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Question Number 46186 Answers: 1 Comments: 1

please help me! S=1^2 q^1 +2^2 q^2 +3^2 q^3 +...+n^2 q^n =?

$$\mathrm{please}\:\mathrm{help}\:\mathrm{me}! \\ $$$$\mathrm{S}=\mathrm{1}^{\mathrm{2}} \mathrm{q}^{\mathrm{1}} +\mathrm{2}^{\mathrm{2}} \mathrm{q}^{\mathrm{2}} +\mathrm{3}^{\mathrm{2}} \mathrm{q}^{\mathrm{3}} +...+\mathrm{n}^{\mathrm{2}} \mathrm{q}^{\mathrm{n}} =? \\ $$

Question Number 46182 Answers: 1 Comments: 4

Question Number 46180 Answers: 0 Comments: 3

Question Number 46172 Answers: 1 Comments: 0

Question Number 46171 Answers: 0 Comments: 1

find ∫ (dx/((√x)+(√(x+1)) +(√(x+2))))

$${find}\:\int\:\:\:\:\frac{{dx}}{\sqrt{{x}}+\sqrt{{x}+\mathrm{1}}\:+\sqrt{{x}+\mathrm{2}}} \\ $$

Question Number 46168 Answers: 2 Comments: 0

Question Number 46157 Answers: 1 Comments: 0

Please help. Find all the general solution of 6x + 8y + 5z = 101 . I got: x = − 48 + 45m + 4n y = 48 + 45m − 3n z = 1 − 2m Please help. Am confused.

$$\mathrm{Please}\:\mathrm{help}. \\ $$$$\:\:\:\:\:\mathrm{Find}\:\mathrm{all}\:\mathrm{the}\:\mathrm{general}\:\mathrm{solution}\:\mathrm{of}\:\:\:\:\:\:\:\mathrm{6x}\:+\:\mathrm{8y}\:+\:\mathrm{5z}\:=\:\mathrm{101}\:. \\ $$$$ \\ $$$$\mathrm{I}\:\mathrm{got}:\:\:\:\:\:\:\:\:\mathrm{x}\:=\:−\:\mathrm{48}\:+\:\mathrm{45m}\:+\:\mathrm{4n} \\ $$$$\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\mathrm{y}\:=\:\:\:\:\:\mathrm{48}\:+\:\mathrm{45m}\:−\:\mathrm{3n} \\ $$$$\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\mathrm{z}\:=\:\:\:\:\:\:\:\mathrm{1}\:−\:\mathrm{2m} \\ $$$$ \\ $$$$\mathrm{Please}\:\mathrm{help}.\:\:\mathrm{Am}\:\mathrm{confused}.\: \\ $$

Question Number 46156 Answers: 1 Comments: 0

Question Number 46146 Answers: 0 Comments: 3

Question Number 46144 Answers: 0 Comments: 0

Object A is in motion.A moves at a velocity of 12ms^(−2) and B is still(not moving).If A collides with B. a) Calculate the velocity at which B will move if it has mass of 70kg. and A has mass of 60kg. b) the momentum after collision. c) state the principle you applied in a) and b) above

$$\:{Object}\:{A}\:{is}\:{in}\:{motion}.{A}\:{moves}\:{at}\:{a}\:{velocity}\:{of}\: \\ $$$$\mathrm{12}{ms}^{−\mathrm{2}} \:{and}\:{B}\:{is}\:{still}\left({not}\:{moving}\right).{If}\:{A}\:{collides}\:{with}\:{B}. \\ $$$$\left.{a}\right)\:{Calculate}\:{the}\:{velocity}\:{at}\:{which}\:{B}\:{will}\:{move}\:{if}\:{it}\:{has}\:{mass} \\ $$$${of}\:\mathrm{70}{kg}.\:{and}\:{A}\:{has}\:{mass}\:{of}\:\mathrm{60}{kg}. \\ $$$$\left.{b}\right)\:{the}\:{momentum}\:{after}\:{collision}. \\ $$$$\left.{c}\left.\right)\left.\:{state}\:{the}\:{principle}\:{you}\:{applied}\:{in}\:{a}\right)\:{and}\:{b}\right)\:{above} \\ $$$$ \\ $$

Question Number 46143 Answers: 1 Comments: 0

Question Number 46139 Answers: 2 Comments: 1

A park has the shape of a regular hexagon of sides 2km each. A boy walks a distance of 5km along the sides of the park. What is the direct distance between the start point and the end point?

$$\mathrm{A}\:\mathrm{park}\:\mathrm{has}\:\mathrm{the}\:\mathrm{shape}\:\mathrm{of}\:\mathrm{a}\:\mathrm{regular}\:\mathrm{hexagon} \\ $$$$\mathrm{of}\:\mathrm{sides}\:\mathrm{2km}\:\mathrm{each}.\:\mathrm{A}\:\mathrm{boy}\:\mathrm{walks}\:\mathrm{a}\:\mathrm{distance} \\ $$$$\mathrm{of}\:\mathrm{5km}\:\mathrm{along}\:\mathrm{the}\:\mathrm{sides}\:\mathrm{of}\:\mathrm{the}\:\mathrm{park}.\: \\ $$$$\mathrm{What}\:\mathrm{is}\:\mathrm{the}\:\mathrm{direct}\:\mathrm{distance}\:\mathrm{between}\: \\ $$$$\mathrm{the}\:\mathrm{start}\:\mathrm{point}\:\mathrm{and}\:\mathrm{the}\:\mathrm{end}\:\mathrm{point}? \\ $$

Question Number 46136 Answers: 1 Comments: 0