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Question Number 64126 Answers: 1 Comments: 0
Question Number 64124 Answers: 0 Comments: 0
$$\sqrt{\mathrm{2014}}\boldsymbol{\mathrm{x}}^{\mathrm{3}} −\mathrm{4029}\boldsymbol{\mathrm{x}}^{\mathrm{2}} +\mathrm{2}=\mathrm{0} \\ $$$$\boldsymbol{\mathrm{x}}_{\mathrm{1}} <\boldsymbol{\mathrm{x}}_{\mathrm{2}} <\boldsymbol{\mathrm{x}}_{\mathrm{3}} \\ $$$$\boldsymbol{\mathrm{x}}_{\mathrm{2}} \left(\boldsymbol{\mathrm{x}}_{\mathrm{1}} +\boldsymbol{\mathrm{x}}_{\mathrm{3}} \right)=? \\ $$
Question Number 64122 Answers: 0 Comments: 0
$$\int{tan}\left(\mathrm{1}/{x}\right){dx} \\ $$
Question Number 64121 Answers: 0 Comments: 0
Question Number 64119 Answers: 3 Comments: 1
Question Number 64111 Answers: 0 Comments: 0
Question Number 64112 Answers: 2 Comments: 1
Question Number 64106 Answers: 0 Comments: 0
Question Number 64105 Answers: 0 Comments: 0
Question Number 64104 Answers: 0 Comments: 0
Question Number 64103 Answers: 0 Comments: 0
Question Number 64102 Answers: 0 Comments: 0
Question Number 64101 Answers: 0 Comments: 1
$${why}\:{the}\:{first}\:{ionisation}\left(\bigtriangleup{H}_{{i}\mathrm{1}} \right){energy}\:{of}\:{Oxygen}\:{smaller} \\ $$$${than}\:{the}\:{second}? \\ $$$${A}.\:{Due}\:{to}\:{the}\:{nuclear}\:{charge} \\ $$$${B}.\:{Due}\:{to}\:{the}\:{distance}\:{of}\:{the}\:{electron}\:{from}\:{the}\:{nucleus} \\ $$$${C}.\:{Due}\:{to}\:{the}\:{effect}\:{of}\:{spin}−{pair}\:{repulsion} \\ $$$${D}.\:{Due}\:{to}\:{a}\:{shielding}\:{effect}. \\ $$
Question Number 64097 Answers: 1 Comments: 1
Question Number 64092 Answers: 1 Comments: 0
$${prove}\:{that}\: \\ $$$${u}={mgh} \\ $$
Question Number 64085 Answers: 0 Comments: 0
$${please}\:{just}\:{read}\:{equation}\:{of}\:{a}\:{line}\:{and}\:{a}\:{plane}\:{in}\:{vectors}. \\ $$$${i}\:{don}'{t}\:{understand}\: \\ $$$$\:\:\left(\boldsymbol{{r}}−\boldsymbol{{a}}\right)×\boldsymbol{{b}}=\mathrm{0}\:\:?? \\ $$
Question Number 64086 Answers: 0 Comments: 5
$${if}\:\:\:\mathrm{3}{x}\:+\:\mathrm{5}{y}\:=\:\mathrm{1} \\ $$$${use}\:{Bezout}'{s}\:{identity}\:{to}\:{find}\:{the}\:{value}\:{of}\:{x}\:{and}\:{y} \\ $$
Question Number 64081 Answers: 0 Comments: 0
$$\int{e}^{\mathrm{sec}\:{x}} \centerdot\:\mathrm{sec}^{\mathrm{3}} {x}\left(\mathrm{sin}^{\mathrm{2}} {x}+\mathrm{cos}\:{x}+\mathrm{sin}\:{x}+\mathrm{sin}\:{x}\:\mathrm{cos}\:{x}\right)\:{dx}= \\ $$
Question Number 64080 Answers: 1 Comments: 2
$$\int\frac{\mathrm{sin}\:{x}−\mathrm{cos}\:{x}}{\sqrt{\mathrm{1}−\mathrm{sin}\:\mathrm{2}{x}}}\:{e}^{\mathrm{sin}\:{x}} \mathrm{cos}\:{x}\:{dx}\:= \\ $$
Question Number 64079 Answers: 0 Comments: 0
$$\underset{\:\mathrm{0}} {\overset{\pi} {\int}}\:\:\frac{{x}\:\mathrm{sin}\:{x}}{\mathrm{1}+\mathrm{cos}^{\mathrm{2}} {x}}\:{dx}\:= \\ $$
Question Number 64078 Answers: 0 Comments: 3
Question Number 64077 Answers: 0 Comments: 0
Question Number 64074 Answers: 0 Comments: 0
$${by}\:{using}\:{laplase}\:{transform}\:{find}\:{laplase}\left({tan}\left({t}\right)\right) \\ $$
Question Number 64068 Answers: 0 Comments: 1
$${calculate}\:\int_{\mathrm{0}} ^{\pi} \:\frac{{tsint}}{\mathrm{3}+{sin}^{\mathrm{2}} {t}}\:{dt}\: \\ $$
Question Number 64066 Answers: 1 Comments: 0
$${let}\:\alpha\:,\beta\:{and}\:\lambda\:{the}\:{roots}\:{of}\:{x}^{\mathrm{3}} +\mathrm{2}{x}−\mathrm{1}\:=\mathrm{0}\:{find}\:{the}\:{value}\:{of} \\ $$$${A}\:=\alpha^{\mathrm{2}} \:+\beta^{\mathrm{2}} \:+\lambda^{\mathrm{2}} \:{and}\:\:{B}\:=\alpha^{\mathrm{3}} \:+\beta^{\mathrm{3}} \:+\lambda^{\mathrm{3}} \:. \\ $$
Question Number 64065 Answers: 0 Comments: 3
$${calculate}\:\int_{\mathrm{0}} ^{\mathrm{1}} \:\frac{{ln}\left(\mathrm{1}+{x}\right)}{\mathrm{1}+{x}^{\mathrm{2}} }{dx} \\ $$
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