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Question Number 57114    Answers: 1   Comments: 4

Question Number 57103    Answers: 0   Comments: 2

let A_n =∫∫_w_n e^(−x^2 −y^2 ) (√(x^2 +y^2 ))dxdy with w_n =[(1/n),n]×[(1/n),n] 1) calculate A_n interms of n 2) find lim_(n→+∞) A_n

$${let}\:{A}_{{n}} =\int\int_{{w}_{{n}} } \:{e}^{−{x}^{\mathrm{2}} −{y}^{\mathrm{2}} } \:\sqrt{{x}^{\mathrm{2}} \:+{y}^{\mathrm{2}} }{dxdy} \\ $$$${with}\:{w}_{{n}} =\left[\frac{\mathrm{1}}{{n}},{n}\right]×\left[\frac{\mathrm{1}}{{n}},{n}\right] \\ $$$$\left.\mathrm{1}\right)\:{calculate}\:{A}_{{n}} {interms}\:{of}\:{n} \\ $$$$\left.\mathrm{2}\right)\:{find}\:{lim}_{{n}\rightarrow+\infty} \:{A}_{{n}} \\ $$

Question Number 57097    Answers: 0   Comments: 2

Question Number 57084    Answers: 4   Comments: 2

Question Number 57075    Answers: 1   Comments: 5

Question Number 57074    Answers: 1   Comments: 0

Solve the system. ^x C_(y + 1) = 20, ^(x − 1) C_y = 10

$$\mathrm{Solve}\:\mathrm{the}\:\mathrm{system}. \\ $$$$\:\:\:\:\:\:\overset{\mathrm{x}} {\:}\mathrm{C}_{\mathrm{y}\:+\:\mathrm{1}} \:\:=\:\:\mathrm{20},\:\:\:\:\:\:\:\:\:\:\:\overset{\mathrm{x}\:−\:\mathrm{1}} {\:}\mathrm{C}_{\mathrm{y}} \:\:=\:\:\mathrm{10} \\ $$

Question Number 57073    Answers: 0   Comments: 2

f(x)=A f : [0, ∞) g : [1, 0] g(x)=B lim_(n→∞) (1/n)∫_0 ^n f(x)g((x/n))dx=...

$${f}\left({x}\right)={A} \\ $$$${f}\::\:\left[\mathrm{0},\:\infty\right)\: \\ $$$${g}\::\:\left[\mathrm{1},\:\mathrm{0}\right] \\ $$$${g}\left({x}\right)={B} \\ $$$$\underset{{n}\rightarrow\infty} {\mathrm{lim}}\:\frac{\mathrm{1}}{{n}}\int_{\mathrm{0}} ^{{n}} {f}\left({x}\right){g}\left(\frac{{x}}{{n}}\right){dx}=... \\ $$

Question Number 57071    Answers: 1   Comments: 1

Question Number 57062    Answers: 2   Comments: 2

find the sum of all three digital natural numbers that are divisible by 7

$${find}\:{the}\:{sum}\:{of}\:{all} \\ $$$${three}\:{digital}\:{natural} \\ $$$${numbers}\:{that}\:{are}\: \\ $$$${divisible}\:{by}\:\mathrm{7} \\ $$

Question Number 57060    Answers: 0   Comments: 0

Question Number 57051    Answers: 0   Comments: 5

F_n = ((ϕ^n − (1 − ϕ)^n )/(√5)) , with { ((ϕ = ((1 + (√5))/2))) :} (G_n ) : { ((G_1 = 1)),((G_2 = 1)),((G_m = G_(m−1) + G_(m−2) )) :} Give a proof for F_n = G_n , ∀n∈N^∗ . Thank you

