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Question Number 47947 Answers: 0 Comments: 1

Question Number 47939 Answers: 1 Comments: 2

Question Number 47938 Answers: 0 Comments: 1

Question Number 47932 Answers: 1 Comments: 1

Question Number 47917 Answers: 0 Comments: 0

Question Number 47916 Answers: 2 Comments: 1

Question Number 47915 Answers: 2 Comments: 0

Question Number 47912 Answers: 0 Comments: 0

Question Number 47908 Answers: 0 Comments: 0

Question Number 47906 Answers: 0 Comments: 2

Question Number 47903 Answers: 0 Comments: 6

Question Number 47902 Answers: 0 Comments: 1

Question Number 47900 Answers: 0 Comments: 0

thanks sir

$${thanks}\:{sir} \\ $$

Question Number 47899 Answers: 0 Comments: 0

Question Number 47896 Answers: 1 Comments: 0

3(5/7)/2(1/7)=×/1.5 sir plz help me

$$\mathrm{3}\frac{\mathrm{5}}{\mathrm{7}}/\mathrm{2}\frac{\mathrm{1}}{\mathrm{7}}=×/\mathrm{1}.\mathrm{5}\:\:\:\:\:\mathrm{sir}\:\mathrm{plz}\:\mathrm{help}\:\mathrm{me} \\ $$$$ \\ $$

Question Number 47883 Answers: 2 Comments: 1

Question Number 47881 Answers: 0 Comments: 1

Question Number 47874 Answers: 0 Comments: 0

An elevator starts with m passengers and stops at n floors (m≤n). The probability that no passengers alight at the same floor is

$$\mathrm{An}\:\mathrm{elevator}\:\mathrm{starts}\:\mathrm{with}\:{m}\:\mathrm{passengers} \\ $$$$\mathrm{and}\:\mathrm{stops}\:\mathrm{at}\:{n}\:\mathrm{floors}\:\left({m}\leqslant{n}\right).\:\mathrm{The}\: \\ $$$$\mathrm{probability}\:\mathrm{that}\:\mathrm{no}\:\mathrm{passengers}\:\mathrm{alight} \\ $$$$\mathrm{at}\:\mathrm{the}\:\mathrm{same}\:\mathrm{floor}\:\mathrm{is} \\ $$

Question Number 47863 Answers: 0 Comments: 0

find ∫ (√(1−x^4 ))dx

$${find}\:\int\:\sqrt{\mathrm{1}−{x}^{\mathrm{4}} }{dx} \\ $$

Question Number 47860 Answers: 0 Comments: 1

Anyone know how it came to the working equation?

$$\mathrm{Anyone}\:\mathrm{know}\:\mathrm{how}\:\mathrm{it}\:\mathrm{came}\:\mathrm{to}\:\mathrm{the}\: \\ $$$$\mathrm{working}\:\mathrm{equation}? \\ $$

Question Number 47857 Answers: 0 Comments: 1

let A_n =Σ_(k=0) ^(n−1) sin(((kπ)/(2n))) and B_n =Σ_(k=0) ^(n−1) cos(((kπ)/(2n))) 1) find A_n and B_n interms of n 2)calculate lim_(n→+∞) (A_n /B_n ) 3)calculate ((lim_(n→+∞) A_n )/(lim_(n→+∞ ) B_n )) .

$${let}\:{A}_{{n}} =\sum_{{k}=\mathrm{0}} ^{{n}−\mathrm{1}} \:{sin}\left(\frac{{k}\pi}{\mathrm{2}{n}}\right)\:{and}\:{B}_{{n}} =\sum_{{k}=\mathrm{0}} ^{{n}−\mathrm{1}} \:{cos}\left(\frac{{k}\pi}{\mathrm{2}{n}}\right) \\ $$$$\left.\mathrm{1}\right)\:{find}\:{A}_{{n}} \:{and}\:{B}_{{n}} \:{interms}\:{of}\:{n} \\ $$$$\left.\mathrm{2}\right){calculate}\:{lim}_{{n}\rightarrow+\infty} \:\:\frac{{A}_{{n}} }{{B}_{{n}} } \\ $$$$\left.\mathrm{3}\right){calculate}\:\frac{{lim}_{{n}\rightarrow+\infty} {A}_{{n}} }{{lim}_{{n}\rightarrow+\infty\:\:} {B}_{{n}} }\:. \\ $$

