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Question Number 73722 Answers: 0 Comments: 2

Question Number 73721 Answers: 0 Comments: 0

Question Number 73715 Answers: 1 Comments: 2

Evaluate the integral : ∫_( R) ∫(3x^2 +14xy+8y^2 )dxdy for the region R in the 1st quadrant bounded by the lines y=((−3)/2)x+1,y=((−3)/2)x+3,y=−(1/4)x and y=−(1/4)x+1 .

$${Evaluate}\:{the}\:{integral}\:: \\ $$$$\underset{\:\mathbb{R}} {\int}\int\left(\mathrm{3}{x}^{\mathrm{2}} +\mathrm{14}{xy}+\mathrm{8}{y}^{\mathrm{2}} \right){dxdy}\:{for}\:{the}\:{region} \\ $$$$\mathbb{R}\:\mathrm{in}\:{the}\:\mathrm{1}{st}\:{quadrant}\:{bounded}\:{by}\:{the} \\ $$$${lines}\:{y}=\frac{−\mathrm{3}}{\mathrm{2}}{x}+\mathrm{1},{y}=\frac{−\mathrm{3}}{\mathrm{2}}{x}+\mathrm{3},{y}=−\frac{\mathrm{1}}{\mathrm{4}}{x} \\ $$$${and}\:{y}=−\frac{\mathrm{1}}{\mathrm{4}}{x}+\mathrm{1}\:. \\ $$

Question Number 73710 Answers: 0 Comments: 0

Question Number 73709 Answers: 0 Comments: 0

Question Number 73708 Answers: 0 Comments: 0

Question Number 73707 Answers: 0 Comments: 1

Question Number 73706 Answers: 1 Comments: 0

If ((tan 3A)/(tan A)) = k, then ((sin 3A)/(sin A)) is equal to

$$\mathrm{If}\:\:\frac{\mathrm{tan}\:\mathrm{3}{A}}{\mathrm{tan}\:{A}}\:=\:{k},\:\mathrm{then}\:\frac{\mathrm{sin}\:\mathrm{3}{A}}{\mathrm{sin}\:{A}}\:\mathrm{is}\:\mathrm{equal}\:\mathrm{to} \\ $$

Question Number 73712 Answers: 1 Comments: 0

Question Number 73697 Answers: 1 Comments: 1

find a formulae for calculus of arctan(x+iy)

$${find}\:{a}\:{formulae}\:{for}\:{calculus}\:{of}\:{arctan}\left({x}+{iy}\right) \\ $$

Question Number 73689 Answers: 2 Comments: 0

∫_(−1) ^( 1) (2+x)sin^(−1) (((√(3−3x^2 ))/(2+x)))dx = ?

$$\int_{−\mathrm{1}} ^{\:\:\mathrm{1}} \left(\mathrm{2}+{x}\right)\mathrm{sin}^{−\mathrm{1}} \left(\frac{\sqrt{\mathrm{3}−\mathrm{3}{x}^{\mathrm{2}} }}{\mathrm{2}+{x}}\right){dx}\:=\:? \\ $$

Question Number 73679 Answers: 0 Comments: 1

We have updated backend code to disallow delete of question which are already answered or commented.

$$\mathrm{We}\:\mathrm{have}\:\mathrm{updated}\:\mathrm{backend}\:\mathrm{code}\:\mathrm{to}\: \\ $$$$\mathrm{disallow}\:\mathrm{delete}\:\mathrm{of}\:\mathrm{question}\:\mathrm{which}\:\mathrm{are} \\ $$$$\mathrm{already}\:\mathrm{answered}\:\mathrm{or}\:\mathrm{commented}. \\ $$$$ \\ $$

Question Number 73673 Answers: 2 Comments: 3

Question Number 73671 Answers: 0 Comments: 0

Question Number 73668 Answers: 1 Comments: 0

Qn . ∫(e^(2x^2 +2x+6) )dx ... I need help plz..

$$\:{Qn}\:.\:\int\left({e}^{\mathrm{2}{x}^{\mathrm{2}} +\mathrm{2}{x}+\mathrm{6}} \right){dx} \\ $$$$\:...\:{I}\:{need}\:{help}\:{plz}.. \\ $$$$ \\ $$$$ \\ $$

