Question and Answers Forum

All Questions Topic List

AllQuestion and Answers: Page 1570

Question Number 52268 Answers: 0 Comments: 3

Question Number 52261 Answers: 0 Comments: 9

Question Number 52258 Answers: 0 Comments: 1

Question Number 52240 Answers: 0 Comments: 1

i=what in complex number.

$${i}={what}\:{in}\:{complex}\:{number}. \\ $$

Question Number 52233 Answers: 3 Comments: 0

please can you help me with this caculus: ∫(1/(cos^2 x)) dx

$${please}\:{can}\:{you}\:{help}\:{me}\:{with}\:{this}\: \\ $$$${caculus}:\:\int\frac{\mathrm{1}}{{cos}^{\mathrm{2}} {x}}\:{dx} \\ $$

Question Number 52223 Answers: 1 Comments: 2

Question Number 52222 Answers: 1 Comments: 0

Question Number 52221 Answers: 0 Comments: 0

a_n =(√(a_(n−1) +a_(n−2) )) a_1 =1 a_2 =3 find explisit to a_n

$${a}_{{n}} =\sqrt{{a}_{{n}−\mathrm{1}} +{a}_{{n}−\mathrm{2}} } \\ $$$${a}_{\mathrm{1}} =\mathrm{1} \\ $$$${a}_{\mathrm{2}} =\mathrm{3} \\ $$$$\mathrm{find}\:\mathrm{explisit}\:\mathrm{to}\:{a}_{{n}} \\ $$

Question Number 52206 Answers: 0 Comments: 1

lim_(x→0) (((1+x)^(1/x) −c)/x)=−(c/2)

$$\underset{{x}\rightarrow\mathrm{0}} {\mathrm{lim}}\frac{\left(\mathrm{1}+{x}\right)^{\mathrm{1}/{x}} −{c}}{{x}}=−\frac{{c}}{\mathrm{2}} \\ $$

Question Number 52208 Answers: 1 Comments: 3

Question Number 52214 Answers: 2 Comments: 4

Question Number 52200 Answers: 0 Comments: 0

proof that (√z^2 ) ≠ z , z ∈ C example i=(√(−1)) i^2 =−1 i^4 =1 (√(i^4 )) ≠ i^2 (√1) ≠ −1 1 ≠ −1

$$\mathrm{proof}\:\mathrm{that}\: \\ $$$$\sqrt{{z}^{\mathrm{2}} }\:\neq\:{z}\:,\:{z}\:\in\:\mathbb{C} \\ $$$$\mathrm{example} \\ $$$${i}=\sqrt{−\mathrm{1}} \\ $$$${i}^{\mathrm{2}} =−\mathrm{1} \\ $$$${i}^{\mathrm{4}} =\mathrm{1} \\ $$$$\sqrt{{i}^{\mathrm{4}} \:}\:\neq\:{i}^{\mathrm{2}} \\ $$$$\sqrt{\mathrm{1}}\:\neq\:−\mathrm{1} \\ $$$$\mathrm{1}\:\neq\:−\mathrm{1} \\ $$$$ \\ $$

Question Number 52198 Answers: 2 Comments: 0

Question Number 52197 Answers: 1 Comments: 0

calculate ∫_(π/4) ^(π/3) ((cosx −sinx)/(2 +sin(2x)))dx

$${calculate}\:\int_{\frac{\pi}{\mathrm{4}}} ^{\frac{\pi}{\mathrm{3}}} \:\frac{{cosx}\:−{sinx}}{\mathrm{2}\:+{sin}\left(\mathrm{2}{x}\right)}{dx} \\ $$$$ \\ $$

Question Number 52182 Answers: 0 Comments: 1

Question Number 52190 Answers: 2 Comments: 3

Question Number 52164 Answers: 2 Comments: 4

find: ∫_0 ^Π (cos^6 θ −cos^4 θ) dθ plase help me in cinding this And also explain if possible

$${find}: \\ $$$$\underset{\mathrm{0}} {\overset{\Pi} {\int}}\left({cos}^{\mathrm{6}} \theta\:−\mathrm{cos}\:^{\mathrm{4}} \theta\right)\:{d}\theta \\ $$$${plase}\:{help}\:{me}\:{in}\:{cinding}\:{this}\:{And}\:{also} \\ $$$${explain}\:{if}\:{possible} \\ $$

Question Number 52161 Answers: 2 Comments: 7

Question Number 52129 Answers: 1 Comments: 5

Question Number 52124 Answers: 1 Comments: 0

The curve y = ax + (b/(2x− 1)) has the stationary point at (2, 7) . Find the value of a and b .

$$\mathrm{The}\:\mathrm{curve}\:\mathrm{y}\:=\:\mathrm{ax}\:+\:\frac{\mathrm{b}}{\mathrm{2x}−\:\mathrm{1}}\:\mathrm{has}\:\mathrm{the}\:\mathrm{stationary}\:\mathrm{point}\:\mathrm{at}\:\:\left(\mathrm{2},\:\mathrm{7}\right)\:.\:\mathrm{Find}\:\mathrm{the}\:\mathrm{value}\:\mathrm{of}\:\mathrm{a}\:\mathrm{and}\:\mathrm{b}\:. \\ $$

Question Number 52123 Answers: 1 Comments: 1

Find lim_(x→∞) ((sin x)/x).

$$\mathrm{Find}\:\:\underset{{x}\rightarrow\infty} {\mathrm{lim}}\frac{\mathrm{sin}\:\mathrm{x}}{\mathrm{x}}. \\ $$

Question Number 52108 Answers: 1 Comments: 0

Question Number 52103 Answers: 2 Comments: 0

((×−0.1)/(×+0.1))=((1.2)/(1.7)) Sir plz help me

$$\frac{×−\mathrm{0}.\mathrm{1}}{×+\mathrm{0}.\mathrm{1}}=\frac{\mathrm{1}.\mathrm{2}}{\mathrm{1}.\mathrm{7}}\:\:\:\:\:\:\:\:\:\:\mathrm{Sir}\:\mathrm{plz}\:\mathrm{help}\:\mathrm{me} \\ $$

Question Number 52099 Answers: 1 Comments: 1

Question Number 52091 Answers: 2 Comments: 1

3^x +4^x =5^x find x BY ISHOLA

$$\mathrm{3}^{{x}} +\mathrm{4}^{{x}} =\mathrm{5}^{{x}} \\ $$$${find}\:{x} \\ $$$${BY}\:{ISHOLA} \\ $$

Question Number 52089 Answers: 0 Comments: 0

Pg 1565 Pg 1566 Pg 1567 Pg 1568 Pg 1569 Pg 1570 Pg 1571 Pg 1572 Pg 1573 Pg 1574

Contact: info@tinkutara.com