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Question Number 40457    Answers: 1   Comments: 0

Question Number 40442    Answers: 2   Comments: 0

Solve : y^4 dx + 2xy^3 dy = ((ydx− xdy)/(x^3 y^3 )).

Solve:y4dx+2xy3dy=ydxxdyx3y3.

Question Number 40434    Answers: 0   Comments: 3

prove that ln(x) is irrational for x natural

provethatln(x)isirrationalforxnatural

Question Number 40426    Answers: 0   Comments: 0

Question Number 40422    Answers: 1   Comments: 1

Solve: ydx − xdy +log xdx =0

Solve:ydxxdy+logxdx=0

Question Number 40418    Answers: 2   Comments: 1

Question Number 40417    Answers: 0   Comments: 0

Question Number 40407    Answers: 1   Comments: 0

let f(x)= x^3 −x−1 1) prove that ∃ α ∈ ]1,2[ /f(α)=0 2) use the newton method with x_0 =(3/2) to find a better value for α (take onlly 5 terms)

letf(x)=x3x11)provethatα]1,2[/f(α)=02)usethenewtonmethodwithx0=32tofindabettervalueforα(takeonlly5terms)

Question Number 40406    Answers: 1   Comments: 0

Question Number 40399    Answers: 3   Comments: 0

Solve : (2(√(xy)) −x)dy + ydx = 0.

Solve:(2xyx)dy+ydx=0.

Question Number 40397    Answers: 1   Comments: 0

Solve : (dy/dx) = ((sin y + x)/(sin 2y − xcos y)) .

Solve:dydx=siny+xsin2yxcosy.

Question Number 40396    Answers: 0   Comments: 1

A block lying on a horizontal conv− eyor belt moving at a constant velocity receives a velocity 5m/s at t=0 sec. relative to the ground in the direction opposite to the dir− ction of motion of the conveyor. Aftert=4sec,the velocity of the block becomes equal to the velocity of the belt . the coefficient of friction between the block and the belt is 0.2 . then the velocity of the conveyor belt is: (g=10m/s^2 ) (A) 13 m/s (B) −13m/s (C)3m/s (D) 6m/s

Ablocklyingonahorizontalconveyorbeltmovingataconstantvelocityreceivesavelocity5m/satt=0sec.relativetothegroundinthedirectionoppositetothedirctionofmotionoftheconveyor.Aftert=4sec,thevelocityoftheblockbecomesequaltothevelocityofthebelt.thecoefficientoffrictionbetweentheblockandthebeltis0.2.thenthevelocityoftheconveyorbeltis:(g=10m/s2)(A)13m/s(B)13m/s(C)3m/s(D)6m/s

Question Number 40388    Answers: 1   Comments: 0

Question Number 40378    Answers: 1   Comments: 3

(1/(1!))+(1/(2!))+(1/(3!))+....+(1/(2018!))=?

11!+12!+13!+....+12018!=?

Question Number 40376    Answers: 0   Comments: 3

Question Number 40375    Answers: 1   Comments: 0

Question Number 40380    Answers: 2   Comments: 1

Solve : (dy/dx) = ((x+y)/(x−y))

Solve:dydx=x+yxy

Question Number 40370    Answers: 0   Comments: 1

let u_n =Σ_(k=0) ^n (3k+1)(−1)^k 1) calculate interms of n S_n =u_0 +u_1 +u_2 +....+u_n 2) calculate u_0 +u_1 +u_2 +....+u_(57)

letun=k=0n(3k+1)(1)k1)calculateintermsofnSn=u0+u1+u2+....+un2)calculateu0+u1+u2+....+u57

Question Number 40466    Answers: 1   Comments: 5

Q..cos^(−1) (1−2x^2 )=2sin^(−1) x,prove please

Q..cos1(12x2)=2sin1x,proveplease

Question Number 40366    Answers: 0   Comments: 1

use newton raphson method to approximate the positive root x^2 −1=0 correct to 4 decimal places perform 3 iteration only setting with x=2

usenewtonraphsonmethodtoapproximatethepositiverootx21=0correctto4decimalplacesperform3iterationonlysettingwithx=2

Question Number 40355    Answers: 1   Comments: 0

Question Number 40352    Answers: 0   Comments: 1

If A= [((4 −3)),((1 0)) ]use the fact that A^2 =4A−3I_2 and mathematical induction to prove A^n =(((3^n −1))/2)A +((3−3^n )/2)I if n≥1

IfA=[4310]usethefactthatA2=4A3I2andmathematicalinductiontoproveAn=(3n1)2A+33n2Iifn1

Question Number 40467    Answers: 1   Comments: 2

∫ln ∣(√(x+1))+(√x)∣ dx=

lnx+1+xdx=

Question Number 40344    Answers: 1   Comments: 2

Question Number 40322    Answers: 1   Comments: 4

Solve : (d^2 y/dx^2 ) = ((dy/dx))^2

Solve:d2ydx2=(dydx)2

Question Number 40321    Answers: 0   Comments: 1

If abc=8 and (1/a) + (1/b) + (1/c) = (3/2) then find the value of ab+bc+ca.

Ifabc=8and1a+1b+1c=32thenfindthevalueofab+bc+ca.

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