Given that z_1 = R_1 + R + jωL ; z_2 = R_2 ; z_3 = (1/(jωC_3 ))
and z_4 = R_4 + (1/(jωC_4 )) and also that z_1 z_3 = z_2 z_4 , express
R and L in terms of the real constants R_1 , R_2 , R_4 , C_3 and C_4
Answer: R = ((R_2 C_3 − R_1 C_4 )/C_4 ) , L = R_2 R_4 C_3
If ((R_1 + jωL)/R_3 ) = (R_2 /(R_4 − j (1/(ωC)))) , where R_1 , R_2 , R_3 , R_4 , ω, L and C
are real , show that L = ((C R_2 R_3 )/(ω^2 C^2 R_4 ^2 + 1))
Prove that:
(a) If ∣z_1 + z_2 ∣ = ∣z_1 − z_2 ∣, the difference of the arguements of z_1
and z_2 is (π/2)
(b) If arg{((z_1 + z_2 )/(z_1 − z_2 ))} = (π/2) , then ∣z_1 ∣ = ∣z_2 ∣
Show that the equation
of tangent to the ellipse
(x^2 /a^2 )+(y^2 /b^2 )=1 at the end of
lactus rectum which
lie in the 1^(st) quadrant is
xe+y−a=0
∗merry X−mas and happy new year∗