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Question Number 75896    Answers: 1   Comments: 0

One pipe can fill a tank in 40 minutes and an outlet pipe can empty the full tank in 24 minutes. If both the pipes are opened simultaneously, what time will it take for the full tank to be emptied?

$$\mathrm{One}\:\mathrm{pipe}\:\mathrm{can}\:\mathrm{fill}\:\mathrm{a}\:\mathrm{tank}\:\mathrm{in}\:\mathrm{40}\:\mathrm{minutes} \\ $$$$\mathrm{and}\:\mathrm{an}\:\mathrm{outlet}\:\mathrm{pipe}\:\mathrm{can}\:\mathrm{empty}\:\mathrm{the}\:\mathrm{full} \\ $$$$\mathrm{tank}\:\mathrm{in}\:\mathrm{24}\:\mathrm{minutes}.\:\mathrm{If}\:\mathrm{both}\:\mathrm{the}\:\mathrm{pipes} \\ $$$$\mathrm{are}\:\mathrm{opened}\:\mathrm{simultaneously},\:\mathrm{what}\:\mathrm{time} \\ $$$$\mathrm{will}\:\mathrm{it}\:\mathrm{take}\:\mathrm{for}\:\mathrm{the}\:\mathrm{full}\:\mathrm{tank}\:\mathrm{to}\:\mathrm{be} \\ $$$$\mathrm{emptied}? \\ $$

Question Number 75895    Answers: 1   Comments: 0

A garrison had provisions for 1500 men for 30 days. After some days, 300 more men joined the garrison. The provisions lasted for a total of 26 days from the beginning. After how many days did the new men join?

$$\mathrm{A}\:\mathrm{garrison}\:\mathrm{had}\:\mathrm{provisions}\:\mathrm{for}\:\mathrm{1500}\:\mathrm{men} \\ $$$$\mathrm{for}\:\mathrm{30}\:\mathrm{days}.\:\mathrm{After}\:\mathrm{some}\:\mathrm{days},\:\mathrm{300}\:\mathrm{more} \\ $$$$\mathrm{men}\:\mathrm{joined}\:\mathrm{the}\:\mathrm{garrison}.\:\mathrm{The}\:\mathrm{provisions} \\ $$$$\mathrm{lasted}\:\mathrm{for}\:\mathrm{a}\:\mathrm{total}\:\mathrm{of}\:\mathrm{26}\:\mathrm{days}\:\mathrm{from}\:\mathrm{the} \\ $$$$\mathrm{beginning}.\:\mathrm{After}\:\mathrm{how}\:\mathrm{many}\:\mathrm{days}\:\mathrm{did} \\ $$$$\mathrm{the}\:\mathrm{new}\:\mathrm{men}\:\mathrm{join}? \\ $$

Question Number 75894    Answers: 0   Comments: 0

When 616 is divided by a certain positive number, which is 66(2/3)% of the quotient, it leaves 16 as the remainder. Find the divisor.

$$\mathrm{When}\:\mathrm{616}\:\mathrm{is}\:\mathrm{divided}\:\mathrm{by}\:\mathrm{a}\:\mathrm{certain}\: \\ $$$$\mathrm{positive}\:\mathrm{number},\:\mathrm{which}\:\mathrm{is}\:\mathrm{66}\frac{\mathrm{2}}{\mathrm{3}}\%\:\mathrm{of}\:\mathrm{the} \\ $$$$\mathrm{quotient},\:\mathrm{it}\:\mathrm{leaves}\:\mathrm{16}\:\mathrm{as}\:\mathrm{the}\:\mathrm{remainder}. \\ $$$$\mathrm{Find}\:\mathrm{the}\:\mathrm{divisor}. \\ $$

Question Number 75890    Answers: 0   Comments: 0

calculate ∫_0 ^∞ ((arctan(2x+3))/(x^2 +4))dx

$${calculate}\:\int_{\mathrm{0}} ^{\infty} \:\:\frac{{arctan}\left(\mathrm{2}{x}+\mathrm{3}\right)}{{x}^{\mathrm{2}} +\mathrm{4}}{dx} \\ $$

Question Number 75889    Answers: 0   Comments: 0

find ∫ (√((x+1)(x+2)(2x−1)))dx

$${find}\:\int\:\sqrt{\left({x}+\mathrm{1}\right)\left({x}+\mathrm{2}\right)\left(\mathrm{2}{x}−\mathrm{1}\right)}{dx} \\ $$

Question Number 75888    Answers: 0   Comments: 1

find ∫_0 ^1 (√(1+x^4 ))dx

$${find}\:\int_{\mathrm{0}} ^{\mathrm{1}} \sqrt{\mathrm{1}+{x}^{\mathrm{4}} }{dx} \\ $$

