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Question Number 48443 Answers: 1 Comments: 3
$${Coefficient}\:{of}\:{x}^{\mathrm{4}} \:{in}\:\left(\mathrm{2}−{x}+\mathrm{3}{x}^{\mathrm{2}} \right)^{\mathrm{6}} =? \\ $$
Question Number 48435 Answers: 1 Comments: 0
$$\frac{\mathrm{2}}{\mathrm{11}}×−\frac{\mathrm{5}}{\mathrm{18}}{y}−\mathrm{1}\frac{\mathrm{13}}{\mathrm{22}}×+\frac{\mathrm{5}}{\mathrm{6}}{y}\:\:\:\: \\ $$$${sir}\:{could}\:{you}\:{help}\:{me}? \\ $$
Question Number 48434 Answers: 2 Comments: 0
Question Number 48433 Answers: 1 Comments: 0
$$\frac{\mathrm{7}}{\mathrm{9}}/\mathrm{3}.\mathrm{1}=×/\mathrm{9}.\mathrm{3}\:\:\:\:{sir}\:{plz}\:{help}\:{me} \\ $$$$ \\ $$
Question Number 48426 Answers: 0 Comments: 4
Question Number 48405 Answers: 0 Comments: 7
Question Number 48396 Answers: 2 Comments: 2
Question Number 48388 Answers: 2 Comments: 1
Question Number 48384 Answers: 1 Comments: 1
Question Number 48374 Answers: 0 Comments: 0
Question Number 48368 Answers: 1 Comments: 0
Question Number 48367 Answers: 2 Comments: 0
Question Number 48366 Answers: 0 Comments: 3
Question Number 48361 Answers: 1 Comments: 1
$$\mathrm{Solve}\:\mathrm{the}\:\mathrm{equation} \\ $$$$\mathrm{cos}^{−\mathrm{1}} \mathrm{x}+\mathrm{cos}^{−\mathrm{1}} \left(\frac{\mathrm{x}}{\mathrm{2}}+\frac{\sqrt{\mathrm{3}−\mathrm{3x}^{\mathrm{2}} }}{\mathrm{2}}\right)=\frac{\pi}{\mathrm{3}} \\ $$
Question Number 48360 Answers: 2 Comments: 1
$${calculate}\:{cos}^{\mathrm{4}} \left(\frac{\pi}{\mathrm{8}}\right)+{cos}^{\mathrm{4}} \left(\frac{\mathrm{3}\pi}{\mathrm{8}}\right)\:+{cos}^{\mathrm{4}} \left(\frac{\mathrm{5}\pi}{\mathrm{8}}\right)\:+{cos}^{\mathrm{4}} \left(\frac{\mathrm{7}\pi}{\mathrm{8}}\right) \\ $$
Question Number 48359 Answers: 2 Comments: 0
Question Number 48341 Answers: 0 Comments: 0
Question Number 48338 Answers: 0 Comments: 6
Question Number 48324 Answers: 0 Comments: 6
Question Number 48322 Answers: 0 Comments: 0
Question Number 48321 Answers: 0 Comments: 1
Question Number 48310 Answers: 1 Comments: 0
Question Number 48307 Answers: 0 Comments: 2
$${f}\left({x}\right)={x}^{{x}^{{x}−\mathrm{1}} } \:\:\:\:\:\left[={x}^{\left({x}^{{x}−\mathrm{1}} \right)} \right] \\ $$$$\mathrm{it}'\mathrm{s}\:\mathrm{a}\:\mathrm{funny}\:\mathrm{one}... \\ $$$${f}\left(\mathrm{1}\right)=\mathrm{1} \\ $$$${f}\left(\mathrm{2}\right)=\mathrm{2}^{\mathrm{2}} \\ $$$${f}\left(\mathrm{3}\right)=\left(\mathrm{3}^{\mathrm{3}} \right)^{\mathrm{3}} \\ $$$${f}\left(\mathrm{4}\right)=\left(\left(\mathrm{4}^{\mathrm{4}} \right)^{\mathrm{4}} \right)^{\mathrm{4}} \\ $$$${f}\left(\mathrm{5}\right)=\left(\left(\left(\mathrm{5}^{\mathrm{5}} \right)^{\mathrm{5}} \right)^{\mathrm{5}} \right)^{\mathrm{5}} \\ $$$$... \\ $$$$\mathrm{find}\:{f}'\left({x}\right) \\ $$
Question Number 48306 Answers: 1 Comments: 0
$$\mathrm{x}^{\mathrm{2}} +\mathrm{4x}+\mathrm{1}=\mathrm{9} \\ $$
Question Number 48295 Answers: 1 Comments: 0
Question Number 48294 Answers: 2 Comments: 3
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