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Question Number 64253    Answers: 0   Comments: 1

Question Number 64251    Answers: 0   Comments: 0

Question Number 64250    Answers: 0   Comments: 0

Question Number 64246    Answers: 3   Comments: 0

Question Number 64240    Answers: 1   Comments: 0

Question Number 64238    Answers: 0   Comments: 2

∫ln(x−5)/x^2 +110x−5dx

$$\int{ln}\left({x}−\mathrm{5}\right)/{x}^{\mathrm{2}} +\mathrm{110}{x}−\mathrm{5}{dx} \\ $$

Question Number 64227    Answers: 1   Comments: 0

∫(1/(x^6 +x^3 ))dx=?

$$\int\frac{\mathrm{1}}{{x}^{\mathrm{6}} +{x}^{\mathrm{3}} }{dx}=? \\ $$

Question Number 64225    Answers: 1   Comments: 0

Solution of the equation ∫_(√2) ^x (dx/(x (√(x^2 −1)))) = (π/(12)) is x = _____.

$$\mathrm{Solution}\:\mathrm{of}\:\mathrm{the}\:\mathrm{equation} \\ $$$$\underset{\sqrt{\mathrm{2}}} {\overset{{x}} {\int}}\:\:\:\frac{{dx}}{{x}\:\sqrt{{x}^{\mathrm{2}} −\mathrm{1}}}\:=\:\frac{\pi}{\mathrm{12}}\:\:\mathrm{is}\:\:{x}\:=\:\_\_\_\_\_. \\ $$

Question Number 64224    Answers: 0   Comments: 1

∫x_x dx ∫x^x dx

$$\int{x}_{{x}} {dx} \\ $$$$ \\ $$$$\int{x}^{{x}} {dx} \\ $$

Question Number 64213    Answers: 0   Comments: 2

∫(1/(x!))dx=?

$$\int\frac{\mathrm{1}}{{x}!}{dx}=? \\ $$

Question Number 64267    Answers: 1   Comments: 1

If ∫_( 0) ^π (1/(a+b cos x)) dx, a>0 is equal to (π/(√(a^2 −b^2 ))) , then ∫_( 0) ^π (1/((a+b cos x)^2 )) dx =

$$\mathrm{If}\:\underset{\:\mathrm{0}} {\overset{\pi} {\int}}\:\:\frac{\mathrm{1}}{{a}+{b}\:\mathrm{cos}\:{x}}\:{dx},\:{a}>\mathrm{0}\:\mathrm{is}\:\mathrm{equal}\:\mathrm{to}\:\frac{\pi}{\sqrt{{a}^{\mathrm{2}} −{b}^{\mathrm{2}} }}\:, \\ $$$$\mathrm{then}\:\underset{\:\mathrm{0}} {\overset{\pi} {\int}}\:\:\:\frac{\mathrm{1}}{\left({a}+{b}\:\mathrm{cos}\:{x}\right)^{\mathrm{2}} }\:{dx}\:= \\ $$

Question Number 64266    Answers: 1   Comments: 0

∫_(1/e) ^e ∣ log x ∣ dx =

$$\:\underset{\mathrm{1}/{e}} {\overset{{e}} {\int}}\:\mid\:\mathrm{log}\:{x}\:\mid\:{dx}\:= \\ $$

Question Number 64265    Answers: 1   Comments: 2

If ∫_(log 2) ^x (1/(√(e^x −1))) dx = (π/6), then x =

$$\mathrm{If}\:\underset{\mathrm{log}\:\mathrm{2}} {\overset{{x}} {\int}}\:\:\frac{\mathrm{1}}{\sqrt{{e}^{{x}} −\mathrm{1}}}\:{dx}\:=\:\frac{\pi}{\mathrm{6}},\:\mathrm{then}\:{x}\:= \\ $$

