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Question Number 60728 Answers: 0 Comments: 0
$${calculate}\:\int_{\mathrm{1}} ^{+\infty} \:\:\frac{{ln}\left({lnx}\right)}{{x}^{\mathrm{2}} −{x}\:+\mathrm{1}}{dx} \\ $$
Question Number 60727 Answers: 0 Comments: 2
$${calculate}\:\int_{\mathrm{1}} ^{+\infty} \:\frac{{ln}\left({lnx}\right)}{\mathrm{1}+{x}^{\mathrm{2}} }{dx} \\ $$
Question Number 60725 Answers: 0 Comments: 2
$${x}\:\:=\:\:\underset{\mathrm{0}\leqslant{i}\leqslant{j}\leqslant\mathrm{2019}} {\sum}\:\left(\:_{\:\:\:\:{j}} ^{\mathrm{2019}} \:\right)\left(\:\:_{{i}} ^{{j}} \:\:\right)\: \\ $$
Question Number 60723 Answers: 0 Comments: 10
$${solve}\:{for}\:{x}\: \\ $$$$\sqrt{{a}−\sqrt{{a}+{x}}}\:+\:\sqrt{{a}+\sqrt{{a}−{x}}}\:=\:\mathrm{2}{x} \\ $$
Question Number 60717 Answers: 0 Comments: 1
Question Number 60706 Answers: 0 Comments: 2
$${let}\:{f}\left({x}\right)\:=\sqrt{\mathrm{1}+{x}^{\mathrm{2}} } \\ $$$$\left.\mathrm{1}\right)\:{let}\:{U}_{{n}} ={f}^{\left({n}\right)} \left({x}\right)\:\:{prove}\:{that}\:\sum_{{k}=\mathrm{0}} ^{{n}} \:{C}_{{n}} ^{{k}} \:{U}_{{k}} {U}_{{n}+\mathrm{1}−{k}} =\mathrm{0}\:\:{for}\:{n}\geqslant\mathrm{2} \\ $$$$\left.\mathrm{2}\right)\:{developp}\:{f}\:{at}\:{integr}\:{serie}\:. \\ $$
Question Number 60705 Answers: 1 Comments: 0
Question Number 60716 Answers: 1 Comments: 1
Question Number 60702 Answers: 0 Comments: 0
Question Number 60701 Answers: 0 Comments: 1
$${let}\:{f}\left({x}\right)\:={e}^{−{x}^{\mathrm{2}} } {ln}\left(\mathrm{2}−{x}\right)\:\:\:{developp}\:{f}\:{at}\:{integr}\:{serie}\:. \\ $$
Question Number 60697 Answers: 1 Comments: 1
Question Number 60695 Answers: 0 Comments: 1
$${solve}\:\sqrt{\mathrm{3}+{x}^{\mathrm{2}} }{y}^{''} \:\:\:\:−\left(\mathrm{2}{x}+\mathrm{1}\right){y}^{'} \:={x}^{\mathrm{2}} \:{e}^{−{x}^{\mathrm{2}} \:\:\:} \\ $$
Question Number 60694 Answers: 0 Comments: 0
$${solve}\:\:\left({x}^{\mathrm{3}} −{x}\right){y}^{''} \:\:\:−\mathrm{2}{x}\:{y}^{'} \:+\mathrm{3}{y}\:={xln}\left(\mathrm{1}+{x}\right) \\ $$
Question Number 60693 Answers: 0 Comments: 0
$${solve}\:\:\left(\mathrm{2}+{e}^{−{x}} \right){y}^{'} \:\:+\left(\mathrm{2}{x}+{e}^{{x}} \right){y}\:={e}^{{x}} {sinx}\: \\ $$
Question Number 60692 Answers: 0 Comments: 0
$${find}\:\:\int\:\:{arctan}\left(\mathrm{2}{cosx}\right){dx}\: \\ $$
Question Number 60691 Answers: 0 Comments: 1
$${calculate}\:{f}\left({a}\right)\:=\:\int\:\:\:\left(\mathrm{1}−\frac{{a}}{{x}^{\mathrm{2}} }\right)\:{arctan}\left({x}+\frac{{a}}{{x}}\right){dx}\:\:\:{with}\:{a}\:{real}\:. \\ $$
Question Number 60690 Answers: 0 Comments: 0
$${find}\:\int\:\left({x}+\mathrm{3}\right)\sqrt{\frac{\mathrm{1}−{x}^{\mathrm{2}} }{\mathrm{1}+{x}^{\mathrm{2}} }}{dx}\: \\ $$
Question Number 60688 Answers: 0 Comments: 0
$${find}\:\int\:\:\:{e}^{−{x}} \sqrt{\frac{\mathrm{3}−{x}}{\mathrm{3}+{x}}}{dx} \\ $$
Question Number 60687 Answers: 1 Comments: 2
$${calculate}\:\:\int\:\frac{\sqrt{\mathrm{1}+{x}^{\mathrm{2}} }−\mathrm{2}{x}}{\sqrt{\mathrm{1}+{x}^{\mathrm{2}} }\:+\mathrm{2}{x}}\:{dx} \\ $$
Question Number 60685 Answers: 1 Comments: 1
$${find}\:{I}_{{n}} =\int_{\mathrm{0}} ^{\frac{\pi}{\mathrm{2}}} \:\frac{\mathrm{1}−{cos}\left({nx}\right)}{{sin}^{\mathrm{2}} \left({nx}\right)}{dx}\: \\ $$
Question Number 60686 Answers: 0 Comments: 0
$${let}\:{f}\left({x}\right)\:={cos}\left(\mathrm{2}{x}\right)\:\:\:\:,\mathrm{2}\pi\:{periodic}\:,\:\:{developp}\:{f}\:{at}\:{fourier}\:{serie} \\ $$
Question Number 60683 Answers: 0 Comments: 0
$${find}\:{A}_{{n}} =\int_{\mathrm{0}} ^{\frac{\pi}{\mathrm{4}}} \:{sin}^{{n}} {xdx}\:\:\:\:{with}\:{n}\:{integr}\:{natural}\:. \\ $$
Question Number 60682 Answers: 0 Comments: 1
$${simplify}\:\:\:\:{S}_{{n}} =\sum_{{k}=\mathrm{0}} ^{{n}} \:\:{sin}^{{k}} \left({x}\right){cos}\left({kx}\right)\:\:\: \\ $$
Question Number 60681 Answers: 0 Comments: 1
$${calculate}\:\:{L}\left({e}^{−\mathrm{2}{x}} {sin}\left(\alpha{x}\right)\right)\:\:\:\:\alpha\:{real}\:\:\:{and}\:{L}\:{laplace}\:{transform} \\ $$
Question Number 60680 Answers: 0 Comments: 2
$${study}\:{the}\:{integral}\:\int_{\mathrm{0}} ^{\mathrm{1}} \:\frac{{x}}{{ln}\left(\mathrm{1}−{x}\right)}{dx} \\ $$
Question Number 60679 Answers: 0 Comments: 1
$${calculate}\:\int_{\mathrm{0}} ^{\infty} \:\:\:\frac{{ln}\left(\mathrm{1}+{e}^{−{x}^{\mathrm{2}} } \right)}{{x}^{\mathrm{2}} \:+\mathrm{4}}\:{dx} \\ $$
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