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Question Number 58698 Answers: 1 Comments: 4

▽^→ ∙((e^(br) /r^2 ) e_r ^∧ )=? b is a constant.

$$\overset{\rightarrow} {\bigtriangledown}\centerdot\left(\frac{{e}^{{br}} }{{r}^{\mathrm{2}} }\:\overset{\wedge} {{e}}_{{r}} \right)=?\:\:\:\:{b}\:{is}\:{a}\:{constant}. \\ $$

Question Number 58696 Answers: 1 Comments: 3

Question Number 58686 Answers: 0 Comments: 1

Question Number 58682 Answers: 1 Comments: 0

3(1/5)+2(1/(15))

$$\mathrm{3}\frac{\mathrm{1}}{\mathrm{5}}+\mathrm{2}\frac{\mathrm{1}}{\mathrm{15}} \\ $$

Question Number 58675 Answers: 0 Comments: 5

Question Number 58671 Answers: 3 Comments: 2

lim_(x→0) ((1−cos5x)/x^2 )

$$\underset{{x}\rightarrow\mathrm{0}} {{lim}}\:\:\frac{\mathrm{1}−{cos}\mathrm{5}{x}}{{x}^{\mathrm{2}} } \\ $$

Question Number 58669 Answers: 2 Comments: 0

{[3×(5+5)]+5}+{[4+(5×4)+5]}

$$\left\{\left[\mathrm{3}×\left(\mathrm{5}+\mathrm{5}\right)\right]+\mathrm{5}\right\}+\left\{\left[\mathrm{4}+\left(\mathrm{5}×\mathrm{4}\right)+\mathrm{5}\right]\right\} \\ $$

Question Number 58668 Answers: 0 Comments: 4

Question Number 58663 Answers: 3 Comments: 0

Question Number 58660 Answers: 0 Comments: 5

Question Number 58652 Answers: 1 Comments: 1

Question Number 58648 Answers: 2 Comments: 4

Question Number 58644 Answers: 1 Comments: 0

6+3^2 ×4

$$\mathrm{6}+\mathrm{3}^{\mathrm{2}} ×\mathrm{4} \\ $$

Question Number 58641 Answers: 1 Comments: 1

What is (1/8)+(1/4)?

$$\mathrm{What}\:\mathrm{is}\:\frac{\mathrm{1}}{\mathrm{8}}+\frac{\mathrm{1}}{\mathrm{4}}? \\ $$

Question Number 58639 Answers: 1 Comments: 0

Question Number 58627 Answers: 1 Comments: 3

Question Number 58626 Answers: 1 Comments: 1

Question Number 58622 Answers: 1 Comments: 2

solve x+y=2xy y+z=3yz z+x=7zx

$${solve} \\ $$$${x}+{y}=\mathrm{2}{xy} \\ $$$${y}+{z}=\mathrm{3}{yz} \\ $$$${z}+{x}=\mathrm{7}{zx} \\ $$

Question Number 58618 Answers: 1 Comments: 0

Question Number 58614 Answers: 2 Comments: 0

with reference to book i am posting some basic question for students. 1)two charged coducting sphere of radius r_(1 ) and r_2 are positvely charged separated at a distance d from each other. force of interaction is F which is correct answer a)F=(1/(4πε))((q_1 q_2 )/d^2 ) b)F>(1/(4πε))((q_1 q_2 )/d^2 ) c)F<(1/(4πε))((q_1 q_2 )/d^2 ) d)none of these 2)same question as 1 but one is +ve q_1 and another is −ve q_2 then which option is correct a)F=F_(columb) b)F>F_(columb) c)F<F_(columb) d)none of these pls give answer with explanatiin..