Question Number 64218    Answers: 0   Comments: 4

so goodbye everybody i am leaving this platform

$${so}\:{goodbye}\:{everybody}\:{i}\:{am}\:{leaving}\:{this}\:{platform} \\ $$

Question Number 64269    Answers: 1   Comments: 0

∫_(−π) ^π [cos px−sin qx]^2 dx, where p, q are integers is equal to

$$\underset{−\pi} {\overset{\pi} {\int}}\:\left[\mathrm{cos}\:{px}−\mathrm{sin}\:{qx}\right]^{\mathrm{2}} {dx},\:\mathrm{where}\:{p},\:{q}\:\mathrm{are}\: \\ $$$$\mathrm{integers}\:\mathrm{is}\:\mathrm{equal}\:\mathrm{to} \\ $$

Question Number 64268    Answers: 0   Comments: 1

lim_(n→∞) ((1^(99) +2^(99) +...+ n^(99) )/n^(100) ) =

$$\underset{{n}\rightarrow\infty} {\mathrm{lim}}\:\frac{\mathrm{1}^{\mathrm{99}} +\mathrm{2}^{\mathrm{99}} +...+\:{n}^{\mathrm{99}} }{{n}^{\mathrm{100}} }\:= \\ $$

Question Number 64270    Answers: 1   Comments: 0

∫((5sin(x) cos(x))/((cos(x)+1))^(1/3) ) dx

$$\int\frac{\mathrm{5}{sin}\left({x}\right)\:{cos}\left({x}\right)}{\sqrt[{\mathrm{3}}]{{cos}\left({x}\right)+\mathrm{1}}}\:{dx} \\ $$

Question Number 64204    Answers: 1   Comments: 1

Question Number 64203    Answers: 1   Comments: 5

M is the midpoint of segment AB. Prove that,for every point P in space, ∣PM∣ ≤ ((∣PA∣ +∣PB∣)/2)

$$\mathrm{M}\:\mathrm{is}\:\mathrm{the}\:\mathrm{midpoint}\:\mathrm{of}\:\mathrm{segment}\:\mathrm{AB}.\:\mathrm{Prove} \\ $$$$\mathrm{that},\mathrm{for}\:\mathrm{every}\:\mathrm{point}\:\mathrm{P}\:\mathrm{in}\:\mathrm{space}, \\ $$$$\mid\mathrm{PM}\mid\:\leqslant\:\frac{\mid\mathrm{PA}\mid\:+\mid\mathrm{PB}\mid}{\mathrm{2}} \\ $$

Question Number 64202    Answers: 0   Comments: 0

Prove 385^(1980) +18^(1980) is not a square.

$$\mathrm{Prove}\:\mathrm{385}^{\mathrm{1980}} +\mathrm{18}^{\mathrm{1980}} \:\mathrm{is}\:\mathrm{not}\:\mathrm{a}\:\mathrm{square}.\: \\ $$

Question Number 64201    Answers: 2   Comments: 0

Find all positive solutions x+y+z = 1 x^3 +y^3 + z^3 + xyz = x^4 + y^4 + z^4 +1

$$\mathrm{Find}\:\mathrm{all}\:\mathrm{positive}\:\mathrm{solutions}\: \\ $$$$\mathrm{x}+\mathrm{y}+\mathrm{z}\:=\:\mathrm{1} \\ $$$$\mathrm{x}^{\mathrm{3}} +\mathrm{y}^{\mathrm{3}} +\:\mathrm{z}^{\mathrm{3}} \:+\:\mathrm{xyz}\:=\:\mathrm{x}^{\mathrm{4}} \:+\:\mathrm{y}^{\mathrm{4}} \:+\:\mathrm{z}^{\mathrm{4}} \:+\mathrm{1} \\ $$

Question Number 64200    Answers: 1   Comments: 1

Question Number 64187    Answers: 1   Comments: 0

Question Number 64186    Answers: 1   Comments: 0

Question Number 64185    Answers: 2   Comments: 3

Question Number 64176    Answers: 1   Comments: 0

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