$$ \\ $$$$\:\:\boldsymbol{{F}}_{\boldsymbol{{n}}} \:=\:\frac{\varphi^{{n}} \:−\:\left(\mathrm{1}\:−\:\varphi\right)^{{n}} }{\sqrt{\mathrm{5}}}\:,\:\:\mathrm{with}\:\begin{cases}{\varphi\:=\:\frac{\mathrm{1}\:+\:\sqrt{\mathrm{5}}}{\mathrm{2}}}\end{cases} \\ $$$$ \\ $$$$\:\:\left(\boldsymbol{{G}}_{\boldsymbol{{n}}} \right)\::\:\begin{cases}{\boldsymbol{{G}}_{\mathrm{1}} \:=\:\mathrm{1}}\\{\boldsymbol{{G}}_{\mathrm{2}} \:=\:\mathrm{1}}\\{\boldsymbol{{G}}_{{m}} \:=\:\boldsymbol{{G}}_{\mathrm{m}−\mathrm{1}} \:+\:\boldsymbol{{G}}_{{m}−\mathrm{2}} }\end{cases} \\ $$$$ \\ $$$$\:\:\mathrm{Give}\:\mathrm{a}\:\mathrm{proof}\:\mathrm{for}\:\boldsymbol{{F}}_{\boldsymbol{{n}}} \:=\:\boldsymbol{{G}}_{\boldsymbol{{n}}} \:,\:\forall{n}\in\mathbb{N}^{\ast} .\: \\ $$$$\:\:\mathrm{Thank}\:\mathrm{you} \\ $$

Question Number 57048    Answers: 2   Comments: 1

Question Number 57046    Answers: 0   Comments: 1

Question Number 57044    Answers: 1   Comments: 1

Question Number 57042    Answers: 1   Comments: 1

Question Number 57024    Answers: 0   Comments: 1

If f(x−1)=2x^3 −3x^2 +7x+10. Find f(3).

$$\mathrm{If}\:\mathrm{f}\left(\mathrm{x}−\mathrm{1}\right)=\mathrm{2x}^{\mathrm{3}} −\mathrm{3x}^{\mathrm{2}} +\mathrm{7x}+\mathrm{10}.\:\mathrm{Find}\:\mathrm{f}\left(\mathrm{3}\right). \\ $$

Question Number 57023    Answers: 1   Comments: 0

There are 28 players in a national football team. 14 play midfield and defence, 15 play defence and attack and 3 play midfield only. the number of players who play attack only is twice those who play defence only, and the number who play defence is equal to those who play attack. If 18 play midfield represent the information on a venn diagram. Find i. how many play at most two games ii. how many play neither attack nor defence iii. how many play either midfield or attack.

$$\mathrm{There}\:\mathrm{are}\:\mathrm{28}\:\mathrm{players}\:\mathrm{in}\:\mathrm{a}\:\mathrm{national}\: \\ $$$$\mathrm{football}\:\mathrm{team}.\:\mathrm{14}\:\mathrm{play}\:\mathrm{midfield}\:\mathrm{and} \\ $$$$\mathrm{defence},\:\mathrm{15}\:\mathrm{play}\:\mathrm{defence}\:\mathrm{and}\:\mathrm{attack}\: \\ $$$$\mathrm{and}\:\mathrm{3}\:\mathrm{play}\:\mathrm{midfield}\:\mathrm{only}.\:\mathrm{the}\:\mathrm{number} \\ $$$$\mathrm{of}\:\mathrm{players}\:\mathrm{who}\:\mathrm{play}\:\mathrm{attack}\:\mathrm{only}\:\mathrm{is}\: \\ $$$$\mathrm{twice}\:\mathrm{those}\:\mathrm{who}\:\mathrm{play}\:\mathrm{defence}\:\mathrm{only},\:\mathrm{and} \\ $$$$\mathrm{the}\:\mathrm{number}\:\mathrm{who}\:\mathrm{play}\:\mathrm{defence} \\ $$$$\:\mathrm{is}\:\mathrm{equal}\:\mathrm{to}\:\mathrm{those}\:\mathrm{who}\:\mathrm{play}\:\mathrm{attack}.\:\mathrm{If}\: \\ $$$$\mathrm{18}\:\mathrm{play}\:\mathrm{midfield}\:\mathrm{represent}\:\mathrm{the}\: \\ $$$$\mathrm{information}\:\mathrm{on}\:\mathrm{a}\:\mathrm{venn}\:\mathrm{diagram}. \\ $$$$\mathrm{Find} \\ $$$$\mathrm{i}.\:\mathrm{how}\:\mathrm{many}\:\mathrm{play}\:\mathrm{at}\:\mathrm{most}\:\mathrm{two}\:\mathrm{games} \\ $$$$\mathrm{ii}.\:\mathrm{how}\:\mathrm{many}\:\mathrm{play}\:\mathrm{neither}\:\mathrm{attack}\:\mathrm{nor} \\ $$$$\mathrm{defence} \\ $$$$\mathrm{iii}.\:\mathrm{how}\:\mathrm{many}\:\mathrm{play}\:\mathrm{either}\:\mathrm{midfield}\:\mathrm{or}\: \\ $$$$\mathrm{attack}. \\ $$

