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Question Number 50279    Answers: 2   Comments: 0

{ ((x+y=6)),((y+z=10)) :} (x,y,z>0)

$$\begin{cases}{\mathrm{x}+\mathrm{y}=\mathrm{6}}\\{\mathrm{y}+\mathrm{z}=\mathrm{10}}\end{cases}\:\:\left(\mathrm{x},\mathrm{y},\mathrm{z}>\mathrm{0}\right) \\ $$

Question Number 50278    Answers: 1   Comments: 6

(√(a+(√(a−x)))) + (√(a−(√(a+x)))) = 2x please i beg u guys please solve this question

$$\sqrt{\mathrm{a}+\sqrt{\mathrm{a}−\mathrm{x}}}\:+\:\sqrt{\mathrm{a}−\sqrt{\mathrm{a}+\mathrm{x}}}\:=\:\mathrm{2x} \\ $$$$\mathrm{please}\:\mathrm{i}\:\mathrm{beg}\:\mathrm{u}\:\mathrm{guys}\: \\ $$$$\mathrm{please}\:\mathrm{solve}\:\mathrm{this}\:\mathrm{question} \\ $$

Question Number 50275    Answers: 1   Comments: 0

Question Number 50274    Answers: 2   Comments: 0

Question Number 50258    Answers: 1   Comments: 0

A delegation of 4 students is to be selected from a total of 12 students. In how many ways can the delegation be selected if: 1) 2 particular students wish to be included together only in the delegation? 2) 2 particular students refuse to be together and 2 other particular students wish to be together only in the delegation?

$${A}\:{delegation}\:{of}\:\mathrm{4}\:{students}\:{is}\:{to}\:{be} \\ $$$${selected}\:{from}\:{a}\:{total}\:{of}\:\mathrm{12}\:{students}. \\ $$$${In}\:{how}\:{many}\:{ways}\:{can}\:{the}\:{delegation} \\ $$$${be}\:{selected}\:{if}: \\ $$$$\left.\mathrm{1}\right)\:\mathrm{2}\:{particular}\:{students}\:{wish}\:{to}\:{be}\: \\ $$$${included}\:{together}\:{only}\:{in}\:{the}\:{delegation}? \\ $$$$\left.\mathrm{2}\right)\:\mathrm{2}\:{particular}\:{students}\:{refuse}\:{to}\:{be}\: \\ $$$${together}\:{and}\:\mathrm{2}\:{other}\:{particular}\:{students} \\ $$$${wish}\:{to}\:{be}\:{together}\:{only}\:{in}\:{the}\:{delegation}? \\ $$

Question Number 50257    Answers: 1   Comments: 0

Question Number 50248    Answers: 1   Comments: 0

Question Number 50228    Answers: 0   Comments: 3

Question Number 50226    Answers: 0   Comments: 1

Three prizes are awarded each for getting more than 80%marks, 98% attendance and good behaviour in the college.In how many ways the prozes can be awarded if 15 student of the college are eligible for the three prizes?

$$\mathrm{Three}\:\mathrm{prizes}\:\mathrm{are}\:\mathrm{awarded}\:\mathrm{each}\:\mathrm{for} \\ $$$$\mathrm{getting}\:\mathrm{more}\:\mathrm{than}\:\mathrm{80\%marks}, \\ $$$$\mathrm{98\%}\:\mathrm{attendance}\:\mathrm{and}\:\mathrm{good} \\ $$$$\mathrm{behaviour}\:\mathrm{in}\:\mathrm{the}\:\mathrm{college}.\mathrm{In}\:\mathrm{how} \\ $$$$\mathrm{many}\:\mathrm{ways}\:\mathrm{the}\:\mathrm{prozes}\:\mathrm{can}\:\mathrm{be} \\ $$$$\mathrm{awarded}\:\mathrm{if}\:\mathrm{15}\:\mathrm{student}\:\mathrm{of}\:\mathrm{the}\:\mathrm{college} \\ $$$$\mathrm{are}\:\mathrm{eligible}\:\mathrm{for}\:\mathrm{the}\:\mathrm{three}\:\mathrm{prizes}? \\ $$