Question Number 73665 Answers: 1 Comments: 0

if cos^2 (θ)=((m^2 −1)/3) , tan^3 ((θ/2))=tan(a) prove that ((cos^2 (a)))^(1/3) + ((sin^2 (a)))^(1/3) = ((((2/m))^2 ))^(1/3)

$${if} \\ $$$$ \\ $$$${cos}^{\mathrm{2}} \left(\theta\right)=\frac{{m}^{\mathrm{2}} −\mathrm{1}}{\mathrm{3}}\:\:,\:\:{tan}^{\mathrm{3}} \left(\frac{\theta}{\mathrm{2}}\right)={tan}\left({a}\right) \\ $$$$ \\ $$$${prove}\:{that} \\ $$$$ \\ $$$$\sqrt[{\mathrm{3}}]{{cos}^{\mathrm{2}} \left({a}\right)}\:+\:\sqrt[{\mathrm{3}}]{{sin}^{\mathrm{2}} \left({a}\right)}\:=\:\sqrt[{\mathrm{3}}]{\left(\frac{\mathrm{2}}{{m}}\right)^{\mathrm{2}} } \\ $$

Question Number 73663 Answers: 1 Comments: 0

Question Number 73649 Answers: 1 Comments: 2

find the range f(x)=(2/(6−(√(x+2))))

$${find}\:{the}\:{range} \\ $$$$ \\ $$$${f}\left({x}\right)=\frac{\mathrm{2}}{\mathrm{6}−\sqrt{{x}+\mathrm{2}}} \\ $$

Question Number 73628 Answers: 1 Comments: 0

find coefficient of x^(r ) in the expension of (2x−6y)^(−8)

$${find}\:{coefficient}\:{of}\:{x}^{{r}\:} \:{in}\:{the}\:{expension}\:{of}\: \\ $$$$\:\left(\mathrm{2}{x}−\mathrm{6}{y}\right)^{−\mathrm{8}} \\ $$

Question Number 73620 Answers: 1 Comments: 0

Question Number 73608 Answers: 0 Comments: 5

determiner la valeur exacte de sin(((85Π)/4))

$$\:\mathrm{determiner} \\ $$$$\:\mathrm{la}\:\mathrm{valeur}\:\mathrm{exacte}\:\mathrm{de}\:\mathrm{sin}\left(\frac{\mathrm{85}\Pi}{\mathrm{4}}\right) \\ $$$$ \\ $$

Question Number 73595 Answers: 0 Comments: 5

i ask all of you not to answer any question from www ( = amirley or something like this) (= best) (=azodbek or something like this) this guy is not to help! he misuses your help and deletes his posts as soon as you have answered them.

$${i}\:{ask}\:{all}\:{of}\:{you}\:{not}\:{to}\:{answer}\:{any} \\ $$$${question}\:{from}\:{www} \\ $$$$\left(\:=\:{amirley}\:{or}\:{something}\:{like}\:{this}\right) \\ $$$$\left(=\:{best}\right) \\ $$$$\left(={azodbek}\:{or}\:{something}\:{like}\:{this}\right) \\ $$$${this}\:{guy}\:{is}\:{not}\:{to}\:{help}!\:{he}\:{misuses} \\ $$$${your}\:{help}\:{and}\:{deletes}\:{his}\:{posts}\:{as} \\ $$$${soon}\:{as}\:{you}\:{have}\:{answered}\:{them}. \\ $$

Question Number 73590 Answers: 2 Comments: 2

prove that (_k ^(n+1) )=(_k ^n )+(_(n−1) ^n ) pleas sir help me ?

$${prove}\:{that}\:\left(_{{k}} ^{{n}+\mathrm{1}} \right)=\left(_{{k}} ^{{n}} \right)+\left(_{{n}−\mathrm{1}} ^{{n}} \right) \\ $$$${pleas}\:{sir}\:{help}\:{me}\:? \\ $$

Question Number 73582 Answers: 0 Comments: 2

Could you help me with references in complex analysis please?

$${Could}\:{you}\:{help}\:{me}\:{with}\:{references} \\ $$$${in}\:{complex}\:{analysis}\:{please}? \\ $$

Question Number 73574 Answers: 0 Comments: 1

Question Number 73572 Answers: 0 Comments: 1

determine wether or not the function f,where f(x) = { ((2x + 1, 0≤ x <2)),((7−x, 2 ≤ x < 4)),((((3x)/4) , 4 ≤ x < 6)) :} is continuous in the interval [0,6[

$${determine}\:{wether}\:{or}\:{not}\:{the}\:{function}\:{f},{where} \\ $$$${f}\left({x}\right)\:=\:\begin{cases}{\mathrm{2}{x}\:+\:\mathrm{1},\:\mathrm{0}\leqslant\:{x}\:<\mathrm{2}}\\{\mathrm{7}−{x},\:\:\:\mathrm{2}\:\leqslant\:{x}\:<\:\mathrm{4}}\\{\frac{\mathrm{3}{x}}{\mathrm{4}}\:,\:\:\mathrm{4}\:\leqslant\:{x}\:<\:\mathrm{6}}\end{cases} \\ $$$${is}\:{continuous}\:{in}\:{the}\:{interval}\:\left[\mathrm{0},\mathrm{6}\left[\right.\right. \\ $$

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