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AllQuestion and Answers: Page 1320

Question Number 70782 Answers: 0 Comments: 3

how can i get my password ? i can′t remeber

$$\mathrm{how}\:\mathrm{can}\:\mathrm{i}\:\mathrm{get}\:\mathrm{my}\:\mathrm{password}\:?\:\mathrm{i}\:\:\mathrm{can}'\mathrm{t}\:\mathrm{remeber} \\ $$

Question Number 70746 Answers: 0 Comments: 4

Question Number 70742 Answers: 0 Comments: 1

Prove that f(x) = x − a cos (x) − b has at least one real root for ∀a,b ∈ R

$$\mathrm{Prove}\:\mathrm{that}\:{f}\left({x}\right)\:=\:{x}\:−\:{a}\:\mathrm{cos}\:\left({x}\right)\:−\:{b} \\ $$$$\mathrm{has}\:\mathrm{at}\:\mathrm{least}\:\mathrm{one}\:\mathrm{real}\:\mathrm{root}\:\mathrm{for}\:\forall{a},{b}\:\in\:\mathbb{R} \\ $$

Question Number 70738 Answers: 1 Comments: 2

Question Number 70741 Answers: 0 Comments: 5

f(x)= { ((x^2 x≤1)),(),((∣x−2∣ x>1)) :} find the critical points

$${f}\left({x}\right)=\begin{cases}{{x}^{\mathrm{2}} \:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:{x}\leqslant\mathrm{1}}\\{}\\{\mid{x}−\mathrm{2}\mid\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:{x}>\mathrm{1}}\end{cases} \\ $$$$ \\ $$$${find}\:{the}\:{critical}\:{points} \\ $$

Question Number 70798 Answers: 1 Comments: 1

Question Number 70720 Answers: 2 Comments: 4

y′′+((y′)/x)+((4y)/x^2 )=1+x^2

$$\mathrm{y}''+\frac{\mathrm{y}'}{\mathrm{x}}+\frac{\mathrm{4y}}{\mathrm{x}^{\mathrm{2}} }=\mathrm{1}+\mathrm{x}^{\mathrm{2}} \\ $$

Question Number 70710 Answers: 1 Comments: 0

pleace how can link this app to my telegram

$$\mathrm{pleace}\:\mathrm{how}\:\mathrm{can}\:\mathrm{link}\:\mathrm{this}\: \\ $$$$\mathrm{app}\:\mathrm{to}\:\mathrm{my}\:\mathrm{telegram} \\ $$

Question Number 70713 Answers: 0 Comments: 1

can i login to my account with other phone? if so how

$$\mathrm{can}\:\mathrm{i}\:\mathrm{login}\:\mathrm{to}\:\mathrm{my}\:\mathrm{account}\: \\ $$$$\mathrm{with}\:\mathrm{other}\:\mathrm{phone}?\:\mathrm{if}\:\mathrm{so}\:\mathrm{how} \\ $$

Question Number 70705 Answers: 1 Comments: 0

(d/dx)(log_(10) x)=?

$$\frac{\mathrm{d}}{\mathrm{dx}}\left(\mathrm{log}_{\mathrm{10}} \mathrm{x}\right)=? \\ $$

Question Number 70704 Answers: 1 Comments: 2

z^4 −2z^2 +2=0

$$\mathrm{z}^{\mathrm{4}} −\mathrm{2z}^{\mathrm{2}} +\mathrm{2}=\mathrm{0} \\ $$

Question Number 70696 Answers: 1 Comments: 4

∫x^x dx=?

$$\int{x}^{{x}} {dx}=? \\ $$

Question Number 70694 Answers: 1 Comments: 0

Question Number 70688 Answers: 0 Comments: 0

Question Number 70686 Answers: 2 Comments: 0

find ∫ (dx/(1+x^6 ))

$${find}\:\int\:\frac{{dx}}{\mathrm{1}+{x}^{\mathrm{6}} } \\ $$

Question Number 70679 Answers: 0 Comments: 2

Hi, i wanna learn more english. can someone help me? write please +584249229498

$${Hi},\:{i}\:{wanna}\:{learn}\:{more}\:{english}. \\ $$$${can}\:{someone}\:{help}\:{me}? \\ $$$${write}\:{please}\:+\mathrm{584249229498} \\ $$

Question Number 70672 Answers: 1 Comments: 1

Question Number 70669 Answers: 0 Comments: 5

Question Number 70659 Answers: 1 Comments: 0

find the range algrbraically f(x)=(√(x^2 −1))

$${find}\:{the}\:{range}\:{algrbraically} \\ $$$$ \\ $$$${f}\left({x}\right)=\sqrt{{x}^{\mathrm{2}} −\mathrm{1}} \\ $$

Question Number 70653 Answers: 1 Comments: 1

lim_(x→(π/2)) (sin x − cos x)^(tan x) = ...

$$\underset{{x}\rightarrow\frac{\pi}{\mathrm{2}}} {\mathrm{lim}}\:\:\left(\mathrm{sin}\:{x}\:−\:\mathrm{cos}\:{x}\right)^{\mathrm{tan}\:{x}} \:\:=\:\:... \\ $$

Question Number 70651 Answers: 0 Comments: 3

Question Number 70639 Answers: 0 Comments: 0

Question Number 70638 Answers: 1 Comments: 1

Question Number 70627 Answers: 0 Comments: 0

please great physicist check question 70568 please help

$${please}\:{great}\:{physicist}\:{check}\:{question}\: \\ $$$$\mathrm{70568}\:{please}\:{help} \\ $$

Question Number 70620 Answers: 0 Comments: 4

Question Number 70617 Answers: 1 Comments: 0

given that α and β are roots of the equation x^2 −5x + 4 =0 α>0 and β >0 find an equation whose roots are (√α) and (√β) how do i find (√(α )) + (√β)

$${given}\:{that}\:\:\alpha\:{and}\:\beta\:{are}\:{roots}\:{of}\:{the}\:{equation}\:{x}^{\mathrm{2}} −\mathrm{5}{x}\:+\:\mathrm{4}\:=\mathrm{0}\: \\ $$$$\alpha>\mathrm{0}\:{and}\:\beta\:>\mathrm{0} \\ $$$${find}\:{an}\:{equation}\:{whose}\:{roots}\:{are}\:\sqrt{\alpha}\:{and}\:\sqrt{\beta}\: \\ $$$$ \\ $$$${how}\:{do}\:{i}\:{find}\:\:\sqrt{\alpha\:}\:+\:\sqrt{\beta}\: \\ $$

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