}\:?\: \\ $$$$\mathrm{the}\:\mathrm{google}+\:\mathrm{page}\:\mathrm{doesn}'\mathrm{t}\:\mathrm{really}\:\mathrm{tell}. \\ $$$$\mathrm{i}\:\mathrm{cannot}\:\mathrm{see}\:\mathrm{where}\:\mathrm{to}\:\mathrm{send}\:\mathrm{my}\:\mathrm{solution}\: \\ $$$$\mathrm{and}\:\mathrm{I}\:\mathrm{can}'\mathrm{t}\:\mathrm{see}\:\mathrm{any}\:\mathrm{guarantee}\:\mathrm{to}\:\mathrm{keep}\:\mathrm{my} \\ $$$$\mathrm{copyright}\: \\ $$$$\mathrm{LYCON}\:\mathrm{TRIX}\:−\: \\ $$$$\mathrm{Gentlemen}\:,\:\mathrm{Download}\:\mathrm{Slack}\:\mathrm{app}\: \\ $$$$\mathrm{then}\:\mathrm{provide}\:\mathrm{your}\:\mathrm{email}\:,\:\mathrm{further}\:\mathrm{regime} \\ $$$$\mathrm{will}\:\mathrm{be}\:\mathrm{operated}\:\mathrm{there}\: \\ $$$$\mathrm{we}\:\mathrm{won}'\mathrm{t}\:\mathrm{trouble}\:\mathrm{you}\:\mathrm{either}\:,\:\mathrm{we}\:\mathrm{care}\: \\ $$$$\mathrm{for}\:\mathrm{your}\:\mathrm{comfort}\:\mathrm{level}\: \\ $$$$\mathrm{I}'\mathrm{m}\:\mathrm{the}\:\mathrm{general}\:\mathrm{manager}\:\mathrm{of}\:\mathrm{NS7UC}\: \\ $$$$\mathrm{initiave}\:,\:\mathrm{LYCON}\:\mathrm{TRIX} \\ $$

Question Number 43606 Answers: 0 Comments: 0

Question Number 43603 Answers: 1 Comments: 0

If the sum of first two terms of an infinite GP is 1 and every term is twice the sum of all the successive terms, then its first term is

$$\mathrm{If}\:\mathrm{the}\:\mathrm{sum}\:\mathrm{of}\:\mathrm{first}\:\mathrm{two}\:\mathrm{terms}\:\mathrm{of}\:\mathrm{an}\:\mathrm{infinite} \\ $$$$\mathrm{GP}\:\mathrm{is}\:\mathrm{1}\:\mathrm{and}\:\mathrm{every}\:\mathrm{term}\:\mathrm{is}\:\mathrm{twice}\:\mathrm{the}\:\mathrm{sum} \\ $$$$\mathrm{of}\:\mathrm{all}\:\mathrm{the}\:\mathrm{successive}\:\mathrm{terms},\:\mathrm{then}\:\mathrm{its} \\ $$$$\mathrm{first}\:\mathrm{term}\:\mathrm{is} \\ $$

Question Number 43602 Answers: 1 Comments: 0

If a, b, c are in GP and log_c a, log_b c, log_a b are in AP, then the common difference of the AP is

$$\mathrm{If}\:\:{a},\:{b},\:{c}\:\:\mathrm{are}\:\mathrm{in}\:\mathrm{GP}\:\mathrm{and}\:\mathrm{log}_{{c}} {a},\:\mathrm{log}_{{b}} {c},\:\mathrm{log}_{{a}} {b} \\ $$$$\mathrm{are}\:\mathrm{in}\:\mathrm{AP},\:\mathrm{then}\:\mathrm{the}\:\mathrm{common}\:\mathrm{difference} \\ $$$$\mathrm{of}\:\mathrm{the}\:\mathrm{AP}\:\mathrm{is} \\ $$

Question Number 43596 Answers: 0 Comments: 0

Question Number 43574 Answers: 1 Comments: 0

Two cyclists Musa and Amadu left point p at the same time in opposite directions. If their speeds are 8 km/h and12 km/h respectively; i. how will it take them to be 40 km apart? ii. calculate the distance covered by Musa within the time in (i)

$$\mathrm{Two}\:\mathrm{cyclists}\:\mathrm{Musa}\:\mathrm{and}\:\mathrm{Amadu}\:\mathrm{left}\:\mathrm{point}\:\mathrm{p}\:\mathrm{at}\:\mathrm{the}\: \\ $$$$\mathrm{same}\:\mathrm{time}\:\mathrm{in}\:\mathrm{opposite}\:\mathrm{directions}.\:\mathrm{If}\:\mathrm{their}\:\mathrm{speeds}\:\mathrm{are} \\ $$$$\mathrm{8}\:\mathrm{km}/\mathrm{h}\:\mathrm{and12}\:\mathrm{km}/\mathrm{h}\:\mathrm{respectively};\: \\ $$$$\mathrm{i}.\:\mathrm{how}\:\mathrm{will}\:\mathrm{it}\:\mathrm{take}\:\mathrm{them}\:\mathrm{to}\:\mathrm{be}\:\mathrm{40}\:\mathrm{km}\:\mathrm{apart}? \\ $$$$\mathrm{ii}.\:\mathrm{calculate}\:\mathrm{the}\:\mathrm{distance}\:\mathrm{covered}\:\mathrm{by}\:\mathrm{Musa}\:\mathrm{within} \\ $$$$\mathrm{the}\:\mathrm{time}\:\mathrm{in}\:\left(\mathrm{i}\right) \\ $$

Question Number 43571 Answers: 1 Comments: 0