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Question Number 46180    Answers: 0   Comments: 3

Question Number 46172    Answers: 1   Comments: 0

Question Number 46171    Answers: 0   Comments: 1

find ∫ (dx/((√x)+(√(x+1)) +(√(x+2))))

$${find}\:\int\:\:\:\:\frac{{dx}}{\sqrt{{x}}+\sqrt{{x}+\mathrm{1}}\:+\sqrt{{x}+\mathrm{2}}} \\ $$

Question Number 46168    Answers: 2   Comments: 0

Question Number 46157    Answers: 1   Comments: 0

Please help. Find all the general solution of 6x + 8y + 5z = 101 . I got: x = − 48 + 45m + 4n y = 48 + 45m − 3n z = 1 − 2m Please help. Am confused.

$$\mathrm{Please}\:\mathrm{help}. \\ $$$$\:\:\:\:\:\mathrm{Find}\:\mathrm{all}\:\mathrm{the}\:\mathrm{general}\:\mathrm{solution}\:\mathrm{of}\:\:\:\:\:\:\:\mathrm{6x}\:+\:\mathrm{8y}\:+\:\mathrm{5z}\:=\:\mathrm{101}\:. \\ $$$$ \\ $$$$\mathrm{I}\:\mathrm{got}:\:\:\:\:\:\:\:\:\mathrm{x}\:=\:−\:\mathrm{48}\:+\:\mathrm{45m}\:+\:\mathrm{4n} \\ $$$$\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\mathrm{y}\:=\:\:\:\:\:\mathrm{48}\:+\:\mathrm{45m}\:−\:\mathrm{3n} \\ $$$$\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\mathrm{z}\:=\:\:\:\:\:\:\:\mathrm{1}\:−\:\mathrm{2m} \\ $$$$ \\ $$$$\mathrm{Please}\:\mathrm{help}.\:\:\mathrm{Am}\:\mathrm{confused}.\: \\ $$

Question Number 46156    Answers: 1   Comments: 0

Question Number 46146    Answers: 0   Comments: 3

Question Number 46144    Answers: 0   Comments: 0

Object A is in motion.A moves at a velocity of 12ms^(−2) and B is still(not moving).If A collides with B. a) Calculate the velocity at which B will move if it has mass of 70kg. and A has mass of 60kg. b) the momentum after collision. c) state the principle you applied in a) and b) above

$$\:{Object}\:{A}\:{is}\:{in}\:{motion}.{A}\:{moves}\:{at}\:{a}\:{velocity}\:{of}\: \\ $$$$\mathrm{12}{ms}^{−\mathrm{2}} \:{and}\:{B}\:{is}\:{still}\left({not}\:{moving}\right).{If}\:{A}\:{collides}\:{with}\:{B}. \\ $$$$\left.{a}\right)\:{Calculate}\:{the}\:{velocity}\:{at}\:{which}\:{B}\:{will}\:{move}\:{if}\:{it}\:{has}\:{mass} \\ $$$${of}\:\mathrm{70}{kg}.\:{and}\:{A}\:{has}\:{mass}\:{of}\:\mathrm{60}{kg}. \\ $$$$\left.{b}\right)\:{the}\:{momentum}\:{after}\:{collision}. \\ $$$$\left.{c}\left.\right)\left.\:{state}\:{the}\:{principle}\:{you}\:{applied}\:{in}\:{a}\right)\:{and}\:{b}\right)\:{above} \\ $$$$ \\ $$

Question Number 46143    Answers: 1   Comments: 0

Question Number 46139    Answers: 2   Comments: 1

A park has the shape of a regular hexagon of sides 2km each. A boy walks a distance of 5km along the sides of the park. What is the direct distance between the start point and the end point?

$$\mathrm{A}\:\mathrm{park}\:\mathrm{has}\:\mathrm{the}\:\mathrm{shape}\:\mathrm{of}\:\mathrm{a}\:\mathrm{regular}\:\mathrm{hexagon} \\ $$$$\mathrm{of}\:\mathrm{sides}\:\mathrm{2km}\:\mathrm{each}.\:\mathrm{A}\:\mathrm{boy}\:\mathrm{walks}\:\mathrm{a}\:\mathrm{distance} \\ $$$$\mathrm{of}\:\mathrm{5km}\:\mathrm{along}\:\mathrm{the}\:\mathrm{sides}\:\mathrm{of}\:\mathrm{the}\:\mathrm{park}.\: \\ $$$$\mathrm{What}\:\mathrm{is}\:\mathrm{the}\:\mathrm{direct}\:\mathrm{distance}\:\mathrm{between}\: \\ $$$$\mathrm{the}\:\mathrm{start}\:\mathrm{point}\:\mathrm{and}\:\mathrm{the}\:\mathrm{end}\:\mathrm{point}? \\ $$

