a ball is droped from a height 20 m. Given that it
rebounce with a velocity of (3/4) that which it hit the ground
find the time interval between the first and second rebounce.
I think it will be
∫_0 ^(π/4) (dx/(√(1+tanx))) ≈∫_0 ^(π/4) (dx/(√(1+x)))
=(𝛑/4)−(1/2).(1/2).((𝛑/4))^2 +((1.3)/(2.4)).(1/3).((𝛑/4))^3 −((1.3.5)/(2.4.6)).(1/4)((𝛑/4))^4 +....