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Question Number 53901 Answers: 1 Comments: 0
Question Number 53890 Answers: 1 Comments: 0
$$\mathrm{pls}.\:\mathrm{help}\:\mathrm{me}\:\mathrm{solve}\:\mathrm{this} \\ $$$$\mathrm{if}\:\mathrm{y}=\frac{\mathrm{x}−\mathrm{2}}{\mathrm{2x}−\mathrm{1}}\:\mathrm{show}\:\mathrm{that}\:\left(\mathrm{2x}−\mathrm{1}\right)\frac{\mathrm{d}^{\mathrm{2}} \mathrm{y}}{\mathrm{dx}^{\mathrm{2}} }+\mathrm{4}\frac{\mathrm{dy}}{\mathrm{dx}}=\mathrm{0} \\ $$
Question Number 53881 Answers: 0 Comments: 2
Question Number 53894 Answers: 2 Comments: 0
$$\underset{\pi/\mathrm{6}} {\overset{\mathrm{5}\pi/\mathrm{6}} {\int}}\sqrt{\mathrm{4}−\mathrm{4}\:\mathrm{sin}^{\mathrm{2}} {t}}\:{dt}\:= \\ $$
Question Number 53867 Answers: 1 Comments: 0
Question Number 53852 Answers: 0 Comments: 0
$${G}_{\mu\nu} =\:{R}_{\mu\nu} −\:\frac{\mathrm{1}}{\mathrm{2}}\:{Rg}_{\mu\nu} \:+\:\boldsymbol{\Lambda}{g}_{\mu\nu} \\ $$$$\mathrm{Wich}\:\mathrm{theory}\:\mathrm{of}\:\mathrm{modern}\:\mathrm{physic}\:\mathrm{belongs}\:\mathrm{this}\:\mathrm{equation}? \\ $$$$\mathrm{and}\:\mathrm{what}\:\mathrm{does}\:\mathrm{it}\:\mathrm{mean}? \\ $$
Question Number 53843 Answers: 1 Comments: 0
Question Number 53842 Answers: 0 Comments: 0
$$\mathrm{Find}\:\mathrm{all}\:\mathrm{the}\:\mathrm{real}\:\mathrm{valued}\:\:\mathrm{f}\:\:\mathrm{satisfying}\: \\ $$$$\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\mathrm{f}\left[\mathrm{2x}\:+\:\mathrm{f}\left(\mathrm{2y}\right)\right]\:+\:\mathrm{f}\left[\mathrm{f}\left(\mathrm{y}\right)\right]\:\:=\:\:\mathrm{4x}\:+\:\mathrm{8y} \\ $$$$\mathrm{for}\:\mathrm{all}\:\mathrm{real}\:\mathrm{numbers}\:\:\mathrm{x}\:\mathrm{and}\:\mathrm{y}.\: \\ $$
Question Number 53841 Answers: 0 Comments: 8
Question Number 53839 Answers: 0 Comments: 4
Question Number 53828 Answers: 1 Comments: 1
Question Number 53827 Answers: 1 Comments: 0
$$\mathrm{5}×\mathrm{6}^{{x}} −\mathrm{3}×\mathrm{4}^{{x}} =\:\mathrm{2}×\mathrm{9}^{{x}} \\ $$$$ \\ $$$${I}\:{need}\:{an}\:{explanation}. \\ $$
Question Number 53824 Answers: 2 Comments: 1
Question Number 53877 Answers: 2 Comments: 1
$$\mathrm{2}×\mathrm{4}^{{x}+\mathrm{2}} −\mathrm{5}×\mathrm{4}^{{x}+\mathrm{1}} −\mathrm{3}×\mathrm{2}^{\mathrm{2}{x}+\mathrm{1}} −\mathrm{4}^{{x}} =\:\mathrm{20} \\ $$
Question Number 53814 Answers: 0 Comments: 0
Question Number 53813 Answers: 0 Comments: 0
Question Number 53811 Answers: 1 Comments: 1
Question Number 53805 Answers: 1 Comments: 4
Question Number 53795 Answers: 1 Comments: 1
$${calculate}\:\sum_{{n}=\mathrm{0}} ^{\infty} \:\:\frac{\left(−\mathrm{1}\right)^{{n}} }{\mathrm{4}{n}+\mathrm{1}}\:=\mathrm{1}−\frac{\mathrm{1}}{\mathrm{5}}\:+\frac{\mathrm{1}}{\mathrm{9}}\:−\frac{\mathrm{1}}{\mathrm{13}}\:+.... \\ $$
Question Number 53792 Answers: 0 Comments: 3
Question Number 53785 Answers: 0 Comments: 1
$${let}\:{f}\left({x}\right)=\int_{\mathrm{0}} ^{\infty} \:\frac{{tsin}\left({tx}\right)}{\mathrm{1}+{t}^{\mathrm{4}} }{dt}\:\:{with}\:{x}>\mathrm{0} \\ $$$$\left.\mathrm{1}\right)\:{find}\:{a}\:{explicit}\:{form}\:{of}\:{f}\left({x}\right) \\ $$$$\left.\mathrm{2}\right)\:{find}\:{the}\:{value}\:{of}\:\int_{\mathrm{0}} ^{\infty} \:\:\frac{{tsin}\left(\mathrm{2}{t}\right)}{\mathrm{1}+{t}^{\mathrm{4}} }{dt}. \\ $$
Question Number 53783 Answers: 1 Comments: 0
$${calculate}\:\int_{\mathrm{0}} ^{\infty} \:\frac{{t}^{\mathrm{2}} }{{e}^{{t}} −\mathrm{1}}{dt}\:{interms}\:{of}\:\xi\left(\mathrm{3}\right) \\ $$
Question Number 53782 Answers: 1 Comments: 0
$${calculate}\:\int_{\mathrm{0}} ^{\mathrm{1}} \:\:\frac{{t}^{\mathrm{2}} }{\mathrm{1}+{t}^{\mathrm{3}} }{dt} \\ $$
Question Number 53781 Answers: 1 Comments: 1
$${calculateA}_{{n}} =\sum_{{n}=\mathrm{1}} ^{\infty} \:{x}^{{n}} {cos}\left({n}\theta\right)\:\:{and}\:{B}_{{n}} =\sum_{{n}=\mathrm{1}} ^{\infty} \:{x}^{{n}} {sin}\left({n}\theta\right) \\ $$
Question Number 53780 Answers: 0 Comments: 0
$${find}\:{nature}\:{of}\:{the}\:{serie}\:\Sigma{sin}\left(\pi{en}!\right) \\ $$
Question Number 53779 Answers: 0 Comments: 0
$$\Sigma\:{u}_{{n}} {is}\:{a}\:{convergent}\:{serie}\:\left({u}_{{n}} >\mathrm{0}\right)\:\:{find}\:{nature}\:{of}\:{the}\:{serie} \\ $$$$\left.\mathrm{1}\right)\:\Sigma\:\frac{\sqrt{{u}_{{n}} }}{{n}} \\ $$$$\left.\mathrm{2}\right)\Sigma\:\:\frac{{u}_{{n}} }{\mathrm{1}+{u}_{{n}} } \\ $$
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