Question Number 75883    Answers: 0   Comments: 2

If a^4 + b^4 + c^4 + d^4 = 16 Prove that, a^5 + b^5 + c^5 + d^5 ≤ 32

$$\mathrm{If}\:\:\:\:\mathrm{a}^{\mathrm{4}} \:+\:\mathrm{b}^{\mathrm{4}} \:+\:\mathrm{c}^{\mathrm{4}} \:+\:\mathrm{d}^{\mathrm{4}} \:\:\:=\:\:\:\mathrm{16} \\ $$$$\mathrm{Prove}\:\mathrm{that},\:\:\:\:\:\:\:\:\mathrm{a}^{\mathrm{5}} \:+\:\mathrm{b}^{\mathrm{5}} \:+\:\mathrm{c}^{\mathrm{5}} \:+\:\mathrm{d}^{\mathrm{5}} \:\:\:\leqslant\:\:\:\mathrm{32} \\ $$

Question Number 75879    Answers: 1   Comments: 0

Question Number 75873    Answers: 1   Comments: 0

∫xe^x dx

$$\int{xe}^{{x}} {dx} \\ $$

Question Number 75868    Answers: 0   Comments: 0

PROVE THAT sin3° sin39° sin75° = sin 9° sin 24° sin 30°

$${PROVE}\:\:{THAT} \\ $$$$ \\ $$$$\mathrm{sin3}°\:\mathrm{sin39}°\:\mathrm{sin75}°\:=\:\mathrm{sin}\:\mathrm{9}°\:\mathrm{sin}\:\mathrm{24}°\:\mathrm{sin}\:\mathrm{30}° \\ $$

Question Number 75860    Answers: 1   Comments: 0

complete and balance S+HNO_3 →

$${complete}\:{and}\:{balance}\: \\ $$$${S}+{HNO}_{\mathrm{3}} \rightarrow \\ $$$$ \\ $$

Question Number 75851    Answers: 1   Comments: 0

Question Number 75849    Answers: 0   Comments: 0

In a AB^△ C: { ((a+b+c=2(h_a +h_b +h_c ))),((a^2 +b^2 +c^2 =6abc)),((h_a ^2 +h_b ^2 +h_c ^2 =6h_a .h_b .h_c )) :} find:∡A

$$\boldsymbol{\mathrm{In}}\:\boldsymbol{\mathrm{a}}\:\boldsymbol{\mathrm{A}}\overset{\bigtriangleup} {\boldsymbol{\mathrm{B}C}}: \\ $$$$\begin{cases}{\boldsymbol{\mathrm{a}}+\boldsymbol{\mathrm{b}}+\boldsymbol{\mathrm{c}}=\mathrm{2}\left(\boldsymbol{\mathrm{h}}_{\boldsymbol{\mathrm{a}}} +\boldsymbol{\mathrm{h}}_{\boldsymbol{\mathrm{b}}} +\boldsymbol{\mathrm{h}}_{\boldsymbol{\mathrm{c}}} \right)}\\{\boldsymbol{\mathrm{a}}^{\mathrm{2}} +\boldsymbol{\mathrm{b}}^{\mathrm{2}} +\boldsymbol{\mathrm{c}}^{\mathrm{2}} =\mathrm{6}\boldsymbol{\mathrm{abc}}}\\{\boldsymbol{\mathrm{h}}_{\boldsymbol{\mathrm{a}}} ^{\mathrm{2}} +\boldsymbol{\mathrm{h}}_{\boldsymbol{\mathrm{b}}} ^{\mathrm{2}} +\boldsymbol{\mathrm{h}}_{\boldsymbol{\mathrm{c}}} ^{\mathrm{2}} =\mathrm{6}\boldsymbol{\mathrm{h}}_{\boldsymbol{\mathrm{a}}} .\boldsymbol{\mathrm{h}}_{\boldsymbol{\mathrm{b}}} .\boldsymbol{\mathrm{h}}_{\boldsymbol{\mathrm{c}}} }\end{cases} \\ $$$$\boldsymbol{\mathrm{find}}:\measuredangle\boldsymbol{\mathrm{A}} \\ $$

Question Number 75848    Answers: 2   Comments: 1

∫_0 ^( (𝛑/2)) ((sin4x)/(1+sinx+cosx))dx=?

$$\underset{\mathrm{0}} {\overset{\:\:\:\:\:\:\:\:\frac{\boldsymbol{\pi}}{\mathrm{2}}} {\int}}\frac{\boldsymbol{\mathrm{sin}}\mathrm{4}\boldsymbol{\mathrm{x}}}{\mathrm{1}+\boldsymbol{\mathrm{sinx}}+\boldsymbol{\mathrm{cosx}}}\boldsymbol{\mathrm{dx}}=? \\ $$

