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Question Number 68414 Answers: 2 Comments: 1

Is it possible to find any value for a,b,c from below system of equetions? { ((sina+sinb=sinc)),((cosa+cosb=cosc)) :}

$$\mathrm{Is}\:\mathrm{it}\:\mathrm{possible}\:\mathrm{to}\:\mathrm{find}\:\mathrm{any}\:\mathrm{value}\:\mathrm{for} \\ $$$$\boldsymbol{\mathrm{a}},\boldsymbol{\mathrm{b}},\boldsymbol{\mathrm{c}}\:\mathrm{from}\:\mathrm{below}\:\mathrm{system}\:\mathrm{of}\:\mathrm{equetions}? \\ $$$$\begin{cases}{\boldsymbol{\mathrm{sina}}+\boldsymbol{\mathrm{sinb}}=\boldsymbol{\mathrm{sinc}}}\\{\boldsymbol{\mathrm{cosa}}+\boldsymbol{\mathrm{cosb}}=\boldsymbol{\mathrm{cosc}}}\end{cases} \\ $$

Question Number 68409 Answers: 1 Comments: 3

calculate ∫_0 ^(+∞) ((arctan(x^2 ))/(1+x^2 ))dx

$${calculate}\:\int_{\mathrm{0}} ^{+\infty} \:\:\frac{{arctan}\left({x}^{\mathrm{2}} \right)}{\mathrm{1}+{x}^{\mathrm{2}} }{dx} \\ $$

Question Number 68405 Answers: 1 Comments: 3

There are a few problem reported. Notification: google discontinued Google Cloud Messaging so notifications are not working. Other Problems: There has been several new phone models and android version updates. And newer android version or phone models might have other issues. We are working on app updates for supporting these and also migrating to new messaging platform. We will address these problems as soon as we can.

$$\mathrm{There}\:\mathrm{are}\:\mathrm{a}\:\mathrm{few}\:\mathrm{problem}\:\mathrm{reported}. \\ $$$$\mathrm{Notification}:\:\mathrm{google}\:\mathrm{discontinued} \\ $$$$\mathrm{Google}\:\mathrm{Cloud}\:\mathrm{Messaging}\:\mathrm{so}\:\mathrm{notifications} \\ $$$$\mathrm{are}\:\mathrm{not}\:\mathrm{working}.\: \\ $$$$\mathrm{Other}\:\mathrm{Problems}: \\ $$$$\mathrm{There}\:\mathrm{has}\:\mathrm{been}\:\mathrm{several}\:\mathrm{new}\:\mathrm{phone} \\ $$$$\mathrm{models}\:\mathrm{and}\:\mathrm{android}\:\mathrm{version}\:\mathrm{updates}. \\ $$$$\mathrm{And}\:\mathrm{newer}\:\mathrm{android}\:\mathrm{version}\:\mathrm{or}\:\mathrm{phone} \\ $$$$\mathrm{models}\:\mathrm{might}\:\mathrm{have}\:\mathrm{other}\:\mathrm{issues}. \\ $$$$ \\ $$$$\mathrm{We}\:\mathrm{are}\:\mathrm{working}\:\mathrm{on}\:\mathrm{app}\:\mathrm{updates}\:\mathrm{for} \\ $$$$\mathrm{supporting}\:\mathrm{these}\:\mathrm{and}\:\mathrm{also}\:\mathrm{migrating} \\ $$$$\mathrm{to}\:\mathrm{new}\:\mathrm{messaging}\:\mathrm{platform}. \\ $$$$ \\ $$$$\mathrm{We}\:\mathrm{will}\:\mathrm{address}\:\mathrm{these}\:\mathrm{problems}\:\mathrm{as}\: \\ $$$$\mathrm{soon}\:\mathrm{as}\:\mathrm{we}\:\mathrm{can}. \\ $$

Question Number 68397 Answers: 2 Comments: 0

Question Number 68390 Answers: 1 Comments: 0

Question Number 68370 Answers: 1 Comments: 0

Question Number 68368 Answers: 1 Comments: 1

(1/(x+1)) = y lim_(x+1 → ∞) x tan ((1/(2x+2)))

$$\frac{\mathrm{1}}{{x}+\mathrm{1}}\:=\:{y} \\ $$$$\underset{{x}+\mathrm{1}\:\rightarrow\:\infty} {\mathrm{lim}}\:\:{x}\:\mathrm{tan}\:\left(\frac{\mathrm{1}}{\mathrm{2}{x}+\mathrm{2}}\right) \\ $$

