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Question Number 71918    Answers: 2   Comments: 2

If Cosθ=((x cosβ − y)/(x − y cosβ)) then prove that, tan(θ/2) =(√(((x−y)/(x+y)) )) tan(β/2)

$$\mathrm{If}\:\mathrm{Cos}\theta=\frac{\mathrm{x}\:\mathrm{cos}\beta\:−\:\mathrm{y}}{\mathrm{x}\:−\:\mathrm{y}\:\mathrm{cos}\beta}\:\:\mathrm{then}\:\mathrm{prove}\:\mathrm{that},\:\mathrm{tan}\frac{\theta}{\mathrm{2}}\:=\sqrt{\frac{\mathrm{x}−\mathrm{y}}{\mathrm{x}+\mathrm{y}}\:}\:\mathrm{tan}\frac{\beta}{\mathrm{2}} \\ $$

Question Number 69667    Answers: 1   Comments: 0

Question Number 69665    Answers: 1   Comments: 1

Question Number 69662    Answers: 1   Comments: 0

prove that ((2x^3 −x^2 −2x+1)/(x^3 +1)) + ((x^3 +1)/(x^4 −2x^3 +3x^2 −2x+1)) = 2

$${prove}\:{that} \\ $$$$ \\ $$$$\frac{\mathrm{2}{x}^{\mathrm{3}} −{x}^{\mathrm{2}} −\mathrm{2}{x}+\mathrm{1}}{{x}^{\mathrm{3}} +\mathrm{1}}\:+\:\frac{{x}^{\mathrm{3}} +\mathrm{1}}{{x}^{\mathrm{4}} −\mathrm{2}{x}^{\mathrm{3}} +\mathrm{3}{x}^{\mathrm{2}} −\mathrm{2}{x}+\mathrm{1}}\:=\:\mathrm{2} \\ $$

Question Number 69645    Answers: 1   Comments: 0

Question Number 69644    Answers: 2   Comments: 0

Question Number 69643    Answers: 1   Comments: 0

Question Number 69641    Answers: 0   Comments: 0

Solve arctg(1−x) + (1/(arcctg(1+x))) = (𝛑/4)

$$\boldsymbol{{Solve}}\:\:\boldsymbol{{arctg}}\left(\mathrm{1}−\boldsymbol{{x}}\right)\:+\:\frac{\mathrm{1}}{\boldsymbol{{arcctg}}\left(\mathrm{1}+\boldsymbol{{x}}\right)}\:=\:\frac{\boldsymbol{\pi}}{\mathrm{4}} \\ $$

Question Number 69637    Answers: 1   Comments: 0

...now try this one: ∫(dx/(x^(1/2) −x^(1/3) −x^(1/6) ))=

$$...\mathrm{now}\:\mathrm{try}\:\mathrm{this}\:\mathrm{one}: \\ $$$$\int\frac{{dx}}{{x}^{\mathrm{1}/\mathrm{2}} −{x}^{\mathrm{1}/\mathrm{3}} −{x}^{\mathrm{1}/\mathrm{6}} }= \\ $$

Question Number 69623    Answers: 1   Comments: 0

∫(1/((√x) + (x)^(1/3) )) dx

$$\int\frac{\mathrm{1}}{\sqrt{{x}}\:+\:\sqrt[{\mathrm{3}}]{{x}}}\:{dx} \\ $$

Question Number 69616    Answers: 0   Comments: 4

Question Number 69606    Answers: 0   Comments: 0

Question Number 69603    Answers: 1   Comments: 0

∫ x^3 arcsinxdx

$$\int\:{x}^{\mathrm{3}} {arcsinxdx} \\ $$

Question Number 69597    Answers: 1   Comments: 1

Question Number 69594    Answers: 1   Comments: 0

Question Number 69593    Answers: 1   Comments: 2

Question Number 69576    Answers: 1   Comments: 1

∫_(−2) ^( 2) (x^3 cos(x/2)+(1/2))(√(4−x^2 ))dx

$$\int_{−\mathrm{2}} ^{\:\mathrm{2}} \left({x}^{\mathrm{3}} {cos}\frac{{x}}{\mathrm{2}}+\frac{\mathrm{1}}{\mathrm{2}}\right)\sqrt{\mathrm{4}−{x}^{\mathrm{2}} }{dx} \\ $$

Question Number 69574    Answers: 1   Comments: 0

Question Number 69573    Answers: 0   Comments: 1

Question Number 69572    Answers: 1   Comments: 0

Question Number 69571    Answers: 1   Comments: 0

Question Number 69570    Answers: 0   Comments: 0

Question Number 69569    Answers: 2   Comments: 0

Question Number 69568    Answers: 1   Comments: 3

Question Number 69567    Answers: 0   Comments: 2

Question Number 69566    Answers: 1   Comments: 0

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