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Question Number 72259 Answers: 1 Comments: 0

∫yz dx +∫xz dy +∫xy dz pleas sir help me ?

$$\int{yz}\:{dx}\:+\int{xz}\:{dy}\:+\int{xy}\:{dz}\:\:\:\:{pleas}\:{sir}\:{help}\:{me}\:? \\ $$

Question Number 72286 Answers: 0 Comments: 0

Question Number 72247 Answers: 1 Comments: 0

Question Number 72232 Answers: 0 Comments: 6

to all those who deleted their posts after they had been answered: I will not answer you anymore this forum had been great but lately it has been filling with unpolite people I′m not a freebie solver for anybody′s homework

$$\mathrm{to}\:\mathrm{all}\:\mathrm{those}\:\mathrm{who}\:\mathrm{deleted}\:\mathrm{their}\:\mathrm{posts}\:\mathrm{after}\:\mathrm{they} \\ $$$$\mathrm{had}\:\mathrm{been}\:\mathrm{answered}:\:\mathrm{I}\:\mathrm{will}\:\mathrm{not}\:\mathrm{answer}\:\mathrm{you} \\ $$$$\mathrm{anymore} \\ $$$$\mathrm{this}\:\mathrm{forum}\:\mathrm{had}\:\mathrm{been}\:\mathrm{great}\:\mathrm{but}\:\mathrm{lately}\:\mathrm{it}\:\mathrm{has} \\ $$$$\mathrm{been}\:\mathrm{filling}\:\mathrm{with}\:\mathrm{unpolite}\:\mathrm{people} \\ $$$$\mathrm{I}'\mathrm{m}\:\mathrm{not}\:\mathrm{a}\:\mathrm{freebie}\:\mathrm{solver}\:\mathrm{for}\:\mathrm{anybody}'\mathrm{s}\:\mathrm{homework} \\ $$

Question Number 72251 Answers: 0 Comments: 1

Question Number 72250 Answers: 0 Comments: 2

f(x)=(ax+b)sin(x)+(cx+d)cos(x) and (dy/dx)=xcos(x) find a , b , c , d

$${f}\left({x}\right)=\left({ax}+{b}\right){sin}\left({x}\right)+\left({cx}+{d}\right){cos}\left({x}\right) \\ $$$${and}\:\:\:\frac{{dy}}{{dx}}={xcos}\left({x}\right) \\ $$$${find}\:\:{a}\:,\:{b}\:,\:{c}\:,\:{d} \\ $$$$ \\ $$$$ \\ $$

Question Number 72248 Answers: 1 Comments: 1

Question Number 72287 Answers: 0 Comments: 0

Question Number 72218 Answers: 0 Comments: 3

Question Number 72198 Answers: 1 Comments: 8

Question Number 72194 Answers: 2 Comments: 1

Question Number 72190 Answers: 1 Comments: 2

3^x +4^x =5^x

$$\mathrm{3}^{\mathrm{x}} +\mathrm{4}^{\mathrm{x}} =\mathrm{5}^{\mathrm{x}} \\ $$

Question Number 72185 Answers: 0 Comments: 2

Question Number 72390 Answers: 0 Comments: 1

calculate U_n =∫_0 ^∞ ((arctan(1+x^4 ))/((x^2 +n^2 )^3 ))dx and determine nature of the serie Σ U_n

$${calculate}\:{U}_{{n}} =\int_{\mathrm{0}} ^{\infty} \:\:\frac{{arctan}\left(\mathrm{1}+{x}^{\mathrm{4}} \right)}{\left({x}^{\mathrm{2}} \:+{n}^{\mathrm{2}} \right)^{\mathrm{3}} }{dx} \\ $$$${and}\:{determine}\:{nature}\:{of}\:{the}\:{serie}\:\Sigma\:{U}_{{n}} \\ $$

Question Number 72389 Answers: 1 Comments: 0

find Σ_(k=1) ^n k(C_n ^k )^2 interms of n

$${find}\:\sum_{{k}=\mathrm{1}} ^{{n}} {k}\left({C}_{{n}} ^{{k}} \right)^{\mathrm{2}} \:{interms}\:{of}\:{n} \\ $$

Question Number 72161 Answers: 1 Comments: 4

Question Number 72178 Answers: 0 Comments: 3

Question Number 72153 Answers: 1 Comments: 3

∫((sin^3 x)/(√(cos x)))dx ∫sin(lnx)dx

$$\int\frac{\mathrm{sin}\:^{\mathrm{3}} \mathrm{x}}{\sqrt{\mathrm{cos}\:\mathrm{x}}}\mathrm{dx} \\ $$$$\int\mathrm{sin}\left(\mathrm{lnx}\right)\mathrm{dx} \\ $$

Question Number 72150 Answers: 0 Comments: 1

Question Number 72148 Answers: 0 Comments: 1

Question Number 72145 Answers: 0 Comments: 4

prove that: cos α×cos 2α×cos 2^2 α...cos 2^n α =((sin 2^(n+1) α)/(2^(n+1) sin α))

$${prove}\:{that}: \\ $$$$\mathrm{cos}\:\alpha×\mathrm{cos}\:\mathrm{2}\alpha×{cos}\:\mathrm{2}^{\mathrm{2}} \alpha...{cos}\:\mathrm{2}^{{n}} \alpha \\ $$$$=\frac{\mathrm{sin}\:\mathrm{2}^{{n}+\mathrm{1}} \alpha}{\mathrm{2}^{{n}+\mathrm{1}} \mathrm{sin}\:\alpha} \\ $$$$ \\ $$

Question Number 72124 Answers: 0 Comments: 0

Question Number 72118 Answers: 0 Comments: 1

Question Number 72117 Answers: 0 Comments: 1

Please help with the proof of cauchy inequality.

$${Please}\:{help}\:{with}\:{the}\:{proof}\:{of}\:{cauchy}\:{inequality}. \\ $$

Question Number 72122 Answers: 0 Comments: 0

If p is the probability that a man x will die in a year, then the probability that out of n men A_1 , A_2 , ..., A_n each aged x, A_1 will die in a year and be first to die, is

$$\mathrm{If}\:\:{p}\:\:\mathrm{is}\:\mathrm{the}\:\mathrm{probability}\:\mathrm{that}\:\mathrm{a}\:\mathrm{man}\:{x}\:\mathrm{will} \\ $$$$\mathrm{die}\:\mathrm{in}\:\mathrm{a}\:\mathrm{year},\:\mathrm{then}\:\mathrm{the}\:\mathrm{probability}\:\mathrm{that} \\ $$$$\mathrm{out}\:\mathrm{of}\:{n}\:\mathrm{men}\:{A}_{\mathrm{1}} ,\:{A}_{\mathrm{2}} ,\:...,\:{A}_{{n}} \:\:\mathrm{each}\:\mathrm{aged}\:{x}, \\ $$$${A}_{\mathrm{1}} \:\mathrm{will}\:\mathrm{die}\:\mathrm{in}\:\mathrm{a}\:\mathrm{year}\:\mathrm{and}\:\mathrm{be}\:\mathrm{first}\:\mathrm{to}\:\mathrm{die}, \\ $$$$\mathrm{is} \\ $$

Question Number 72112 Answers: 1 Comments: 0

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