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Question Number 48846 Answers: 0 Comments: 1

Question Number 48845 Answers: 1 Comments: 1

Question Number 48843 Answers: 0 Comments: 0

Question Number 48841 Answers: 0 Comments: 0

thanks sir

$${thanks}\:{sir} \\ $$$$ \\ $$

Question Number 48849 Answers: 1 Comments: 0

in (0 π)the number of solutions of the equation tanθ+tan2θ+tan3θ=tanθtan2θtan3θ is ans:2

$$\mathrm{in}\:\left(\mathrm{0}\:\pi\right)\mathrm{the}\:\mathrm{number}\:\mathrm{of}\:\mathrm{solutions}\:\mathrm{of}\:\mathrm{the} \\ $$$$\mathrm{equation}\:\mathrm{tan}\theta+\mathrm{tan2}\theta+\mathrm{tan3}\theta=\mathrm{tan}\theta\mathrm{tan2}\theta\mathrm{tan3}\theta \\ $$$$\mathrm{is} \\ $$$$\mathrm{ans}:\mathrm{2} \\ $$

Question Number 48837 Answers: 1 Comments: 0

0.25(×+2)=0.5(2×−1)

$$\mathrm{0}.\mathrm{25}\left(×+\mathrm{2}\right)=\mathrm{0}.\mathrm{5}\left(\mathrm{2}×−\mathrm{1}\right) \\ $$

Question Number 48833 Answers: 1 Comments: 4

Question Number 48830 Answers: 1 Comments: 0

10((47)/(60))−(8(1/5)−5(2/3))×(5/8) sir could you help me

$$\mathrm{10}\frac{\mathrm{47}}{\mathrm{60}}−\left(\mathrm{8}\frac{\mathrm{1}}{\mathrm{5}}−\mathrm{5}\frac{\mathrm{2}}{\mathrm{3}}\right)×\frac{\mathrm{5}}{\mathrm{8}}\:\:\:\:{sir}\:{could}\:{you}\:{help}\:{me} \\ $$$$ \\ $$

Question Number 48829 Answers: 0 Comments: 3

lim_(x→0) ((∫1^x [t^2 (e^(1/t) −1)−t]dt)/(x^2 ln (1+1/x)))

$$\underset{{x}\rightarrow\mathrm{0}} {\mathrm{lim}}\frac{\int\mathrm{1}^{{x}} \left[{t}^{\mathrm{2}} \left({e}^{\mathrm{1}/{t}} −\mathrm{1}\right)−{t}\right]{dt}}{{x}^{\mathrm{2}} \mathrm{ln}\:\left(\mathrm{1}+\mathrm{1}/{x}\right)} \\ $$

Question Number 48826 Answers: 1 Comments: 0

2(5/7) 380 8(3/7) × plz help me

$$\mathrm{2}\frac{\mathrm{5}}{\mathrm{7}}\:\:\:\:\:\:\:\:\:\:\:\mathrm{380} \\ $$$$\mathrm{8}\frac{\mathrm{3}}{\mathrm{7}}\:\:\:\:\:\:\:\:\:\:\:\:\:×\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:{plz}\:{help}\:{me} \\ $$$$ \\ $$$$ \\ $$

Question Number 48823 Answers: 1 Comments: 3

Question Number 48815 Answers: 0 Comments: 7

who red marked ...better you come forwaed and say...it is better to show the way rather become cynic... better you solve your self and show the results rather pointing fingure to others...

$${who}\:{red}\:{marked}\:...{better}\:{you}\:{come}\:{forwaed} \\ $$$${and}\:{say}...{it}\:{is}\:{better}\:{to}\:{show}\:{the}\:{way}\:{rather}\:{become} \\ $$$${cynic}... \\ $$$${better}\:{you}\:{solve}\:{your}\:{self}\:{and}\:{show}\:{the}\:{results} \\ $$$${rather}\:{pointing}\:{fingure}\:{to}\:{others}... \\ $$$$ \\ $$

Question Number 48795 Answers: 1 Comments: 1

Find the sum: ^(30) C_0 .5^(100) −^(30) C_1 .5^(98) .3^3 +^(30) C_2 .5^(96) .3^6 − ...=?

$${Find}\:{the}\:{sum}: \\ $$$$\:^{\mathrm{30}} {C}_{\mathrm{0}} .\mathrm{5}^{\mathrm{100}} −^{\mathrm{30}} {C}_{\mathrm{1}} .\mathrm{5}^{\mathrm{98}} .\mathrm{3}^{\mathrm{3}} +^{\mathrm{30}} {C}_{\mathrm{2}} .\mathrm{5}^{\mathrm{96}} .\mathrm{3}^{\mathrm{6}} −\:...=? \\ $$

Question Number 48777 Answers: 0 Comments: 13

Question Number 48769 Answers: 1 Comments: 0

Question Number 48763 Answers: 2 Comments: 1

Question Number 48757 Answers: 2 Comments: 2

Question Number 48750 Answers: 1 Comments: 0

i need explanation for the division when 20751 is devided by 25 answer is 830.04..i need clarification why this red coloured zero (0) is coming when division is done by simple division...

$${i}\:{need}\:{explanation}\:{for}\:{the}\:{division}\:{when}\:\mathrm{20751} \\ $$$${is}\:{devided}\:{by}\:\mathrm{25} \\ $$$${answer}\:{is}\:\mathrm{830}.\mathrm{04}..{i}\:{need}\:{clarification}\:{why} \\ $$$${this}\:{red}\:{coloured}\:{zero}\:\left(\mathrm{0}\right)\:{is}\:{coming}\: \\ $$$${when}\:{division}\:{is}\:{done}\:{by}\:{simple}\:{division}... \\ $$

Question Number 48748 Answers: 0 Comments: 0