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Question Number 51774 Answers: 1 Comments: 4

Question Number 51768 Answers: 1 Comments: 2

Question Number 51772 Answers: 2 Comments: 0

x^3 +12x+12=0 Express your answer in surd form

$$\mathrm{x}^{\mathrm{3}} +\mathrm{12x}+\mathrm{12}=\mathrm{0} \\ $$$$ \\ $$$$\mathrm{Express}\:\mathrm{your}\:\mathrm{answer}\:\mathrm{in}\:\mathrm{surd}\:\mathrm{form} \\ $$$$ \\ $$

Question Number 51733 Answers: 2 Comments: 3

Question Number 51729 Answers: 1 Comments: 0

81^(1/4) × 9^(3/2) × 27^(4/3) = _____

$$\mathrm{81}^{\frac{\mathrm{1}}{\mathrm{4}}} ×\:\mathrm{9}^{\frac{\mathrm{3}}{\mathrm{2}}} ×\:\mathrm{27}^{\frac{\mathrm{4}}{\mathrm{3}}} =\:\_\_\_\_\_ \\ $$

Question Number 51728 Answers: 0 Comments: 5

Question Number 51721 Answers: 1 Comments: 0

Find the range of value of x given that: ∣x + i∣ ≥ (1/x)

$$\mathrm{Find}\:\mathrm{the}\:\mathrm{range}\:\mathrm{of}\:\mathrm{value}\:\mathrm{of}\:\mathrm{x}\:\mathrm{given}\:\mathrm{that}:\:\:\:\:\:\mid\mathrm{x}\:+\:\mathrm{i}\mid\:\geqslant\:\frac{\mathrm{1}}{\mathrm{x}} \\ $$

Question Number 51720 Answers: 0 Comments: 0

Question Number 51712 Answers: 0 Comments: 9

Question Number 51700 Answers: 1 Comments: 1

Question Number 51694 Answers: 1 Comments: 0

Question Number 51691 Answers: 1 Comments: 0

Question Number 51710 Answers: 1 Comments: 0

solve the equation y = xy′+ (y′)^2

$${solve}\:{the}\:{equation} \\ $$$${y}\:=\:{xy}'+\:\left({y}'\right)^{\mathrm{2}} \\ $$

Question Number 51709 Answers: 2 Comments: 0

y′′=2y(y′) solve the equation

$${y}''=\mathrm{2}{y}\left({y}'\right) \\ $$$$ \\ $$$${solve}\:{the}\:{equation} \\ $$

Question Number 51680 Answers: 1 Comments: 2

Solve the equation: (1) z^3 + 1 − 10i = 0 (2) z^4 − i + 2 = 0

$$\mathrm{Solve}\:\mathrm{the}\:\mathrm{equation}:\:\:\:\:\: \\ $$$$\:\left(\mathrm{1}\right)\:\:\:\:\:\mathrm{z}^{\mathrm{3}} \:+\:\mathrm{1}\:−\:\mathrm{10i}\:\:=\:\:\mathrm{0} \\ $$$$\:\left(\mathrm{2}\right)\:\:\:\:\:\mathrm{z}^{\mathrm{4}} \:−\:\mathrm{i}\:+\:\mathrm{2}\:\:=\:\:\mathrm{0} \\ $$

Question Number 51673 Answers: 0 Comments: 1

Question Number 51658 Answers: 3 Comments: 7

Question Number 51649 Answers: 2 Comments: 0

It takes man A 6 days to a piece of work. It takes man B 4 days to do the same piece of work. How many days will A and B take to do the same piece of work?

$$\mathrm{It}\:\mathrm{takes}\:\mathrm{man}\:\mathrm{A}\:\mathrm{6}\:\mathrm{days}\:\mathrm{to}\:\mathrm{a}\:\mathrm{piece}\:\mathrm{of} \\ $$$$\mathrm{work}.\:\mathrm{It}\:\mathrm{takes}\:\mathrm{man}\:\mathrm{B}\:\mathrm{4}\:\mathrm{days}\:\mathrm{to}\:\mathrm{do}\: \\ $$$$\mathrm{the}\:\mathrm{same}\:\mathrm{piece}\:\mathrm{of}\:\mathrm{work}.\:\mathrm{How}\:\mathrm{many} \\ $$$$\mathrm{days}\:\mathrm{will}\:\mathrm{A}\:\mathrm{and}\:\mathrm{B}\:\mathrm{take}\:\mathrm{to}\:\mathrm{do}\:\mathrm{the} \\ $$$$\mathrm{same}\:\mathrm{piece}\:\mathrm{of}\:\mathrm{work}? \\ $$

Question Number 51643 Answers: 2 Comments: 0

If ∣z∣ = 1, prove that ((z − 1)/(z^− − 1)) (z ≠ 1) is a pure imaginary

$$\mathrm{If}\:\:\:\mid\mathrm{z}\mid\:=\:\mathrm{1},\:\:\:\:\mathrm{prove}\:\mathrm{that}\:\:\:\:\:\frac{\mathrm{z}\:−\:\mathrm{1}}{\overset{−} {\mathrm{z}}\:−\:\mathrm{1}}\:\:\:\:\:\:\left(\mathrm{z}\:\neq\:\mathrm{1}\right)\:\:\:\mathrm{is}\:\mathrm{a}\:\mathrm{pure}\:\mathrm{imaginary} \\ $$

Question Number 51637 Answers: 2 Comments: 0

An object 60cm tall is placed on the principal axis of a convex lens and its 30cm tall image is formed on the screen placed at a distance of 40cm from the object.What is the focal length of the lens?

$${An}\:{object}\:\mathrm{60}{cm}\:{tall}\:{is}\:{placed}\:{on} \\ $$$${the}\:{principal}\:{axis}\:{of}\:{a}\:{convex}\:{lens} \\ $$$${and}\:{its}\:\mathrm{30}{cm}\:{tall}\:{image}\:{is}\:{formed} \\ $$$${on}\:{the}\:{screen}\:{placed}\:{at}\:{a}\:{distance} \\ $$$${of}\:\mathrm{40}{cm}\:{from}\:{the}\:{object}.{What}\:{is} \\ $$$${the}\:{focal}\:{length}\:{of}\:{the}\:{lens}? \\ $$

Question Number 51636 Answers: 1 Comments: 4

Question Number 51644 Answers: 0 Comments: 0

Question Number 51630 Answers: 1 Comments: 4

Question Number 51628 Answers: 0 Comments: 2

Question Number 51621 Answers: 0 Comments: 6

Question Number 51617 Answers: 1 Comments: 2

A=lim_(x→0) ((e^x −e^(−x) −2x)/x^3 )(without using L′hopital rule)

$$\mathrm{A}=\underset{{x}\rightarrow\mathrm{0}} {\mathrm{lim}}\frac{{e}^{{x}} −{e}^{−{x}} −\mathrm{2}{x}}{{x}^{\mathrm{3}} }\left({without}\:\right. \\ $$$$\left.{using}\:{L}'\mathrm{hopital}\:\mathrm{rule}\right) \\ $$$$ \\ $$

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