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AllQuestion and Answers: Page 1559

Question Number 54248 Answers: 2 Comments: 1

Question Number 54242 Answers: 2 Comments: 0

Question Number 54240 Answers: 1 Comments: 1

Question Number 54239 Answers: 1 Comments: 0

Question Number 54229 Answers: 1 Comments: 1

Question Number 54226 Answers: 0 Comments: 4

Question Number 54224 Answers: 2 Comments: 4

∫_0 ^( (π/4)) ((sinx+cosx)/(16+9sin2x)) dx =?

$$\int_{\mathrm{0}} ^{\:\frac{\pi}{\mathrm{4}}} \frac{\mathrm{sin}{x}+\mathrm{cos}{x}}{\mathrm{16}+\mathrm{9sin2}{x}}\:{dx}\:=? \\ $$

Question Number 54219 Answers: 1 Comments: 0

tan^6 (π/9)−33 tan^4 (π/9)+27tan^2 (π/9) =

$$\mathrm{tan}^{\mathrm{6}} \:\frac{\pi}{\mathrm{9}}−\mathrm{33}\:\mathrm{tan}^{\mathrm{4}} \frac{\pi}{\mathrm{9}}+\mathrm{27tan}^{\mathrm{2}} \:\frac{\pi}{\mathrm{9}}\:=\: \\ $$

Question Number 54209 Answers: 2 Comments: 0

Question Number 54206 Answers: 1 Comments: 2

Question Number 54194 Answers: 1 Comments: 1

Question Number 54199 Answers: 0 Comments: 0

pls. am a new comer and i want to know how to draw diagrams especially moments of force.

$$\mathrm{pls}.\:\mathrm{am}\:\mathrm{a}\:\mathrm{new}\:\mathrm{comer}\:\mathrm{and}\:\mathrm{i}\:\mathrm{want}\:\mathrm{to}\: \\ $$$$\mathrm{know}\:\mathrm{how}\:\mathrm{to}\:\mathrm{draw}\:\mathrm{diagrams}\:\mathrm{especially}\:\mathrm{moments}\:\mathrm{of} \\ $$$$\mathrm{force}. \\ $$

Question Number 54176 Answers: 0 Comments: 0

what is the integral vslue of ∫x!dx

$${what}\:{is}\:{the}\:{integral}\:{vslue}\:{of}\:\int{x}!{dx} \\ $$

Question Number 54170 Answers: 1 Comments: 1

Question Number 54167 Answers: 1 Comments: 2

Question Number 54163 Answers: 0 Comments: 1

Question Number 54160 Answers: 1 Comments: 1

Question Number 54156 Answers: 0 Comments: 1

Please sirs, How is, − cot(α) = tan((1/2)π + α) ????

$$\mathrm{Please}\:\mathrm{sirs},\:\:\mathrm{How}\:\mathrm{is},\:\:\:\:\:\:−\:\mathrm{cot}\left(\alpha\right)\:\:=\:\:\mathrm{tan}\left(\frac{\mathrm{1}}{\mathrm{2}}\pi\:+\:\alpha\right)\:\:???? \\ $$

Question Number 54152 Answers: 0 Comments: 3

Question Number 54137 Answers: 1 Comments: 2

Question Number 54126 Answers: 1 Comments: 0

Prove that ((sin 19θ)/(sin θ)) = cos(−18θ)+cos(−16θ)+... ...+ cos(−2θ)+1+cos(2θ)+....+cos(18θ).

$${Prove}\:{that} \\ $$$$\frac{\mathrm{sin}\:\mathrm{19}\theta}{\mathrm{sin}\:\theta}\:=\:\mathrm{cos}\left(−\mathrm{18}\theta\right)+\mathrm{cos}\left(−\mathrm{16}\theta\right)+... \\ $$$$\:\:\:...+\:\mathrm{cos}\left(−\mathrm{2}\theta\right)+\mathrm{1}+\mathrm{cos}\left(\mathrm{2}\theta\right)+....+\mathrm{cos}\left(\mathrm{18}\theta\right). \\ $$

Question Number 54116 Answers: 0 Comments: 0

Question Number 54102 Answers: 1 Comments: 3

the absolute value ∫_(10) ^(19) ((cos x)/(1+x^8 )) dx is...

$$\mathrm{the}\:\mathrm{absolute}\:\mathrm{value} \\ $$$$\int_{\mathrm{10}} ^{\mathrm{19}} \frac{\mathrm{cos}\:{x}}{\mathrm{1}+{x}^{\mathrm{8}} }\:{dx}\:\mathrm{is}... \\ $$

Question Number 54093 Answers: 0 Comments: 8

If tan(z) = 2, find the value of z

$$\mathrm{If}\:\:\:\:\:\:\mathrm{tan}\left(\mathrm{z}\right)\:\:=\:\:\mathrm{2},\:\:\:\:\mathrm{find}\:\mathrm{the}\:\mathrm{value}\:\mathrm{of}\:\:\mathrm{z} \\ $$

Question Number 54074 Answers: 1 Comments: 5

Evaluate : 1) ∫_0 ^( 1) (dx/((√(1+x))+(√(1−x))+2)) 2) ∫_0 ^( 2) ((ln(1+2x))/(1+x^2 )) 3) ∫_0 ^( π) (x/(√(1+sin^3 x)))((3πcosx+4sinx)sin^2 x+4)dx 4) ∫_0 ^( π) ((x^2 cos^2 x−xsinx−cosx−1)/((1+xsinx)^2 )) dx.

$${Evaluate}\:: \\ $$$$\left.\mathrm{1}\right)\:\:\:\:\:\:\int_{\mathrm{0}} ^{\:\mathrm{1}} \frac{{dx}}{\sqrt{\mathrm{1}+{x}}+\sqrt{\mathrm{1}−{x}}+\mathrm{2}}\: \\ $$$$ \\ $$$$\left.\mathrm{2}\right)\:\:\:\:\:\int_{\mathrm{0}} ^{\:\mathrm{2}} \frac{{ln}\left(\mathrm{1}+\mathrm{2}{x}\right)}{\mathrm{1}+{x}^{\mathrm{2}} } \\ $$$$\left.\mathrm{3}\right) \\ $$$$\:\int_{\mathrm{0}} ^{\:\pi} \frac{{x}}{\sqrt{\mathrm{1}+\mathrm{sin}^{\mathrm{3}} {x}}}\left(\left(\mathrm{3}\pi\mathrm{cos}{x}+\mathrm{4sin}{x}\right)\mathrm{sin}^{\mathrm{2}} {x}+\mathrm{4}\right){dx} \\ $$$$\left.\mathrm{4}\right) \\ $$$$\int_{\mathrm{0}} ^{\:\pi} \:\frac{{x}^{\mathrm{2}} \mathrm{cos}^{\mathrm{2}} {x}−{x}\mathrm{sin}{x}−\mathrm{cos}{x}−\mathrm{1}}{\left(\mathrm{1}+{x}\mathrm{sin}{x}\right)^{\mathrm{2}} }\:{dx}. \\ $$

Question Number 54073 Answers: 1 Comments: 0

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