Question Number 47852 Answers: 0 Comments: 1

1) find ∫ x arctan(x)dx 2) find the value of ∫_0 ^1 x arctan(x)dx

$$\left.\mathrm{1}\right)\:{find}\:\int\:{x}\:{arctan}\left({x}\right){dx} \\ $$$$\left.\mathrm{2}\right)\:{find}\:{the}\:{value}\:{of}\:\:\int_{\mathrm{0}} ^{\mathrm{1}} \:{x}\:{arctan}\left({x}\right){dx} \\ $$

Question Number 47851 Answers: 2 Comments: 3

let f(x)=x+1+(√x) and g(x)=x+1−(√x) find ∫ ((f(x))/(g(x)))dx and ((∫f(x)dx)/(∫g(x)dx)) .

$${let}\:\:{f}\left({x}\right)={x}+\mathrm{1}+\sqrt{{x}}\:{and}\:{g}\left({x}\right)={x}+\mathrm{1}−\sqrt{{x}} \\ $$$${find}\:\int\:\frac{{f}\left({x}\right)}{{g}\left({x}\right)}{dx}\:\:{and}\:\:\frac{\int{f}\left({x}\right){dx}}{\int{g}\left({x}\right){dx}}\:. \\ $$

Question Number 47848 Answers: 0 Comments: 2

A body ascends a slope with a speed of 10m/s.If 105J of energy of the body is lost due to friction then the height to which the body will rise is a)0.5m b)4.5m c)3.5m d)2.0m

$${A}\:{body}\:{ascends}\:{a}\:{slope}\:{with}\:{a} \\ $$$${speed}\:{of}\:\mathrm{10}{m}/{s}.{If}\:\mathrm{105}{J}\:{of}\:{energy} \\ $$$${of}\:{the}\:{body}\:{is}\:{lost}\:{due}\:{to}\:{friction}\: \\ $$$${then}\:{the}\:{height}\:{to}\:{which}\:{the}\:{body} \\ $$$${will}\:{rise}\:{is} \\ $$$$\left.{a}\left.\right)\left.\mathrm{0}\left..\mathrm{5}{m}\:\:\:{b}\right)\mathrm{4}.\mathrm{5}{m}\:\:\:{c}\right)\mathrm{3}.\mathrm{5}{m}\:\:\:{d}\right)\mathrm{2}.\mathrm{0}{m} \\ $$

Question Number 47837 Answers: 0 Comments: 0

there are 5 possible answers for each question of a multiple choice exam containing 10 questions. if a condidate answered it randomly. find the probability that he gets (i) no question right (ii) 3 questions right (iii) 5 questions right (iv) at least one question right

$${there}\:{are}\:\mathrm{5}\:{possible}\:{answers}\:{for}\:{each}\:{question}\:{of}\:{a}\: \\ $$$${multiple}\:{choice}\:{exam}\:{containing}\:\mathrm{10}\:{questions}.\: \\ $$$${if}\:{a}\:{condidate}\:{answered}\:{it}\:{randomly}.\: \\ $$$${find}\:{the}\:{probability}\:{that}\:{he}\:{gets}\:\left({i}\right)\:{no}\:{question}\:{right} \\ $$$$\:\left({ii}\right)\:\mathrm{3}\:{questions}\:{right}\:\left({iii}\right)\:\mathrm{5}\:{questions}\:{right}\: \\ $$$$\:\left({iv}\right)\:{at}\:{least}\:{one}\:{question}\:{right}\: \\ $$$$ \\ $$$$ \\ $$$$ \\ $$$$ \\ $$

Question Number 47836 Answers: 2 Comments: 0

prove cosec^2 θ−cotθcosecθ=1

$${prove}\:{cosec}^{\mathrm{2}} \theta−{cot}\theta{cosec}\theta=\mathrm{1} \\ $$

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