Question and Answers Forum

All Questions   Topic List

AllQuestion and Answers: Page 1610

Question Number 40818    Answers: 1   Comments: 0

$${Two}\:{large}\:{parallel}\:{metal}\:{plates}\:{carrying} \\ $$$${opposite}\:{charges}\:{are}\:{seperated}\:{by}\:{a} \\ $$$${distance}\:{of}\:\mathrm{0}.\mathrm{2}{m},{and}\:{the}\:{potential} \\ $$$${difference}\:{between}\:{them}\:{is}\:\mathrm{0}.\mathrm{5}{KV}. \\ $$$$\left({a}\right){Calculate}\:{the}\:{magnitude}\:{of}\:{the} \\ $$$${uniform}\:{electric}\:{field}\:{between}\:{them}. \\ $$$$\left({b}\right){Also}\:{calculate}\:{the}\:{workdone}\:{by} \\ $$$${this}\:{field}\:{on}\:{a}\:{charge}\:{of}\:\mathrm{4}.\mathrm{0}×\mathrm{10}^{−\mathrm{9}} {C} \\ $$$${when}\:{it}\:{moves}\:{from}\:{the}\:{plate}\:{of} \\ $$$${higher}\:{potential}\:{to}\:{that}\:{of}\:{lower} \\ $$$${potential}. \\ $$

Question Number 40817    Answers: 1   Comments: 0

$${An}\:{electric}\:{field}\:{of}\:\mathrm{2}.\mathrm{66}{KV}/{m},{and} \\ $$$${a}\:{magnetic}\:{field}\:{of}\:\mathrm{1}.\mathrm{20}{T},{act}\:{on}\:{a} \\ $$$${moving}\:{electron}.{Calculate}\:{the}\:{speed} \\ $$$${of}\:{the}\:{electron}\:{if}\:{the}\:{resultant}\:{force} \\ $$$${due}\:{to}\:{both}\:{fields}\:{is}\:{zero}. \\ $$$$ \\ $$

Question Number 40816    Answers: 0   Comments: 0

$${An}\:{electric}\:{field}\:{of}\:\mathrm{2}.\mathrm{66}{KV}/{m},{and} \\ $$$${a}\:{magnetic}\:{field}\:{of}\:\mathrm{1}.\mathrm{20}{T},{act}\:{on}\:{a} \\ $$$${moving}\:{electron}.{Calculate}\:{the}\:{speed} \\ $$$${of}\:{the}\:{electron}\:{if}\:{the}\:{resultant}\:{force} \\ $$$${due}\:{to}\:{both}\:{fields}\:{is}\:{zero}. \\ $$$$ \\ $$

Question Number 40815    Answers: 1   Comments: 0

$${Calculate}\:{the}\:{magnetic}\:{force},{F}_{{b}} \:{on} \\ $$$${an}\:{electron}\:{with}\:{velocity},{v}=\mathrm{20}\hat {{j}m}/{s} \\ $$$${which}\:{enters}\:{a}\:{magnetic}\:{field}\:{of} \\ $$$${flux}\:{density},{B}=\mathrm{0}.\mathrm{6}\hat {{k}T} \\ $$

Question Number 40814    Answers: 0   Comments: 3

Question Number 40813    Answers: 0   Comments: 4

Question Number 40804    Answers: 0   Comments: 6

Question Number 40787    Answers: 1   Comments: 4

$$\mathrm{Let}\:\mathrm{I}_{\mathrm{1}} =\:\int_{\frac{\pi}{\mathrm{6}}} ^{\frac{\pi}{\mathrm{3}}} \frac{\mathrm{sin}\:{x}}{{x}}\:{dx}\:\:,\:\:\mathrm{I}_{\mathrm{2}} =\:\int_{\frac{\pi}{\mathrm{6}}} ^{\frac{\pi}{\mathrm{3}}} \frac{\mathrm{sin}\:\left(\mathrm{sin}\:{x}\right)}{\mathrm{sin}\:{x}}{dx} \\ $$$$,\:\mathrm{I}_{\mathrm{3}} =\:\int_{\frac{\pi}{\mathrm{6}}} ^{\frac{\pi}{\mathrm{3}}} \frac{\mathrm{sin}\:\left(\mathrm{tan}\:{x}\right)}{\mathrm{tan}\:{x}}{dx}.\: \\ $$$${P}\mathrm{rove}\:\mathrm{that}\:\mathrm{I}_{\mathrm{2}} \:>\:\mathrm{I}_{\mathrm{1}} \:>\:\mathrm{I}_{\mathrm{3}} \:. \\ $$

Question Number 40786    Answers: 1   Comments: 0

$${A}\:{parallel}\:{plate}\:{capacitor}\:{of}\:{plate} \\ $$$${spacing},\:\mathrm{1}{mm}\:{is}\:{charged}\:{to}\:{a}\:{potential} \\ $$$${of}\:\mathrm{50}{V}.{Find}\:{the}\:{energy}\:{density}\:{in} \\ $$$${the}\:{capacitor} \\ $$

Question Number 40782    Answers: 0   Comments: 0

$${let}\:{f}\left({x}\right)={ln}\left(\mathrm{1}+{arctanx}\right) \\ $$$$\left.\mathrm{1}\right)\:{calculate}\:{f}^{\left({n}\right)} \left({x}\right)\:{then}\:{f}^{\left({n}\right)} \left(\mathrm{0}\right) \\ $$$$\left.\mathrm{2}\right)\:{developp}\:{f}\:{at}\:{integr}\:{serie}\:. \\ $$