Question Number 50220    Answers: 0   Comments: 4

Question Number 50219    Answers: 7   Comments: 0

Question Number 50423    Answers: 1   Comments: 1

find f(a) =∫_a ^(+∞) (dx/((1+x^2 )(√(x^2 −a^2 )))) with a>0

$${find}\:{f}\left({a}\right)\:=\int_{{a}} ^{+\infty} \:\:\:\frac{{dx}}{\left(\mathrm{1}+{x}^{\mathrm{2}} \right)\sqrt{{x}^{\mathrm{2}} −{a}^{\mathrm{2}} }}\:\:{with}\:{a}>\mathrm{0} \\ $$

Question Number 50209    Answers: 1   Comments: 0

The gcf and lcm of three numbers are 2 and 1200 respectively. if the two numbers are 16 and 24, find the third number

$$\boldsymbol{\mathrm{The}}\:\boldsymbol{\mathrm{gcf}}\:\boldsymbol{\mathrm{and}}\:\boldsymbol{\mathrm{lcm}}\:\boldsymbol{\mathrm{of}}\:\boldsymbol{\mathrm{three}}\:\boldsymbol{\mathrm{numbers}} \\ $$$$\boldsymbol{\mathrm{are}}\:\mathrm{2}\:\boldsymbol{\mathrm{and}}\:\mathrm{1200}\:\boldsymbol{\mathrm{respectively}}. \\ $$$$\boldsymbol{\mathrm{if}}\:\boldsymbol{\mathrm{the}}\:\boldsymbol{\mathrm{two}}\:\boldsymbol{\mathrm{numbers}}\:\boldsymbol{\mathrm{are}}\:\mathrm{16}\:\boldsymbol{\mathrm{and}}\:\mathrm{24}, \\ $$$$\boldsymbol{\mathrm{find}}\:\boldsymbol{\mathrm{the}}\:\boldsymbol{\mathrm{third}}\:\boldsymbol{\mathrm{number}} \\ $$

Question Number 50201    Answers: 0   Comments: 2

a=665,21 b=47,14

$$\mathrm{a}=\mathrm{665},\mathrm{21}\:\:\:\:\:\:\:\mathrm{b}=\mathrm{47},\mathrm{14} \\ $$

Question Number 50198    Answers: 0   Comments: 1

Question Number 50197    Answers: 0   Comments: 0

plz plz help me sir

$$\mathrm{plz}\:\mathrm{plz}\:\mathrm{help}\:\mathrm{me}\:\mathrm{sir} \\ $$

Question Number 50196    Answers: 0   Comments: 0

Question Number 50195    Answers: 0   Comments: 0

Question Number 50194    Answers: 0   Comments: 2

Question Number 50349    Answers: 0   Comments: 0

Question Number 50200    Answers: 0   Comments: 2

Question Number 50239    Answers: 1   Comments: 1

Question Number 50186    Answers: 1   Comments: 0

Let f(x)= ∫_2 ^( x) (dt/(1+t^6 )). Prove that : (1/(730))<f(3)<(1/(65)).

$${Let}\:{f}\left({x}\right)=\:\int_{\mathrm{2}} ^{\:{x}} \:\frac{{dt}}{\mathrm{1}+{t}^{\mathrm{6}} }. \\ $$$${Prove}\:{that}\:\::\:\frac{\mathrm{1}}{\mathrm{730}}<{f}\left(\mathrm{3}\right)<\frac{\mathrm{1}}{\mathrm{65}}. \\ $$

Question Number 50175    Answers: 1   Comments: 0

Question Number 50171    Answers: 0   Comments: 3

Sir l′m sorry l dont understand you

$$\mathrm{Sir}\:\mathrm{l}'\mathrm{m}\:\mathrm{sorry}\:\mathrm{l}\:\mathrm{dont}\:\mathrm{understand}\: \\ $$$$\mathrm{you} \\ $$

Question Number 50163    Answers: 2   Comments: 0

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