Question Number 57020    Answers: 0   Comments: 3

[f(x+1)−f(x)]^2 =4[f(x)−1] f(x)=? −−−−−−−−−−−−− f(0)=0

$$\left[{f}\left({x}+\mathrm{1}\right)−{f}\left({x}\right)\right]^{\mathrm{2}} =\mathrm{4}\left[{f}\left({x}\right)−\mathrm{1}\right] \\ $$$${f}\left({x}\right)=? \\ $$$$−−−−−−−−−−−−− \\ $$$${f}\left(\mathrm{0}\right)=\mathrm{0} \\ $$

Question Number 57012    Answers: 2   Comments: 0

Find the local minimum value of f(x) where f(x)= (x−(1/x))+((2/(x−(1/x)))) ?

$${Find}\:{the}\:{local}\:{minimum}\:{value}\:{of}\:{f}\left({x}\right) \\ $$$${where}\:{f}\left({x}\right)=\:\left({x}−\frac{\mathrm{1}}{{x}}\right)+\left(\frac{\mathrm{2}}{{x}−\frac{\mathrm{1}}{{x}}}\right)\:? \\ $$

Question Number 57011    Answers: 1   Comments: 0

f(((x+y)/2))f(((x−y)/2))=g(x) g(x+y)g(x−y)=[f(x)]^2 −[f(y)]^2 f(x),g(x)=?

$${f}\left(\frac{{x}+{y}}{\mathrm{2}}\right){f}\left(\frac{{x}−{y}}{\mathrm{2}}\right)={g}\left({x}\right) \\ $$$${g}\left({x}+{y}\right){g}\left({x}−{y}\right)=\left[{f}\left({x}\right)\right]^{\mathrm{2}} −\left[{f}\left({y}\right)\right]^{\mathrm{2}} \\ $$$${f}\left({x}\right),{g}\left({x}\right)=? \\ $$

Question Number 57010    Answers: 1   Comments: 1

f(((x+y)/2))=((f(x)f(y))/(f(2))) f(x)=?

$${f}\left(\frac{{x}+{y}}{\mathrm{2}}\right)=\frac{{f}\left({x}\right){f}\left({y}\right)}{{f}\left(\mathrm{2}\right)} \\ $$$${f}\left({x}\right)=? \\ $$

Question Number 57007    Answers: 1   Comments: 3

cosec ((π/(14))) − 4 cos (((2π)/7)) = ?

$$\mathrm{cosec}\:\left(\frac{\pi}{\mathrm{14}}\right)\:−\:\mathrm{4}\:\mathrm{cos}\:\left(\frac{\mathrm{2}\pi}{\mathrm{7}}\right)\:\:=\:\:? \\ $$

Question Number 57001    Answers: 0   Comments: 1

construct an analytic function f(z) whose real part is e^x cos y

$${construct}\:{an}\:{analytic}\:{function}\:{f}\left({z}\right)\:{whose}\:{real}\:{part}\:{is}\:{e}^{{x}} \mathrm{cos}\:{y} \\ $$

Question Number 57000    Answers: 3   Comments: 1

If (x+2)^2 is a factor of the polynomial f(x)=mx^3 +x^2 +x+n, find; the values of m and n.

$$\mathrm{If}\:\left(\mathrm{x}+\mathrm{2}\right)^{\mathrm{2}} \:\mathrm{is}\:\mathrm{a}\:\mathrm{factor}\:\mathrm{of}\:\mathrm{the}\:\mathrm{polynomial} \\ $$$$\mathrm{f}\left(\mathrm{x}\right)=\mathrm{mx}^{\mathrm{3}} +\mathrm{x}^{\mathrm{2}} +\mathrm{x}+\mathrm{n},\:\mathrm{find}; \\ $$$$\:\mathrm{the}\:\mathrm{values}\:\mathrm{of}\:\mathrm{m}\:\mathrm{and}\:\mathrm{n}. \\ $$

Question Number 56991    Answers: 0   Comments: 4

x! − x^2 = 8 , Find x

$$\:\:\mathrm{x}!\:−\:\mathrm{x}^{\mathrm{2}} \:\:=\:\:\mathrm{8}\:,\:\:\:\:\mathrm{Find}\:\:\mathrm{x} \\ $$$$ \\ $$

Question Number 56986    Answers: 2   Comments: 1

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