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Question Number 87624 Answers: 0 Comments: 1

find minimum value of cos^2 w + sec^2 w

$$\mathrm{find}\:\mathrm{minimum}\:\mathrm{value}\:\mathrm{of}\:\mathrm{cos}\:^{\mathrm{2}} \mathrm{w}\:+ \\ $$$$\mathrm{sec}\:^{\mathrm{2}} \mathrm{w}\: \\ $$

Question Number 87614 Answers: 1 Comments: 0

{ (((x+y).2^(y−2x) =6.25)),(((x+y)^(1/(2x−y)) =5)) :}

$$\begin{cases}{\left({x}+{y}\right).\mathrm{2}^{{y}−\mathrm{2}{x}} =\mathrm{6}.\mathrm{25}}\\{\left({x}+{y}\right)^{\frac{\mathrm{1}}{\mathrm{2}{x}−{y}}} =\mathrm{5}}\end{cases} \\ $$

Question Number 87613 Answers: 1 Comments: 1

Question Number 87630 Answers: 0 Comments: 1

Question Number 87598 Answers: 0 Comments: 1

Question Number 87586 Answers: 1 Comments: 0

l.c.m of two numbers is p^2 q^4 r^4 p q r are primes.find the possible no. of pairs

$${l}.{c}.{m}\:{of}\:{two}\:{numbers}\:{is}\:{p}^{\mathrm{2}} {q}^{\mathrm{4}} {r}^{\mathrm{4}} \:{p}\:{q}\:{r}\:{are} \\ $$$${primes}.{find}\:{the}\:{possible}\:{no}.\:{of}\:{pairs} \\ $$

Question Number 87585 Answers: 1 Comments: 0

Question Number 87581 Answers: 2 Comments: 1

Question Number 110350 Answers: 2 Comments: 0

((bob)/(hans)) (1)lim_(x→3) ((sin (x−(9/x)))/(tan (x−3)cos ((9/x)−x)))= (2)(x tan^(−1) (y))dx +( (x^2 /(2(1+y^2 )))). dy =0

$$\:\:\:\frac{{bob}}{{hans}} \\ $$$$\left(\mathrm{1}\right)\underset{{x}\rightarrow\mathrm{3}} {\mathrm{lim}}\:\frac{\mathrm{sin}\:\left({x}−\frac{\mathrm{9}}{{x}}\right)}{\mathrm{tan}\:\left({x}−\mathrm{3}\right)\mathrm{cos}\:\left(\frac{\mathrm{9}}{{x}}−{x}\right)}= \\ $$$$\left(\mathrm{2}\right)\left({x}\:\mathrm{tan}^{−\mathrm{1}} \left({y}\right)\right){dx}\:+\left(\:\frac{{x}^{\mathrm{2}} }{\mathrm{2}\left(\mathrm{1}+{y}^{\mathrm{2}} \right)}\right).\:{dy}\:=\mathrm{0}\: \\ $$

Question Number 87563 Answers: 1 Comments: 5

Which of the two numbers ((1+2+2^2 +2^3 +...+2^(n−1) )/(1+2+2^2 +2^3 +...+2^n )) and ((1+3+3^2 +3^3 +...+3^(n−1) )/(1+3+3^2 +3^3 +...+3^n )) is greater?

$$\mathrm{Which}\:\mathrm{of}\:\mathrm{the}\:\mathrm{two}\:\mathrm{numbers} \\ $$$$\frac{\mathrm{1}+\mathrm{2}+\mathrm{2}^{\mathrm{2}} +\mathrm{2}^{\mathrm{3}} +...+\mathrm{2}^{\mathrm{n}−\mathrm{1}} }{\mathrm{1}+\mathrm{2}+\mathrm{2}^{\mathrm{2}} +\mathrm{2}^{\mathrm{3}} +...+\mathrm{2}^{\mathrm{n}} }\:\mathrm{and}\: \\ $$$$\frac{\mathrm{1}+\mathrm{3}+\mathrm{3}^{\mathrm{2}} +\mathrm{3}^{\mathrm{3}} +...+\mathrm{3}^{\mathrm{n}−\mathrm{1}} }{\mathrm{1}+\mathrm{3}+\mathrm{3}^{\mathrm{2}} +\mathrm{3}^{\mathrm{3}} +...+\mathrm{3}^{\mathrm{n}} }\:\mathrm{is}\:\mathrm{greater}? \\ $$

Question Number 87561 Answers: 0 Comments: 3

for x,y ∈R , x ,y > 0 satisfy the equation { ((x^3 y−xy^3 = 24)),((x^2 +y^2 = 10 )) :} find the possible value of x+y? (a) 6 (b) 5 (c) 4 (d) 3(√2) (e) 2

$$\mathrm{for}\:\mathrm{x},\mathrm{y}\:\in\mathbb{R}\:,\: \\ $$$$\mathrm{x}\:,\mathrm{y}\:>\:\mathrm{0}\:\mathrm{satisfy}\:\mathrm{the}\:\mathrm{equation}\: \\ $$$$\begin{cases}{\mathrm{x}^{\mathrm{3}} \mathrm{y}−\mathrm{xy}^{\mathrm{3}} \:=\:\mathrm{24}}\\{\mathrm{x}^{\mathrm{2}} +\mathrm{y}^{\mathrm{2}} \:=\:\mathrm{10}\:}\end{cases} \\ $$$$\mathrm{find}\:\mathrm{the}\:\mathrm{possible}\:\mathrm{value}\:\mathrm{of}\:\mathrm{x}+\mathrm{y}? \\ $$$$\left(\mathrm{a}\right)\:\mathrm{6}\:\:\:\left(\mathrm{b}\right)\:\mathrm{5}\:\:\:\left(\mathrm{c}\right)\:\mathrm{4}\:\:\:\left(\mathrm{d}\right)\:\mathrm{3}\sqrt{\mathrm{2}}\:\:\left(\mathrm{e}\right)\:\mathrm{2} \\ $$

Question Number 87556 Answers: 1 Comments: 1