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AllQuestion and Answers: Page 158

Question Number 205289 Answers: 0 Comments: 0

Question Number 205288 Answers: 0 Comments: 0

Question Number 205284 Answers: 0 Comments: 0

Question Number 205297 Answers: 2 Comments: 0

Find the′′ range ′′ of : i : f (x) =⌊ (( x)/( ⌊ x ⌋)) ⌋ ii: f(x) = (( x)/(⌊ x ⌋ + ⌊ −x ⌋))

$$ \\ $$$$\:\:\:{Find}\:\:{the}''\:{range}\:''\:{of}\:\:: \\ $$$$ \\ $$$$\:\:\:{i}\::\:\:\:{f}\:\left({x}\right)\:=\lfloor\:\frac{\:{x}}{\:\lfloor\:{x}\:\rfloor}\:\rfloor \\ $$$$\:\:\:{ii}:\:{f}\left({x}\right)\:=\:\frac{\:{x}}{\lfloor\:{x}\:\rfloor\:+\:\lfloor\:−{x}\:\rfloor} \\ $$$$\:\: \\ $$

Question Number 205280 Answers: 0 Comments: 1

Question Number 205279 Answers: 1 Comments: 0

∫^(π/2) _(-π/2) ((8(√2)cosx)/((1+e^(sinx) )(1+sin^4 x)))dx=aπ+blog(3+2(√2)) then find a+b

$$\underset{-\pi/\mathrm{2}} {\int}^{\pi/\mathrm{2}} \frac{\mathrm{8}\sqrt{\mathrm{2}}{cosx}}{\left(\mathrm{1}+\overset{{sinx}} {{e}}\right)\left(\mathrm{1}+{si}\overset{\mathrm{4}} {{n}x}\right)}{dx}={a}\pi+{blog}\left(\mathrm{3}+\mathrm{2}\sqrt{\mathrm{2}}\right)\:{then}\:{find}\:{a}+{b} \\ $$

Question Number 205273 Answers: 3 Comments: 0

If f(x−1)=2x+2 Find f(x)=?

$$\mathrm{If}\:\:\:\mathrm{f}\left(\mathrm{x}−\mathrm{1}\right)=\mathrm{2x}+\mathrm{2} \\ $$$$\mathrm{Find}\:\:\:\mathrm{f}\left(\mathrm{x}\right)=? \\ $$

Question Number 205269 Answers: 2 Comments: 0

Question Number 205264 Answers: 1 Comments: 0

pls how to calculate this? ∫_(1/2) ^1 ((ln(x+1))/x)dx

$$\boldsymbol{{pls}}\:\boldsymbol{{how}}\:\boldsymbol{{to}}\:\boldsymbol{{calculate}}\:\boldsymbol{{this}}? \\ $$$$\int_{\frac{\mathrm{1}}{\mathrm{2}}} ^{\mathrm{1}} \frac{\boldsymbol{{ln}}\left(\boldsymbol{{x}}+\mathrm{1}\right)}{\boldsymbol{{x}}}\boldsymbol{{dx}} \\ $$

Question Number 205262 Answers: 1 Comments: 0

nature of the serie Σ_(n≥1) ((ln(n))/n)

$${nature}\:{of}\:{the}\:{serie}\:\sum_{{n}\geqslant\mathrm{1}} \:\frac{{ln}\left({n}\right)}{{n}} \\ $$

Question Number 205256 Answers: 2 Comments: 2

Find: lim_(x→0) ((1/x)) = ?

$$\mathrm{Find}:\:\:\:\underset{\boldsymbol{\mathrm{x}}\rightarrow\mathrm{0}} {\mathrm{lim}}\:\left(\frac{\mathrm{1}}{\mathrm{x}}\right)\:=\:? \\ $$

Question Number 205248 Answers: 1 Comments: 0

∫_0 ^π ((x^2 cos^2 (x)−xsin(x)−cos(x)−1)/((1+xsin(x))^2 ))dx

$$\:\:\:\int_{\mathrm{0}} ^{\pi} \:\frac{{x}^{\mathrm{2}} \mathrm{cos}^{\mathrm{2}} \left({x}\right)−{x}\mathrm{sin}\left({x}\right)−\mathrm{cos}\left({x}\right)−\mathrm{1}}{\left(\mathrm{1}+{x}\mathrm{sin}\left({x}\right)\right)^{\mathrm{2}} }{dx} \\ $$

Question Number 205361 Answers: 1 Comments: 0

Question Number 205245 Answers: 1 Comments: 0

calculate ∫((3xdx)/( (√(1−x^4 )))) plsssssss

$$\boldsymbol{{calculate}} \\ $$$$\:\:\: \\ $$$$\int\frac{\mathrm{3}\boldsymbol{{xdx}}}{\:\sqrt{\mathrm{1}−\boldsymbol{{x}}^{\mathrm{4}} }} \\ $$$$\boldsymbol{{plsssssss}} \\ $$