Question Number 68354 Answers: 0 Comments: 6

lim_(x,y→(0,0)) ((x^4 − x^2 y^2 + y^4 )/(x^2 + x^4 y^4 + y^2 ))

$$\underset{{x},\mathrm{y}\rightarrow\left(\mathrm{0},\mathrm{0}\right)} {\mathrm{lim}}\:\frac{\mathrm{x}^{\mathrm{4}} \:−\:\mathrm{x}^{\mathrm{2}} \mathrm{y}^{\mathrm{2}} \:+\:\mathrm{y}^{\mathrm{4}} }{\mathrm{x}^{\mathrm{2}} \:+\:\mathrm{x}^{\mathrm{4}} \mathrm{y}^{\mathrm{4}} \:+\:\mathrm{y}^{\mathrm{2}} } \\ $$

Question Number 68353 Answers: 1 Comments: 0

If sin x+sin^2 x=1, then value of cos^2 x+cos^4 x is

$$\mathrm{If}\:\mathrm{sin}\:{x}+\mathrm{sin}^{\mathrm{2}} {x}=\mathrm{1},\:\mathrm{then}\:\mathrm{value}\:\mathrm{of} \\ $$$$\mathrm{cos}^{\mathrm{2}} {x}+\mathrm{cos}^{\mathrm{4}} {x}\:\:\mathrm{is} \\ $$

Question Number 68352 Answers: 1 Comments: 0

The value of ((1−tan^2 15°)/(1+tan^2 15°)) is

$$\mathrm{The}\:\mathrm{value}\:\mathrm{of}\:\:\frac{\mathrm{1}−\mathrm{tan}^{\mathrm{2}} \mathrm{15}°}{\mathrm{1}+\mathrm{tan}^{\mathrm{2}} \mathrm{15}°}\:\:\mathrm{is} \\ $$

Question Number 68351 Answers: 2 Comments: 0

If 2x^2 +(2p−13)x+2=0 is exactly divisible by x−3, then the value of p is

$$\mathrm{If}\:\mathrm{2}{x}^{\mathrm{2}} +\left(\mathrm{2}{p}−\mathrm{13}\right){x}+\mathrm{2}=\mathrm{0}\:\mathrm{is}\:\mathrm{exactly}\:\mathrm{divisible} \\ $$$$\mathrm{by}\:{x}−\mathrm{3},\:\mathrm{then}\:\mathrm{the}\:\mathrm{value}\:\mathrm{of}\:{p}\:\mathrm{is} \\ $$

Question Number 68350 Answers: 1 Comments: 2

Question Number 68349 Answers: 1 Comments: 0

Question Number 68346 Answers: 0 Comments: 0

Question Number 68342 Answers: 3 Comments: 1

Question Number 68336 Answers: 1 Comments: 1

A man gave $5,720.00 to be shared among his son and three daughters. If each of the daughter′s share is (3/4) of the son′s share, how much did the son receive?

$$\mathrm{A}\:\mathrm{man}\:\mathrm{gave}\:\$\mathrm{5},\mathrm{720}.\mathrm{00}\:\mathrm{to}\:\mathrm{be}\:\mathrm{shared}\:\mathrm{among} \\ $$$$\mathrm{his}\:\mathrm{son}\:\mathrm{and}\:\mathrm{three}\:\mathrm{daughters}.\:\mathrm{If}\:\mathrm{each}\:\mathrm{of} \\ $$$$\mathrm{the}\:\mathrm{daughter}'\mathrm{s}\:\mathrm{share}\:\mathrm{is}\:\frac{\mathrm{3}}{\mathrm{4}}\:\mathrm{of}\:\mathrm{the}\:\mathrm{son}'\mathrm{s}\:\mathrm{share}, \\ $$$$\mathrm{how}\:\mathrm{much}\:\mathrm{did}\:\mathrm{the}\:\mathrm{son}\:\mathrm{receive}? \\ $$

Question Number 68331 Answers: 2 Comments: 0

Differentiate y=ln tan^(−1) (3x^2 )_

$${Differentiate}\:{y}={ln}\:\mathrm{tan}^{−\mathrm{1}} \left(\mathrm{3}{x}^{\mathrm{2}} \underset{} {\right)} \\ $$

Question Number 68329 Answers: 0 Comments: 0

y=ln (sinx+x^2 )

$${y}=\mathrm{ln}\:\left({sinx}+{x}^{\mathrm{2}} \right) \\ $$

Question Number 68327 Answers: 1 Comments: 0

y=(1−2x^(−7) )^3

$${y}=\left(\mathrm{1}−\mathrm{2}{x}^{−\mathrm{7}} \right)^{\mathrm{3}} \\ $$

Question Number 68316 Answers: 0 Comments: 1

∫(4sin 3x+(e^(4x) /4))