Question Number 40773    Answers: 1   Comments: 0

$${A}\:{pair}\:{of}\:{oppositely}\:{charged}\:{plane} \\ $$$${parallel}\:{plates}\:{each}\:{of}\:{area},\mathrm{100}{cm}^{\mathrm{2}} \\ $$$${has}\:{the}\:{electric}\:{field}\:{of}\:{the}\:{value} \\ $$$$\mathrm{5}.\mathrm{0}×\mathrm{10}^{\mathrm{4}} {N}/{C}.{Calculate}\:{the}\:{charge} \\ $$$${on}\:{each}\:{plate}. \\ $$

Question Number 40771    Answers: 2   Comments: 1

Question Number 40770    Answers: 1   Comments: 0

$${An}\:{electric}\:{dipole}\:{is}\:{placed}\:{at}\:{rest} \\ $$$${in}\:{a}\:{uniform}\:{external}\:{electric} \\ $$$${field},{and}\:{released}.{Discuss}\:{its} \\ $$$${motion}\:{mathematically}. \\ $$

Question Number 40764    Answers: 1   Comments: 0

$$\boldsymbol{\mathrm{a}}\:\boldsymbol{\mathrm{piece}}\:\boldsymbol{\mathrm{of}}\:\boldsymbol{\mathrm{wire}}\:\mathrm{40}\boldsymbol{\mathrm{cm}}\:\boldsymbol{\mathrm{long}} \\ $$$$\boldsymbol{\mathrm{is}}\:\boldsymbol{\mathrm{cut}}\:\boldsymbol{\mathrm{into}}\:\boldsymbol{\mathrm{two}}\:\boldsymbol{\mathrm{parts}}\:\boldsymbol{\mathrm{and}}\:\boldsymbol{\mathrm{each}}\:\boldsymbol{\mathrm{part}} \\ $$$$\boldsymbol{\mathrm{is}}\:\boldsymbol{\mathrm{then}}\:\boldsymbol{\mathrm{bent}}\:\boldsymbol{\mathrm{into}}\:\boldsymbol{\mathrm{a}}\:\boldsymbol{\mathrm{square}}.\boldsymbol{\mathrm{if}}\:\boldsymbol{\mathrm{the}}\:\boldsymbol{\mathrm{sum}} \\ $$$$\boldsymbol{\mathrm{of}}\:\boldsymbol{\mathrm{these}}\:\boldsymbol{\mathrm{squares}}\:\boldsymbol{\mathrm{is}}\:\mathrm{68}\boldsymbol{\mathrm{cm}}^{\mathrm{2}} \\ $$$$\boldsymbol{\mathrm{find}}\:\boldsymbol{\mathrm{the}}\:\boldsymbol{\mathrm{lengths}}\:\boldsymbol{\mathrm{of}}\:\:\boldsymbol{\mathrm{the}}\:\boldsymbol{\mathrm{two}} \\ $$$$\boldsymbol{\mathrm{pieces}}\:\boldsymbol{\mathrm{of}}\:\boldsymbol{\mathrm{wire}}. \\ $$

Question Number 40763    Answers: 2   Comments: 0

Question Number 40760    Answers: 0   Comments: 0

$${find}\:\:\int\:\:\:\frac{\sqrt{\mathrm{1}+{x}^{\mathrm{2}} }}{\sqrt{\mathrm{1}−{x}^{\mathrm{3}} }}\:{dx} \\ $$

Question Number 40759    Answers: 1   Comments: 2

$${calculate}\:{lim}_{{n}\rightarrow+\infty} \:\:\:\:\:\frac{\mathrm{1}−{e}^{−{nx}^{\mathrm{2}} } }{{x}^{\mathrm{2}} {sin}\left(\frac{\pi}{{n}}\right)} \\ $$

Question Number 40745    Answers: 3   Comments: 0

Question Number 40743    Answers: 2   Comments: 0

Question Number 40740    Answers: 0   Comments: 5

Question Number 40738    Answers: 2   Comments: 2

Question Number 40732    Answers: 1   Comments: 2

Question Number 40717    Answers: 1   Comments: 1

$$\int\sqrt{{tanx}/{sinx}.{cosxdx}} \\ $$

Question Number 40716    Answers: 2   Comments: 0

$$\int\left({cosx}−{cos}\mathrm{2}{x}/\mathrm{1}−{cosx}\right){dx} \\ $$

Question Number 40715    Answers: 1   Comments: 1

$$\mathrm{for}\:\mathrm{x}\geqslant\mathrm{2}\:\mid\mathrm{x}−\mathrm{2}\mid= \\ $$

Question Number 40711    Answers: 1   Comments: 0

$${Two}\:{point}\:{charges},{q}_{\mathrm{1}} =\mathrm{0}.\mathrm{4}\mu{C}\:{and} \\ $$$${q}_{\mathrm{2}} =−\mathrm{0}.\mathrm{3}\mu{C}\:{are}\:{placed}\:{at}\:\mathrm{10}{cm} \\ $$$${apart}.{Calculate}\: \\ $$$$\left({a}\right){the}\:{potential}\:{at}\:{point}\:{A}\:{which}\:{is} \\ $$$${midway}\:{between}\:{them},{and} \\ $$$$\left({b}\right){point}\:{B}\:{which}\:{is}\:\mathrm{6}{cm}\:{from}\:{q}_{\mathrm{1}} \\ $$$${and}\:\mathrm{8}{cm}\:{from}\:{q}_{\mathrm{2}} \\ $$

  Pg 1605      Pg 1606      Pg 1607      Pg 1608      Pg 1609      Pg 1610      Pg 1611      Pg 1612      Pg 1613      Pg 1614   

Terms of Service

Privacy Policy

Contact: info@tinkutara.com