Question Number 46136    Answers: 1   Comments: 0

Question Number 46121    Answers: 0   Comments: 1

Question Number 46129    Answers: 0   Comments: 4

Question Number 46110    Answers: 1   Comments: 2

Question Number 46103    Answers: 1   Comments: 3

Find the area enclosed between curves y^2 (2a−x)=x^3 and line x=2 above the x−axis ? Graphing calculators are not allowed..

$${Find}\:{the}\:{area}\:{enclosed}\:{between}\:{curves} \\ $$$${y}^{\mathrm{2}} \left(\mathrm{2}{a}−{x}\right)={x}^{\mathrm{3}} \:{and}\:{line}\:{x}=\mathrm{2}\:{above}\:{the} \\ $$$${x}−{axis}\:? \\ $$$${Graphing}\:{calculators}\:{are}\:{not}\:{allowed}.. \\ $$

Question Number 46101    Answers: 1   Comments: 0

I=∫(x^(n+1) /(√(1+x^n )))dx=?

$$\mathrm{I}=\int\frac{\mathrm{x}^{\mathrm{n}+\mathrm{1}} }{\sqrt{\mathrm{1}+\mathrm{x}^{\mathrm{n}} }}\mathrm{dx}=? \\ $$

Question Number 46095    Answers: 1   Comments: 0

Question Number 46091    Answers: 1   Comments: 1

Question Number 46088    Answers: 1   Comments: 0

Question Number 46087    Answers: 1   Comments: 0

please help me!! calculate: I=∫_2 ^(1+e^2 ) ((12288ln(x−1))/([ln^(12) (x−1)+4096](x−1)))dx thanks!!!

$$\mathrm{please}\:\mathrm{help}\:\mathrm{me}!! \\ $$$$\mathrm{calculate}: \\ $$$$\mathrm{I}=\underset{\mathrm{2}} {\overset{\mathrm{1}+\mathrm{e}^{\mathrm{2}} } {\int}}\frac{\mathrm{12288ln}\left(\mathrm{x}−\mathrm{1}\right)}{\left[\mathrm{ln}^{\mathrm{12}} \left(\mathrm{x}−\mathrm{1}\right)+\mathrm{4096}\right]\left(\mathrm{x}−\mathrm{1}\right)}\mathrm{dx} \\ $$$$\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\mathrm{thanks}!!! \\ $$

Question Number 46085    Answers: 1   Comments: 2

Question Number 46084    Answers: 1   Comments: 1

Question Number 46083    Answers: 1   Comments: 0

Question Number 46060    Answers: 1   Comments: 0

determine whether or not lim_(x→0) [ is continuous

$${determine}\:{whether}\:{or}\:{not}\:\:\underset{\mathrm{x}\rightarrow\mathrm{0}} {\mathrm{lim}}\left[\:\:\:\:\:\right. \\ $$$${is}\:{continuous} \\ $$

Question Number 46045    Answers: 1   Comments: 0

A number is said to be ′′right prime′′ if despite dropping the left most digits successively, Number continues to be a prime number. For example: 223 is a right prime because despite dropping 2 from left most part, we obtain 23 as the prime number. Next, even after dropping 2 from left, 3 is a prime. How many two digit numbers are right prime ?

$$\mathrm{A}\:\mathrm{number}\:\mathrm{is}\:\mathrm{said}\:\mathrm{to}\:\mathrm{be}\:''\mathrm{right}\:\mathrm{prime}''\:\mathrm{if}\:\mathrm{despite}\:\mathrm{dropping}\:\mathrm{the}\:\mathrm{left}\:\mathrm{most} \\ $$$$\mathrm{digits}\:\mathrm{successively},\:\:\mathrm{Number}\:\mathrm{continues}\:\mathrm{to}\:\mathrm{be}\:\mathrm{a}\:\mathrm{prime}\:\mathrm{number}.\:\: \\ $$$$\mathrm{For}\:\mathrm{example}:\:\:\mathrm{223}\:\mathrm{is}\:\mathrm{a}\:\mathrm{right}\:\mathrm{prime}\:\mathrm{because}\:\mathrm{despite}\:\mathrm{dropping}\:\mathrm{2}\:\mathrm{from}\:\mathrm{left} \\ $$$$\mathrm{most}\:\mathrm{part},\:\mathrm{we}\:\mathrm{obtain}\:\:\mathrm{23}\:\mathrm{as}\:\mathrm{the}\:\mathrm{prime}\:\mathrm{number}.\:\mathrm{Next},\:\mathrm{even}\:\mathrm{after}\:\mathrm{dropping}\: \\ $$$$\mathrm{2}\:\mathrm{from}\:\mathrm{left},\:\:\mathrm{3}\:\mathrm{is}\:\mathrm{a}\:\mathrm{prime}. \\ $$$$\:\:\:\:\:\mathrm{How}\:\mathrm{many}\:\mathrm{two}\:\mathrm{digit}\:\mathrm{numbers}\:\mathrm{are}\:\mathrm{right}\:\mathrm{prime}\:? \\ $$

Question Number 46042    Answers: 4   Comments: 10

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