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Question Number 47639 Answers: 1 Comments: 0

derivation or proof or full explanation of R=(R_1 ^2 +R_2 ^2 +2R_1 .R_2 cosθ)^(1/2)

$$\boldsymbol{\mathrm{derivation}}\:\boldsymbol{\mathrm{or}}\:\boldsymbol{\mathrm{proof}}\:\boldsymbol{\mathrm{or}}\:\boldsymbol{\mathrm{full}}\:\boldsymbol{\mathrm{explanation}} \\ $$$$\boldsymbol{\mathrm{of}}\:\boldsymbol{\mathrm{R}}=\left(\boldsymbol{\mathrm{R}}_{\mathrm{1}} ^{\mathrm{2}} +\boldsymbol{\mathrm{R}}_{\mathrm{2}} ^{\mathrm{2}} +\mathrm{2R}_{\mathrm{1}} .\mathrm{R}_{\mathrm{2}} \mathrm{cos}\theta\right)^{\mathrm{1}/\mathrm{2}} \\ $$

Question Number 47628 Answers: 1 Comments: 0

If the first term and n^(th) term of G.P., are a and b respectively, p is the product of n terms. Prove that p^2 = (ab)^n .

$$\mathrm{If}\:\mathrm{the}\:\mathrm{first}\:\mathrm{term}\:\mathrm{and}\:\mathrm{n}^{\mathrm{th}} \:\mathrm{term}\:\mathrm{of}\:\mathrm{G}.\mathrm{P}.,\:\:\mathrm{are}\:\mathrm{a}\:\mathrm{and}\:\mathrm{b}\:\mathrm{respectively},\: \\ $$$$\mathrm{p}\:\mathrm{is}\:\mathrm{the}\:\mathrm{product}\:\mathrm{of}\:\mathrm{n}\:\mathrm{terms}.\:\mathrm{Prove}\:\mathrm{that}\:\mathrm{p}^{\mathrm{2}} \:=\:\left(\mathrm{ab}\right)^{\mathrm{n}} . \\ $$$$ \\ $$$$ \\ $$

Question Number 47627 Answers: 0 Comments: 0

Could someone explain me how cellular automata theory can be used in the bioligical field in relation to the spread of disease and/or cancer cells ? Thank you very much !

$$\mathrm{Could}\:\mathrm{someone}\:\mathrm{explain}\:\mathrm{me}\:\mathrm{how}\:\mathrm{cellular} \\ $$$$\mathrm{automata}\:\mathrm{theory}\:\mathrm{can}\:\mathrm{be}\:\mathrm{used}\:\mathrm{in}\:\mathrm{the} \\ $$$$\mathrm{bioligical}\:\mathrm{field}\:\mathrm{in}\:\mathrm{relation}\:\mathrm{to}\:\mathrm{the}\:\mathrm{spread} \\ $$$$\mathrm{of}\:\mathrm{disease}\:\mathrm{and}/\mathrm{or}\:\mathrm{cancer}\:\mathrm{cells}\:? \\ $$$${Thank}\:{you}\:{very}\:{much}\:! \\ $$

Question Number 47626 Answers: 0 Comments: 0

thanks sir

$$\mathrm{thanks}\:\mathrm{sir} \\ $$

Question Number 47624 Answers: 1 Comments: 0

Solve the d.e using method of variation of parameter. (d^2 y/dx^2 )+3(dy/dx)+2y=sin(e^x )

$$\mathrm{Solve}\:\mathrm{the}\:\mathrm{d}.\mathrm{e}\:\mathrm{using}\:\mathrm{method}\:\mathrm{of}\:\mathrm{variation} \\ $$$$\mathrm{of}\:\mathrm{parameter}. \\ $$$$ \\ $$$$\:\frac{\mathrm{d}^{\mathrm{2}} \mathrm{y}}{\mathrm{dx}^{\mathrm{2}} }+\mathrm{3}\frac{\mathrm{dy}}{\mathrm{dx}}+\mathrm{2y}=\mathrm{sin}\left(\mathrm{e}^{\mathrm{x}} \right) \\ $$

Question Number 47623 Answers: 0 Comments: 0

Solve the d.e using method of variation of parameter. (d^2 y/dx^2 )+3(dy/dx)+2y=sin(e^x )

Question Number 47613 Answers: 1 Comments: 0

1(8/9)=((2x−1)/5) sir plz help me

$$\mathrm{1}\frac{\mathrm{8}}{\mathrm{9}}=\frac{\mathrm{2x}−\mathrm{1}}{\mathrm{5}}\:\:\:\mathrm{sir}\:\mathrm{plz}\:\mathrm{help}\:\mathrm{me} \\ $$

Question Number 47621 Answers: 1 Comments: 1

Find locus of point P from which tangents PA & PB to circles x^2 +y^2 =a^2 and x^2 +y^2 =b^2 respectively are perpendicular.

$${Find}\:{locus}\:{of}\:{point}\:{P}\:{from}\:{which} \\ $$$${tangents}\:{PA}\:\&\:{PB}\:{to}\:{circles}\:{x}^{\mathrm{2}} +{y}^{\mathrm{2}} ={a}^{\mathrm{2}} \\ $$$${and}\:{x}^{\mathrm{2}} +{y}^{\mathrm{2}} ={b}^{\mathrm{2}} \:{respectively}\:{are}\:{perpendicular}. \\ $$

Question Number 47607 Answers: 1 Comments: 1

∫_a ^b ((∣x∣)/x)dx

$$\int_{{a}} ^{{b}} \frac{\mid{x}\mid}{{x}}{dx} \\ $$

Question Number 47801 Answers: 1 Comments: 0

An object starts from rest and moves with a velocity of (3i+4j)ms^(−1) . It covers a distance of 400km.Find a) its acceleration b) the time taken to cover the distance 400km.

$${An}\:{object}\:{starts}\:{from}\:{rest}\:{and}\:{moves}\:{with}\:{a}\:{velocity}\:{of}\: \\ $$$$\left(\mathrm{3}{i}+\mathrm{4}{j}\right){ms}^{−\mathrm{1}} .\:{It}\:{covers}\:{a}\:{distance}\:{of}\:\mathrm{400}{km}.{Find}\: \\ $$$$\left.{a}\right)\:{its}\:{acceleration} \\ $$$$\left.{b}\right)\:{the}\:{time}\:{taken}\:{to}\:{cover}\:{the}\:{distance}\:\mathrm{400}{km}. \\ $$

Question Number 47595 Answers: 0 Comments: 3