3)αparticle of energy 5MeV pass
through an ionisation chamber at the
rate of 10 pwe second . Assum that all
the energy is used in producing ion
pairs,calculate the current produced.
(35MeV is required for producing an
ion pair and e=1.6×10^(-19) C)
solution:
Energy of α particles=5×10^6 eV
Energy required for producing one
ion pair=35eV
No.of ion pairs produced by one α
particle =((5×10^6 )/(35))=1.426×10^5
since 10 particle enter the chamber in
one second
=1.426×10^5 ×10=1.426×10^6
charge on dach ion=1.6×10^(-19) C
Current=(1.426×10^6 )×(1.6×10^(-19) )C/s
=2.287×10^(-13) A.
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