Question Number 207920 Answers: 2 Comments: 2

Given p,q ,r and s real positive numbers such that { ((p^2 +q^2 = r^2 +s^2 )),((p^2 +s^2 −ps = q^2 +r^2 +qr.)) :} Find ((pq+rs)/(ps+qr)) .

$$\:\:\:\:\mathrm{Given}\:\mathrm{p},\mathrm{q}\:,\mathrm{r}\:\mathrm{and}\:\mathrm{s}\:\mathrm{real}\:\mathrm{positive}\: \\ $$$$\:\:\mathrm{numbers}\:\mathrm{such}\:\mathrm{that}\: \\ $$$$\:\:\:\:\begin{cases}{\mathrm{p}^{\mathrm{2}} +\mathrm{q}^{\mathrm{2}} =\:\mathrm{r}^{\mathrm{2}} +\mathrm{s}^{\mathrm{2}} }\\{\mathrm{p}^{\mathrm{2}} +\mathrm{s}^{\mathrm{2}} −\mathrm{ps}\:=\:\mathrm{q}^{\mathrm{2}} +\mathrm{r}^{\mathrm{2}} +\mathrm{qr}.}\end{cases} \\ $$$$\:\:\mathrm{Find}\:\:\frac{\mathrm{pq}+\mathrm{rs}}{\mathrm{ps}+\mathrm{qr}}\:. \\ $$

Question Number 205238 Answers: 1 Comments: 1

4^x + x = 260 find the possible values of x

$$\mathrm{4}^{{x}} \:+\:{x}\:=\:\mathrm{260} \\ $$$${find}\:{the}\:{possible}\:{values}\:{of}\:{x} \\ $$$$ \\ $$

Question Number 205237 Answers: 1 Comments: 0

Question Number 205230 Answers: 0 Comments: 1

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Question Number 205227 Answers: 1 Comments: 2

Question Number 205220 Answers: 2 Comments: 0

cos^4 x − sin^4 x = cos^2 x ⇒ x = ?

$$\mathrm{cos}^{\mathrm{4}} \:\mathrm{x}\:−\:\mathrm{sin}^{\mathrm{4}} \:\mathrm{x}\:=\:\mathrm{cos}^{\mathrm{2}} \:\mathrm{x} \\ $$$$\Rightarrow\:\mathrm{x}\:=\:? \\ $$

Question Number 205219 Answers: 2 Comments: 0

{ ((sinx + cosx = 1)),((sinx − cosy = 1)) :} ⇒ x = ?

$$\begin{cases}{\mathrm{sinx}\:+\:\mathrm{cosx}\:=\:\mathrm{1}}\\{\mathrm{sinx}\:−\:\mathrm{cosy}\:=\:\mathrm{1}}\end{cases} \\ $$$$\Rightarrow\:\mathrm{x}\:=\:? \\ $$

Question Number 205218 Answers: 1 Comments: 0

∣ sinx∣ + ∣ cosx ∣ = 1 ⇒ x = ?

$$\mid\:\mathrm{sinx}\mid\:+\:\mid\:\mathrm{cosx}\:\mid\:=\:\mathrm{1} \\ $$$$\Rightarrow\:\mathrm{x}\:=\:? \\ $$

Question Number 205217 Answers: 1 Comments: 0

4 sin (x/2) ∙ cos (x/2) = 1 ⇒ x = ?

$$\mathrm{4}\:\mathrm{sin}\:\frac{\mathrm{x}}{\mathrm{2}}\:\centerdot\:\mathrm{cos}\:\frac{\mathrm{x}}{\mathrm{2}}\:=\:\mathrm{1} \\ $$$$\Rightarrow\:\mathrm{x}\:=\:? \\ $$

Question Number 205211 Answers: 1 Comments: 0

Question Number 205216 Answers: 0 Comments: 0

∫ ((arccos^3 x)/( (√(1−x^3 )))) dx =?

$$\:\:\:\:\:\int\:\frac{\mathrm{arccos}\:^{\mathrm{3}} \mathrm{x}}{\:\sqrt{\mathrm{1}−\mathrm{x}^{\mathrm{3}} }}\:\mathrm{dx}\:=? \\ $$

Question Number 205203 Answers: 0 Comments: 0

If x,y,z>0 then in △ABC holds: Σ ((yz)/h_a ^2 ) ≤ (R^2 /(4F^2 )) (x + y + z)^2

$$\mathrm{If}\:\:\:\mathrm{x},\mathrm{y},\mathrm{z}>\mathrm{0}\:\:\:\mathrm{then}\:\mathrm{in}\:\:\:\bigtriangleup\mathrm{ABC}\:\:\:\mathrm{holds}: \\ $$$$\Sigma\:\:\frac{\mathrm{yz}}{\mathrm{h}_{\boldsymbol{\mathrm{a}}} ^{\mathrm{2}} }\:\:\leqslant\:\:\frac{\mathrm{R}^{\mathrm{2}} }{\mathrm{4F}^{\mathrm{2}} }\:\:\left(\mathrm{x}\:+\:\mathrm{y}\:+\:\mathrm{z}\right)^{\mathrm{2}} \\ $$

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