$${with}\:{reference}\:{to}\:{book}\:\:{i}\:{am}\:{posting}\:{some}\:{basic} \\ $$$${question}\:{for}\:{students}. \\ $$$$\left.\mathrm{1}\right){two}\:{charged}\:{coducting}\:{sphere}\:{of}\:{radius} \\ $$$${r}_{\mathrm{1}\:} {and}\:{r}_{\mathrm{2}} \:{are}\:{positvely}\:{charged}\:{separated} \\ $$$${at}\:{a}\:{distance}\:{d}\:{from}\:{each}\:{other}. \\ $$$${force}\:{of}\:{interaction}\:{is}\:{F} \\ $$$${which}\:{is}\:{correct}\:{answer}\: \\ $$$$\left.{a}\right){F}=\frac{\mathrm{1}}{\mathrm{4}\pi\epsilon}\frac{{q}_{\mathrm{1}} {q}_{\mathrm{2}} }{{d}^{\mathrm{2}} } \\ $$$$\left.{b}\right){F}>\frac{\mathrm{1}}{\mathrm{4}\pi\epsilon}\frac{{q}_{\mathrm{1}} {q}_{\mathrm{2}} }{{d}^{\mathrm{2}} } \\ $$$$\left.{c}\right){F}<\frac{\mathrm{1}}{\mathrm{4}\pi\epsilon}\frac{{q}_{\mathrm{1}} {q}_{\mathrm{2}} }{{d}^{\mathrm{2}} } \\ $$$$\left.{d}\right){none}\:{of}\:{these} \\ $$$$\left.\mathrm{2}\right){same}\:{question}\:{as}\:\mathrm{1}\:{but}\:{one}\:{is}\:+{ve}\:{q}_{\mathrm{1}} \:{and} \\ $$$${another}\:{is}\:−{ve}\:{q}_{\mathrm{2}} \:{then}\:{which}\:{option}\:{is}\:{correct} \\ $$$$\left.{a}\right){F}={F}_{{columb}} \\ $$$$\left.{b}\right){F}>{F}_{{columb}} \\ $$$$\left.{c}\right){F}<{F}_{{columb}} \\ $$$$\left.{d}\right){none}\:{of}\:{these} \\ $$$${pls}\:{give}\:{answer}\:{with}\:{explanatiin}.. \\ $$

Question Number 58612 Answers: 1 Comments: 0

P(x) is a monic−fifth degree polynomial that satisfy P(1) = 1 P(2) = 4 P(3) = 9 P(4) = 16 P(5) = 25 P(6) = ?

$${P}\left({x}\right)\:\:{is}\:\:{a}\:\:{monic}−{fifth}\:\:{degree}\:\:{polynomial}\:\:{that}\:{satisfy} \\ $$$$\:\:\:\:{P}\left(\mathrm{1}\right)\:\:=\:\:\mathrm{1} \\ $$$$\:\:\:\:{P}\left(\mathrm{2}\right)\:\:=\:\:\mathrm{4} \\ $$$$\:\:\:\:{P}\left(\mathrm{3}\right)\:\:=\:\:\mathrm{9} \\ $$$$\:\:\:\:{P}\left(\mathrm{4}\right)\:\:=\:\:\mathrm{16} \\ $$$$\:\:\:\:{P}\left(\mathrm{5}\right)\:\:=\:\:\mathrm{25} \\ $$$$\:\:\:\:{P}\left(\mathrm{6}\right)\:\:=\:\:? \\ $$$$ \\ $$

Question Number 58609 Answers: 1 Comments: 0

Question Number 58600 Answers: 2 Comments: 0

x ∈ R^+ (positive real numbers) Prove that x^2 + (2/x) ≥ 3

$${x}\:\:\in\:\:\mathbb{R}^{+} \:\left({positive}\:\:{real}\:\:{numbers}\right) \\ $$$${Prove}\:\:{that}\:\: \\ $$$$\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:{x}^{\mathrm{2}} \:+\:\frac{\mathrm{2}}{{x}}\:\:\geqslant\:\:\mathrm{3} \\ $$

Question Number 58595 Answers: 1 Comments: 0

Question Number 58592 Answers: 1 Comments: 0

If ∣z−1∣=1, then prove that arg(z) = (1/2)arg(z−1).

$${If}\:\mid{z}−\mathrm{1}\mid=\mathrm{1},\:{then}\:{prove}\:{that}\:{arg}\left({z}\right)\:=\: \\ $$$$\frac{\mathrm{1}}{\mathrm{2}}{arg}\left({z}−\mathrm{1}\right). \\ $$

Question Number 58587 Answers: 0 Comments: 0

For x > 0 , y < 1 . Prove that x^y + y^x > 1

$${For}\:\:\:{x}\:>\:\mathrm{0}\:\:,\:\:\:{y}\:\:<\:\:\mathrm{1}\:. \\ $$$${Prove}\:\:{that}\:\:\:\:{x}^{{y}} \:+\:{y}^{{x}} \:\:>\:\:\mathrm{1} \\ $$

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