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AllQuestion and Answers: Page 1520

Question Number 50201 Answers: 0 Comments: 2

a=665,21 b=47,14

$$\mathrm{a}=\mathrm{665},\mathrm{21}\:\:\:\:\:\:\:\mathrm{b}=\mathrm{47},\mathrm{14} \\ $$

Question Number 50198 Answers: 0 Comments: 1

Question Number 50197 Answers: 0 Comments: 0

plz plz help me sir

$$\mathrm{plz}\:\mathrm{plz}\:\mathrm{help}\:\mathrm{me}\:\mathrm{sir} \\ $$

Question Number 50196 Answers: 0 Comments: 0

Question Number 50195 Answers: 0 Comments: 0

Question Number 50194 Answers: 0 Comments: 2

Question Number 50349 Answers: 0 Comments: 0

Question Number 50200 Answers: 0 Comments: 2

Question Number 50239 Answers: 1 Comments: 1

Question Number 50186 Answers: 1 Comments: 0

Let f(x)= ∫_2 ^( x) (dt/(1+t^6 )). Prove that : (1/(730))<f(3)<(1/(65)).

$${Let}\:{f}\left({x}\right)=\:\int_{\mathrm{2}} ^{\:{x}} \:\frac{{dt}}{\mathrm{1}+{t}^{\mathrm{6}} }. \\ $$$${Prove}\:{that}\:\::\:\frac{\mathrm{1}}{\mathrm{730}}<{f}\left(\mathrm{3}\right)<\frac{\mathrm{1}}{\mathrm{65}}. \\ $$

Question Number 50175 Answers: 1 Comments: 0

Question Number 50171 Answers: 0 Comments: 3

Sir l′m sorry l dont understand you

$$\mathrm{Sir}\:\mathrm{l}'\mathrm{m}\:\mathrm{sorry}\:\mathrm{l}\:\mathrm{dont}\:\mathrm{understand}\: \\ $$$$\mathrm{you} \\ $$

Question Number 50163 Answers: 2 Comments: 0

Question Number 50161 Answers: 1 Comments: 0

Find the function whose first derivative is 8−(5/(x^2 )^(1/3) ) the initial conditions f(8)=−20

$${Find}\:{the}\:{function}\:{whose}\:{first}\: \\ $$$${derivative}\:{is}\:\mathrm{8}−\frac{\mathrm{5}}{\sqrt[{\mathrm{3}}]{{x}^{\mathrm{2}} }}\:{the}\:{initial}\: \\ $$$${conditions}\:{f}\left(\mathrm{8}\right)=−\mathrm{20} \\ $$

Question Number 50158 Answers: 7 Comments: 1

Question Number 50156 Answers: 0 Comments: 1

Question Number 50155 Answers: 0 Comments: 1

plz help me sir

$$\mathrm{plz}\:\mathrm{help}\:\mathrm{me}\:\mathrm{sir} \\ $$

Question Number 50140 Answers: 5 Comments: 0

Solve the differential equation a)x(x+y)(dy/dx)=x^2 +xy−3y^2 b)y+xy^2 −x(dy/dx)=0 c [ x^2 (d^2 y/dx^(2 ) )−2x(dy/dx)+2(2x^2 +1)y=24x^3 given that (dy/dx)=6 ,(d^2 y/dx^2 )=0

$${Solve}\:{the}\:{differential} \\ $$$${equation} \\ $$$$\left.{a}\right){x}\left({x}+{y}\right)\frac{{dy}}{{dx}}={x}^{\mathrm{2}} +{xy}−\mathrm{3}{y}^{\mathrm{2}} \\ $$$$\left.{b}\right){y}+{xy}^{\mathrm{2}} −{x}\frac{{dy}}{{dx}}=\mathrm{0} \\ $$$${c}\:\left[\:\:{x}^{\mathrm{2}} \frac{{d}^{\mathrm{2}} {y}}{{dx}^{\mathrm{2}\:} }−\mathrm{2}{x}\frac{{dy}}{{dx}}+\mathrm{2}\left(\mathrm{2}{x}^{\mathrm{2}} +\mathrm{1}\right){y}=\mathrm{24}{x}^{\mathrm{3}} \right. \\ $$$${given}\:{that}\:\frac{{dy}}{{dx}}=\mathrm{6}\:\:\:,\frac{{d}^{\mathrm{2}} {y}}{{dx}^{\mathrm{2}} }=\mathrm{0} \\ $$

Question Number 50138 Answers: 0 Comments: 1

$$\mathrm{D} \\ $$

Question Number 50135 Answers: 2 Comments: 2

Question Number 50132 Answers: 0 Comments: 1

Let f be a positive function. Let I_1 =∫_(1−k) ^k x f{x(1−x} dx, I_2 =∫_(1−k) ^k x f{x(1−x} dx, where 2k−1>0. Then (I_1 /I_2 ) is

$$\mathrm{Let}\:{f}\:\:\mathrm{be}\:\mathrm{a}\:\mathrm{positive}\:\mathrm{function}.\:\mathrm{Let} \\ $$$${I}_{\mathrm{1}} =\underset{\mathrm{1}−{k}} {\overset{{k}} {\int}}{x}\:{f}\left\{{x}\left(\mathrm{1}−{x}\right\}\:{dx},\:\right. \\ $$$${I}_{\mathrm{2}} =\underset{\mathrm{1}−{k}} {\overset{{k}} {\int}}{x}\:{f}\left\{{x}\left(\mathrm{1}−{x}\right\}\:{dx},\:\right. \\ $$$$\mathrm{where}\:\mathrm{2}{k}−\mathrm{1}>\mathrm{0}.\:\mathrm{Then}\:\frac{{I}_{\mathrm{1}} }{{I}_{\mathrm{2}} }\:\:\mathrm{is} \\ $$

Question Number 50126 Answers: 0 Comments: 0

Question Number 50125 Answers: 0 Comments: 2

help me plz sir

$$\mathrm{help}\:\mathrm{me}\:\mathrm{plz}\:\mathrm{sir} \\ $$

Question Number 50101 Answers: 2 Comments: 4

Question Number 50093 Answers: 2 Comments: 1

Question Number 50089 Answers: 1 Comments: 2

lim_(x→8) ((x^2 −6x−16)/(∣x−8∣))

$$\underset{{x}\rightarrow\mathrm{8}} {\mathrm{lim}}\:\:\frac{\mathrm{x}^{\mathrm{2}} −\mathrm{6x}−\mathrm{16}}{\mid\mathrm{x}−\mathrm{8}\mid} \\ $$

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