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In a triangle whose sides measure 5 cm, 6 cm, and 7 cm a point P, inside the triangle is 2 cm from de long side 5 cm and 3 cm from the long side 6 cm. What is the distance from P beside 7 cm side?

$${In}\:{a}\:{triangle}\:{whose}\:{sides}\:{measure} \\ $$$$\mathrm{5}\:{cm},\:\mathrm{6}\:{cm},\:{and}\:\:\mathrm{7}\:{cm}\:{a}\:{point}\:{P},\:{inside} \\ $$$${the}\:{triangle}\:{is}\:\mathrm{2}\:{cm}\:{from}\:{de}\:{long}\:{side} \\ $$$$\mathrm{5}\:{cm}\:{and}\:\mathrm{3}\:{cm}\:{from}\:{the}\:{long}\:{side} \\ $$$$\mathrm{6}\:{cm}.\:{What}\:{is}\:{the}\:{distance}\:{from}\:{P} \\ $$$${beside}\:\mathrm{7}\:{cm}\:{side}? \\ $$

Question Number 76445 Answers: 0 Comments: 6

how evaluate lim_(x→0) (((1−(√(1+x^2 ))×cos x)/x^4 )).

$${how}\:{evaluate}\:\underset{{x}\rightarrow\mathrm{0}} {\mathrm{lim}}\left(\frac{\mathrm{1}−\sqrt{\mathrm{1}+{x}^{\mathrm{2}} }×\mathrm{cos}\:{x}}{{x}^{\mathrm{4}} }\right). \\ $$

Question Number 76443 Answers: 1 Comments: 0

Question Number 76442 Answers: 1 Comments: 0

Question Number 76439 Answers: 1 Comments: 0

solve in [0;2π[ 1+2sin3x≤0

$$\mathrm{solve}\:\mathrm{in}\:\left[\mathrm{0};\mathrm{2}\pi\left[\:\right.\right. \\ $$$$\mathrm{1}+\mathrm{2sin3}{x}\leqslant\mathrm{0} \\ $$

Question Number 76438 Answers: 1 Comments: 0

given N =(4/(((√5)+1)(5^(1/4) +1)(5^(1/8) +1)(5^(1/(16)) +1))) find value of (N+1)^(48) .

$${given}\:{N}\:=\frac{\mathrm{4}}{\left(\sqrt{\mathrm{5}}+\mathrm{1}\right)\left(\mathrm{5}^{\frac{\mathrm{1}}{\mathrm{4}}} +\mathrm{1}\right)\left(\mathrm{5}^{\frac{\mathrm{1}}{\mathrm{8}}} +\mathrm{1}\right)\left(\mathrm{5}^{\frac{\mathrm{1}}{\mathrm{16}}} +\mathrm{1}\right)} \\ $$$${find}\:{value}\:{of}\:\left({N}+\mathrm{1}\right)^{\mathrm{48}} . \\ $$

Question Number 76436 Answers: 2 Comments: 0

Question Number 76434 Answers: 2 Comments: 0

if sec x − tan x = 4, then find sin x.

$$\mathrm{if}\:\mathrm{sec}\:\mathrm{x}\:−\:\mathrm{tan}\:\mathrm{x}\:=\:\mathrm{4},\:\mathrm{then}\:\mathrm{find}\: \\ $$$$\mathrm{sin}\:\mathrm{x}. \\ $$

Question Number 76431 Answers: 1 Comments: 1

how to find x^(2048) + x^(−2048) if x+x^(−1) =(((√5)+1)/2)

$${how}\:{to}\:{find}\:{x}^{\mathrm{2048}} \:+\:{x}^{−\mathrm{2048}} \\ $$$${if}\:\:{x}+{x}^{−\mathrm{1}} =\frac{\sqrt{\mathrm{5}}+\mathrm{1}}{\mathrm{2}} \\ $$

Question Number 76428 Answers: 2 Comments: 0

Question Number 76424 Answers: 1 Comments: 1

how to calculate ∫(√(x/(√(x/(√(x/(√(...)))))))) dx ?

$${how}\:{to}\:{calculate}\:\int\sqrt{\frac{{x}}{\sqrt{\frac{{x}}{\sqrt{\frac{{x}}{\sqrt{...}}}}}}}\:\:{dx}\:? \\ $$

Question Number 76407 Answers: 0 Comments: 0

Question Number 76404 Answers: 0 Comments: 2

Hello have nice end of year good bless you all i respond note in y re message becsuse i have so many problemes that mack me feel no pleasur any more to do somthing i think its importante to say it i will back Soon i hop so Sorry for my English

$$\mathrm{Hello}\:\mathrm{have}\:\mathrm{nice}\:\mathrm{end}\:\mathrm{of}\:\mathrm{year}\:\mathrm{good}\:\mathrm{bless}\:\mathrm{you} \\ $$$$\mathrm{all}\:\mathrm{i}\:\mathrm{respond}\:\mathrm{note}\:\mathrm{in}\:\mathrm{y}\:\mathrm{re}\:\mathrm{message}\:\mathrm{becsuse}\:\mathrm{i}\:\mathrm{have}\:\mathrm{so}\:\mathrm{many}\:\mathrm{problemes} \\ $$$$\mathrm{that}\:\mathrm{mack}\:\mathrm{me}\:\mathrm{feel}\:\mathrm{no}\:\mathrm{pleasur}\:\mathrm{any}\:\mathrm{more}\:\mathrm{to}\:\mathrm{do}\:\mathrm{somthing} \\ $$$$\mathrm{i}\:\mathrm{think}\:\mathrm{its}\:\mathrm{importante}\:\mathrm{to}\:\mathrm{say}\:\mathrm{it}\:\mathrm{i}\:\mathrm{will}\:\mathrm{back}\:\mathrm{Soon}\:\mathrm{i}\:\mathrm{hop}\:\mathrm{so}\:\:\mathrm{Sorry}\:\mathrm{for} \\ $$$$\mathrm{my}\:\mathrm{English} \\ $$

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