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Question Number 64150 Answers: 1 Comments: 2

calculate ∫_(−∞) ^(+∞) (dx/((x^2 +1)(x^2 +2)(x^2 +3)))

$${calculate}\:\int_{−\infty} ^{+\infty} \:\:\:\frac{{dx}}{\left({x}^{\mathrm{2}} +\mathrm{1}\right)\left({x}^{\mathrm{2}} +\mathrm{2}\right)\left({x}^{\mathrm{2}} +\mathrm{3}\right)} \\ $$

Question Number 64147 Answers: 2 Comments: 0

Question Number 64139 Answers: 1 Comments: 2

∫_( 0) ^1 (dx/(x^2 +2x cos α+1)) = α sin α

$$\underset{\:\mathrm{0}} {\overset{\mathrm{1}} {\int}}\:\:\:\frac{{dx}}{{x}^{\mathrm{2}} +\mathrm{2}{x}\:\mathrm{cos}\:\alpha+\mathrm{1}}\:=\:\alpha\:\mathrm{sin}\:\alpha \\ $$

Question Number 64138 Answers: 1 Comments: 0

Question Number 64130 Answers: 2 Comments: 1

(√(4x+((12)/x)))=((x^2 +7)/(x+1)) x=?

$$\sqrt{\mathrm{4}\boldsymbol{\mathrm{x}}+\frac{\mathrm{12}}{\boldsymbol{\mathrm{x}}}}=\frac{\boldsymbol{\mathrm{x}}^{\mathrm{2}} +\mathrm{7}}{\boldsymbol{\mathrm{x}}+\mathrm{1}} \\ $$$$\boldsymbol{\mathrm{x}}=? \\ $$

Question Number 64129 Answers: 0 Comments: 0

Question Number 64126 Answers: 1 Comments: 0

Question Number 64124 Answers: 0 Comments: 0

(√(2014))x^3 −4029x^2 +2=0 x_1 <x_2 <x_3 x_2 (x_1 +x_3 )=?

$$\sqrt{\mathrm{2014}}\boldsymbol{\mathrm{x}}^{\mathrm{3}} −\mathrm{4029}\boldsymbol{\mathrm{x}}^{\mathrm{2}} +\mathrm{2}=\mathrm{0} \\ $$$$\boldsymbol{\mathrm{x}}_{\mathrm{1}} <\boldsymbol{\mathrm{x}}_{\mathrm{2}} <\boldsymbol{\mathrm{x}}_{\mathrm{3}} \\ $$$$\boldsymbol{\mathrm{x}}_{\mathrm{2}} \left(\boldsymbol{\mathrm{x}}_{\mathrm{1}} +\boldsymbol{\mathrm{x}}_{\mathrm{3}} \right)=? \\ $$

Question Number 64122 Answers: 0 Comments: 0

∫tan(1/x)dx

$$\int{tan}\left(\mathrm{1}/{x}\right){dx} \\ $$

Question Number 64121 Answers: 0 Comments: 0

∫tan(1/x)dx

$$\int{tan}\left(\mathrm{1}/{x}\right){dx} \\ $$

Question Number 64119 Answers: 3 Comments: 1

Question Number 64111 Answers: 0 Comments: 0

Question Number 64112 Answers: 2 Comments: 1

Question Number 64106 Answers: 0 Comments: 0

∫tan(1/x)dx

$$\int{tan}\left(\mathrm{1}/{x}\right){dx} \\ $$

Question Number 64105 Answers: 0 Comments: 0

∫tan(1/x)dx

$$\int{tan}\left(\mathrm{1}/{x}\right){dx} \\ $$

Question Number 64104 Answers: 0 Comments: 0

∫tan(1/x)dx

$$\int{tan}\left(\mathrm{1}/{x}\right){dx} \\ $$

Question Number 64103 Answers: 0 Comments: 0

∫tan(1/x)dx

$$\int{tan}\left(\mathrm{1}/{x}\right){dx} \\ $$

Question Number 64102 Answers: 0 Comments: 0

∫tan(1/x)dx

$$\int{tan}\left(\mathrm{1}/{x}\right){dx} \\ $$

Question Number 64101 Answers: 0 Comments: 1

why the first ionisation(△H_(i1) )energy of Oxygen smaller than the second? A. Due to the nuclear charge B. Due to the distance of the electron from the nucleus C. Due to the effect of spin−pair repulsion D. Due to a shielding effect.

