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Question Number 62053 Answers: 0 Comments: 1
$$\mathrm{m5}=\mathrm{25} \\ $$
Question Number 62052 Answers: 0 Comments: 1
$$\mathrm{3}\frac{\mathrm{1}}{\mathrm{4}}−\frac{\mathrm{3}}{\mathrm{4}} \\ $$
Question Number 62051 Answers: 0 Comments: 1
$$\frac{\mathrm{7}^{\mathrm{5}} }{\mathrm{7}^{\mathrm{3}} } \\ $$
Question Number 62050 Answers: 0 Comments: 1
$$\left[\mathrm{3}×\mathrm{5}+\mathrm{3}\right]+\left[\mathrm{3}+\left(\mathrm{3}×\mathrm{2}\right)\right] \\ $$
Question Number 62049 Answers: 0 Comments: 1
$$\frac{\mathrm{1}}{\mathrm{4}}+\frac{\mathrm{1}}{\mathrm{5}} \\ $$
Question Number 62048 Answers: 0 Comments: 1
$$\left(\frac{\mathrm{1}}{\mathrm{2}}\right)^{\mathrm{3}} \\ $$
Question Number 62047 Answers: 0 Comments: 1
$$\left(\mathrm{4y}\right)^{\mathrm{2}} \\ $$
Question Number 62045 Answers: 1 Comments: 0
$$\mathrm{help} \\ $$$$ \\ $$$$\left(\mathrm{x}+\mathrm{1}\right)^{\mathrm{1}/\mathrm{2}} +\left(\mathrm{x}^{\mathrm{2}} −\mathrm{1}\right)^{\mathrm{1}/\mathrm{3}} =\mathrm{4} \\ $$$$\mathrm{find}\:\mathrm{x} \\ $$
Question Number 62041 Answers: 0 Comments: 2
Question Number 62037 Answers: 1 Comments: 0
$$\mathrm{3}{no}_{\mathrm{2}} +{h}_{\mathrm{2}} {o}\Rightarrow\mathrm{2}{hno}_{\mathrm{3}} +{no} \\ $$$$ \\ $$
Question Number 62036 Answers: 0 Comments: 3
$$\mathrm{Correct}\:\mathrm{me}\:\mathrm{if}\:\mathrm{I}\:\mathrm{am}\:\mathrm{wrong}. \\ $$$$\underset{\sqrt{−\mathrm{1}}=\mathrm{1}} {\overset{\mathrm{3}} {\sum}}\mathrm{x}_{\sqrt{−\mathrm{1}}} +\mathrm{y}_{\sqrt{−\mathrm{1}}} \\ $$$$\therefore\left({i}=\sqrt{−\mathrm{1}}\right) \\ $$$$ \\ $$
Question Number 62035 Answers: 0 Comments: 0
$${study}\:{the}\:{sequence}\:\:{U}_{{n}+\mathrm{1}} =\sqrt{{U}_{{n}} \:+\frac{\mathrm{1}}{{n}+\mathrm{1}}}\:\:{with}\:\:{U}_{\mathrm{0}} =\mathrm{1}\:. \\ $$
Question Number 62034 Answers: 0 Comments: 0
$${calculate}\:\:\int_{\mathrm{0}} ^{\mathrm{1}} \:\:\:\:\frac{{x}^{\mathrm{3}} }{\mathrm{2}{e}^{−{x}} −{x}^{\mathrm{2}} +\mathrm{2}{x}−\mathrm{2}}\:{dx} \\ $$
Question Number 62024 Answers: 0 Comments: 0
Question Number 62023 Answers: 3 Comments: 3
Question Number 62022 Answers: 1 Comments: 0
Question Number 62019 Answers: 0 Comments: 1
Question Number 62016 Answers: 0 Comments: 1
$${the}\:\mathrm{2}\:{and}\:\mathrm{3}\:{term}\:{of}\:{GP}\:\:{is}\:\mathrm{24} \\ $$$${and}\:\mathrm{12}\left({x}+\mathrm{1}\right).{If}\:{the}\:{sum}\:{of}\:{the}\: \\ $$$${first}\:\mathrm{3}\:{terms}\:{is}\:\mathrm{76}.{Find}\:{the}\:{value} \\ $$$${of}\:{x} \\ $$
Question Number 62014 Answers: 1 Comments: 0
Question Number 62010 Answers: 0 Comments: 0
$${if}\: \\ $$$$ \\ $$$${x}^{\mathrm{2}} +{y}^{\mathrm{2}} +{z}^{\mathrm{2}} −\mathrm{2}{xyz}=\mathrm{1} \\ $$$${prove}\:{that} \\ $$$$ \\ $$$$\frac{{dx}}{\sqrt{\mathrm{1}−{x}^{\mathrm{2}} }}\:+\:\frac{{dy}}{\sqrt{\mathrm{1}−{y}^{\mathrm{2}} }}\:+\:\frac{{dz}}{\sqrt{\mathrm{1}−{z}^{\mathrm{2}} }}\:=\:\mathrm{0} \\ $$
Question Number 62003 Answers: 0 Comments: 0
$${let}\:\xi\left({x}\right)\:=\sum_{{n}=\mathrm{1}} ^{\infty} \:\frac{\mathrm{1}}{{n}^{{x}} }\:\:\:{with}\:{x}>\mathrm{1}\:\:{prove}\:{that}\:\:\xi\left({x}\right)\:=\prod_{{p}\:{prime}} \:\:\:\:\:\:\frac{\mathrm{1}}{\mathrm{1}−{p}^{−{x}} } \\ $$
Question Number 62002 Answers: 0 Comments: 0
Question Number 62001 Answers: 0 Comments: 1
$${find}\:\:\int_{\mathrm{0}} ^{\frac{\pi}{\mathrm{4}}} \:\:\:\frac{{x}^{\mathrm{2}} }{\mathrm{1}−{cos}\left({x}\right)}{dx}\: \\ $$
Question Number 62000 Answers: 0 Comments: 0
$${calculate}\:\int_{\mathrm{0}} ^{\mathrm{1}} \:\:{ln}\left(\mathrm{1}+{x}\right){ln}^{\mathrm{2}} \left(\mathrm{1}−{x}\right){dx} \\ $$
Question Number 61994 Answers: 1 Comments: 1
Question Number 61993 Answers: 1 Comments: 0
$${ultraviolet}\:{light}\:{of}\:{wavelength}\:\mathrm{300}×\mathrm{10}^{−\mathrm{9}} {m} \\ $$$${causes}\:{photon}\:{emissions}\:{from}\:{a}\:{surface} \\ $$$${The}\:{stopping}\:{potential}\:{is}\:\mathrm{6}{V}.{Find}\:{the} \\ $$$${work}-{function}\:{in}\:{electron}-{Volts} \\ $$
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