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Question Number 210261 Answers: 2 Comments: 0

show that ((sinAcosA−sinBcosB)/(cos^2 A−sin^2 B))=tan(A−B)

$$\boldsymbol{\mathrm{show}}\:\boldsymbol{\mathrm{that}} \\ $$$$\frac{\boldsymbol{\mathrm{sinAcosA}}−\boldsymbol{\mathrm{sinBcosB}}}{\boldsymbol{\mathrm{cos}}^{\mathrm{2}} \boldsymbol{\mathrm{A}}−\boldsymbol{\mathrm{sin}}^{\mathrm{2}} \boldsymbol{\mathrm{B}}}=\boldsymbol{\mathrm{tan}}\left(\boldsymbol{\mathrm{A}}−\boldsymbol{\mathrm{B}}\right) \\ $$

Question Number 210248 Answers: 1 Comments: 0

Question Number 210236 Answers: 2 Comments: 0

Question Number 210235 Answers: 2 Comments: 2

Question Number 210234 Answers: 2 Comments: 2

Question Number 210233 Answers: 2 Comments: 0

Question Number 210231 Answers: 0 Comments: 1

Resoudre dans R { ((acos x−bsin x=c (x≠0))),((sin ((1/(sin x))) =d (−1≤d≤+1))) :}

$$\mathrm{Resoudre}\:\boldsymbol{\mathrm{dans}}\:\mathbb{R} \\ $$$$\begin{cases}{\boldsymbol{\mathrm{a}}\mathrm{cos}\:\boldsymbol{\mathrm{x}}−\boldsymbol{\mathrm{b}}\mathrm{sin}\:\boldsymbol{\mathrm{x}}=\boldsymbol{\mathrm{c}}\:\:\:\:\:\left(\boldsymbol{\mathrm{x}}\neq\mathrm{0}\right)}\\{\mathrm{sin}\:\left(\frac{\mathrm{1}}{\mathrm{sin}\:\boldsymbol{\mathrm{x}}}\right)\:\:\:\:\:\:\:\:\:=\boldsymbol{\mathrm{d}}\:\:\:\:\left(−\mathrm{1}\leqslant\boldsymbol{\mathrm{d}}\leqslant+\mathrm{1}\right)}\end{cases} \\ $$$$ \\ $$

Question Number 210208 Answers: 4 Comments: 0

∫_0 ^1 e^e^e^x e^e^x e^x dx

$$ \\ $$$$\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\int_{\mathrm{0}} ^{\mathrm{1}} \:{e}^{{e}^{{e}^{{x}} } } \:{e}^{{e}^{{x}} } \:{e}^{{x}} {dx} \\ $$$$ \\ $$

Question Number 210206 Answers: 0 Comments: 0

Ω=∫_(1/e) ^e (dx/((1+x^2 )(1+xlog^7 x)))

$$ \\ $$$$\:\:\:\:\:\:\:\:\:\:\:\:\:\:\Omega=\int_{\frac{\mathrm{1}}{{e}}} ^{{e}} \frac{{dx}}{\left(\mathrm{1}+{x}^{\mathrm{2}} \right)\left(\mathrm{1}+{x}\mathrm{log}\:^{\mathrm{7}} {x}\right)} \\ $$$$ \\ $$

Question Number 210229 Answers: 3 Comments: 0

Question Number 210228 Answers: 0 Comments: 0

Question Number 210227 Answers: 0 Comments: 0

Question Number 210369 Answers: 0 Comments: 0

Question Number 210194 Answers: 0 Comments: 1

Question Number 210181 Answers: 0 Comments: 3

Question Number 210180 Answers: 1 Comments: 2

Question Number 210172 Answers: 3 Comments: 0

Question Number 210171 Answers: 0 Comments: 0

Find: lim_(n→+∞) (n/((n!)^2 4^n )) Π_(k=1) ^n ((2k−1)^2 + 4) = ?

$$\mathrm{Find}: \\ $$$$\underset{\boldsymbol{\mathrm{n}}\rightarrow+\infty} {\mathrm{lim}}\:\:\frac{\mathrm{n}}{\left(\mathrm{n}!\right)^{\mathrm{2}} \:\mathrm{4}^{\boldsymbol{\mathrm{n}}} }\:\:\underset{\boldsymbol{\mathrm{k}}=\mathrm{1}} {\overset{\boldsymbol{\mathrm{n}}} {\prod}}\:\left(\left(\mathrm{2k}−\mathrm{1}\right)^{\mathrm{2}} \:+\:\mathrm{4}\right)\:=\:? \\ $$

Question Number 210157 Answers: 3 Comments: 0

Question Number 210156 Answers: 1 Comments: 0

Question Number 210155 Answers: 1 Comments: 0

Question Number 210142 Answers: 0 Comments: 1

Question Number 210133 Answers: 1 Comments: 0

calcul ∫_0 ^1 [nt^(n−1) (1−t)−t^n ]dt

$${calcul} \\ $$$$\int_{\mathrm{0}} ^{\mathrm{1}} \left[{nt}^{{n}−\mathrm{1}} \left(\mathrm{1}−{t}\right)−{t}^{{n}} \right]{dt} \\ $$

Question Number 210127 Answers: 1 Comments: 0

Question Number 210126 Answers: 1 Comments: 0

Question Number 210124 Answers: 0 Comments: 0

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