Question Number 75840    Answers: 1   Comments: 0

If x^(200) < 3^(300) , then greatest possible integral value of x is _____.

$$\mathrm{If}\:\:{x}^{\mathrm{200}} \:<\:\mathrm{3}^{\mathrm{300}} \:,\:\mathrm{then}\:\mathrm{greatest}\:\mathrm{possible} \\ $$$$\mathrm{integral}\:\mathrm{value}\:\mathrm{of}\:\:\:{x}\:\:\mathrm{is}\:\_\_\_\_\_. \\ $$

Question Number 75838    Answers: 0   Comments: 1

Question Number 75845    Answers: 1   Comments: 2

{ ((x+yz=x^2 )),((y+xz=y^2 )),((z+xy=z^2 )) :} solve for x,y,z.

$$\begin{cases}{\boldsymbol{\mathrm{x}}+\boldsymbol{\mathrm{yz}}=\boldsymbol{\mathrm{x}}^{\mathrm{2}} }\\{\boldsymbol{\mathrm{y}}+\boldsymbol{\mathrm{xz}}=\boldsymbol{\mathrm{y}}^{\mathrm{2}} }\\{\boldsymbol{\mathrm{z}}+\boldsymbol{\mathrm{xy}}=\boldsymbol{\mathrm{z}}^{\mathrm{2}} }\end{cases}\:\:\:\:\:\boldsymbol{\mathrm{solve}}\:\boldsymbol{\mathrm{for}}\:\boldsymbol{\mathrm{x}},\boldsymbol{\mathrm{y}},\boldsymbol{\mathrm{z}}. \\ $$

Question Number 75830    Answers: 1   Comments: 5

Question Number 75828    Answers: 1   Comments: 1

Σ_(n=1) ^∞ (1/(10^n ))

$$\underset{{n}=\mathrm{1}} {\overset{\infty} {\sum}}\frac{\mathrm{1}}{\mathrm{10}^{{n}} } \\ $$

Question Number 75826    Answers: 1   Comments: 1

Question Number 75846    Answers: 2   Comments: 0

sin^5 x+(√2)sinx=1 , x∈[0,2𝛑]

$$\boldsymbol{\mathrm{sin}}^{\mathrm{5}} \boldsymbol{\mathrm{x}}+\sqrt{\mathrm{2}}\boldsymbol{\mathrm{sinx}}=\mathrm{1}\:\:\:\:\:\:\:\:,\:\:\boldsymbol{\mathrm{x}}\in\left[\mathrm{0},\mathrm{2}\boldsymbol{\pi}\right] \\ $$

Question Number 75847    Answers: 0   Comments: 2

{ ((((tgx−tgy)/(1−tgx.tgy))=tg(x/2))),(( ((tgx+tgy)/(1+tgxtgy))=tg(y/2))) :}

$$\begin{cases}{\frac{\boldsymbol{\mathrm{tgx}}−\boldsymbol{\mathrm{tgy}}}{\mathrm{1}−\boldsymbol{\mathrm{tgx}}.\boldsymbol{\mathrm{tgy}}}=\boldsymbol{\mathrm{tg}}\frac{\boldsymbol{\mathrm{x}}}{\mathrm{2}}}\\{\:\:\frac{\boldsymbol{\mathrm{tgx}}+\boldsymbol{\mathrm{tgy}}}{\mathrm{1}+\boldsymbol{\mathrm{tgxtgy}}}=\boldsymbol{\mathrm{tg}}\frac{\boldsymbol{\mathrm{y}}}{\mathrm{2}}}\end{cases} \\ $$

Question Number 75825    Answers: 0   Comments: 0

Question Number 75822    Answers: 0   Comments: 0

Question Number 75821    Answers: 0   Comments: 1

Question Number 75818    Answers: 1   Comments: 3

Given the increasing sequence : 1, 4, 8, 13, ... a. Find U_(2019) b. Find S_(2019) U_n is nth−term of the sequence S_n is sum of n − term of the sequence Arithmetic Sequence Degree Two

$${Given}\:\:{the}\:\:{increasing}\:\:{sequence}\:: \\ $$$$\mathrm{1},\:\mathrm{4},\:\mathrm{8},\:\mathrm{13},\:... \\ $$$${a}.\:{Find}\:\:{U}_{\mathrm{2019}} \\ $$$${b}.\:{Find}\:\:{S}_{\mathrm{2019}} \\ $$$${U}_{{n}} \:\:{is}\:\:{nth}−{term}\:\:{of}\:\:{the}\:\:{sequence} \\ $$$${S}_{{n}} \:\:{is}\:\:{sum}\:\:{of}\:\:{n}\:−\:{term}\:\:{of}\:\:{the}\:\:{sequence} \\ $$$${Arithmetic}\:\:{Sequence}\:\:{Degree}\:\:{Two} \\ $$

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