f(x)= 2x^3 −x−4
show that the equation f(x) =0 has root between 1 and 2
show that the equation f(x) =0 can be written as
x = (√(((2/x) +(1/2))))
use the iteration
x_(n+1 ) = (√(((2/x_n ) +(1/2)) ,))
with x_0 = 1.385 to find to 3 decimal places the value of x_1 .
let f(x) =∫_0 ^(π/4) (dt/(x+tant)) with x real
1) find aexplicit form of f(x)
2)find also g(x) =∫_0 ^(π/4) (dt/((x+tant)^2 ))
3)give f^((n)) (x)at form of integral
4)calculate ∫_0 ^(π/4) (dt/(2+tant)) and ∫_0 ^(π/4) (dt/((2+tant)^2 ))