$${why}\:{the}\:{first}\:{ionisation}\left(\bigtriangleup{H}_{{i}\mathrm{1}} \right){energy}\:{of}\:{Oxygen}\:{smaller} \\ $$$${than}\:{the}\:{second}? \\ $$$${A}.\:{Due}\:{to}\:{the}\:{nuclear}\:{charge} \\ $$$${B}.\:{Due}\:{to}\:{the}\:{distance}\:{of}\:{the}\:{electron}\:{from}\:{the}\:{nucleus} \\ $$$${C}.\:{Due}\:{to}\:{the}\:{effect}\:{of}\:{spin}−{pair}\:{repulsion} \\ $$$${D}.\:{Due}\:{to}\:{a}\:{shielding}\:{effect}. \\ $$

Question Number 64097 Answers: 1 Comments: 1

Question Number 64092 Answers: 1 Comments: 0

prove that u=mgh

$${prove}\:{that}\: \\ $$$${u}={mgh} \\ $$

Question Number 64085 Answers: 0 Comments: 0

please just read equation of a line and a plane in vectors. i don′t understand (r−a)×b=0 ??

$${please}\:{just}\:{read}\:{equation}\:{of}\:{a}\:{line}\:{and}\:{a}\:{plane}\:{in}\:{vectors}. \\ $$$${i}\:{don}'{t}\:{understand}\: \\ $$$$\:\:\left(\boldsymbol{{r}}−\boldsymbol{{a}}\right)×\boldsymbol{{b}}=\mathrm{0}\:\:?? \\ $$

Question Number 64086 Answers: 0 Comments: 5

if 3x + 5y = 1 use Bezout′s identity to find the value of x and y

$${if}\:\:\:\mathrm{3}{x}\:+\:\mathrm{5}{y}\:=\:\mathrm{1} \\ $$$${use}\:{Bezout}'{s}\:{identity}\:{to}\:{find}\:{the}\:{value}\:{of}\:{x}\:{and}\:{y} \\ $$

Question Number 64081 Answers: 0 Comments: 0

∫e^(sec x) ∙ sec^3 x(sin^2 x+cos x+sin x+sin x cos x) dx=

$$\int{e}^{\mathrm{sec}\:{x}} \centerdot\:\mathrm{sec}^{\mathrm{3}} {x}\left(\mathrm{sin}^{\mathrm{2}} {x}+\mathrm{cos}\:{x}+\mathrm{sin}\:{x}+\mathrm{sin}\:{x}\:\mathrm{cos}\:{x}\right)\:{dx}= \\ $$

Question Number 64080 Answers: 1 Comments: 2

∫((sin x−cos x)/(√(1−sin 2x))) e^(sin x) cos x dx =

$$\int\frac{\mathrm{sin}\:{x}−\mathrm{cos}\:{x}}{\sqrt{\mathrm{1}−\mathrm{sin}\:\mathrm{2}{x}}}\:{e}^{\mathrm{sin}\:{x}} \mathrm{cos}\:{x}\:{dx}\:= \\ $$

Question Number 64079 Answers: 0 Comments: 0

∫_( 0) ^π ((x sin x)/(1+cos^2 x)) dx =

$$\underset{\:\mathrm{0}} {\overset{\pi} {\int}}\:\:\frac{{x}\:\mathrm{sin}\:{x}}{\mathrm{1}+\mathrm{cos}^{\mathrm{2}} {x}}\:{dx}\:= \\ $$

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