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Question Number 88306 Answers: 0 Comments: 5

Question Number 88301 Answers: 0 Comments: 2

A circle touches the four sides of quadrilateral ABCD. Show/prove that AB+CD=BC+DA. Please help.

$${A}\:{circle}\:{touches}\:{the}\:{four}\:{sides} \\ $$$${of}\:{quadrilateral}\:{ABCD}.\:\mathrm{Show}/\mathrm{prove} \\ $$$$\mathrm{that}\:\mathrm{A}{B}+{CD}={BC}+{DA}. \\ $$$$\mathrm{Please}\:\mathrm{help}. \\ $$

Question Number 88300 Answers: 0 Comments: 0

A circle touches the four sides of quadrilateral ABCD. Show/prove that AB+CD=BC+DA. Please help.

$${A}\:{circle}\:{touches}\:{the}\:{four}\:{sides} \\ $$$${of}\:{quadrilateral}\:{ABCD}.\:\mathrm{Show}/\mathrm{prove} \\ $$$$\mathrm{that}\:\mathrm{A}{B}+{CD}={BC}+{DA}. \\ $$$$\mathrm{Please}\:\mathrm{help}. \\ $$

Question Number 88307 Answers: 1 Comments: 0

∫(x^2 /(x^2 −(5/2)x−(3/2))) dx

$$\int\frac{{x}^{\mathrm{2}} }{{x}^{\mathrm{2}} −\frac{\mathrm{5}}{\mathrm{2}}{x}−\frac{\mathrm{3}}{\mathrm{2}}}\:{dx} \\ $$

Question Number 88289 Answers: 0 Comments: 5

Question Number 88288 Answers: 1 Comments: 1

Question Number 88286 Answers: 0 Comments: 1

Question Number 88272 Answers: 1 Comments: 1

Question Number 88270 Answers: 0 Comments: 1

Question Number 88263 Answers: 1 Comments: 1

prove that ∣((e^z −e^(−z) )/2)∣^2 +cos^2 y=sinh^2 x when z=x+iy

$${prove}\:{that}\: \\ $$$$\mid\frac{{e}^{{z}} −{e}^{−{z}} }{\mathrm{2}}\mid^{\mathrm{2}} +{cos}^{\mathrm{2}} {y}={sinh}^{\mathrm{2}} {x}\:\:\:\:\:{when}\:{z}={x}+{iy} \\ $$$$ \\ $$

Question Number 88261 Answers: 1 Comments: 0

Question Number 88253 Answers: 0 Comments: 0

∫ ((ln(x^2 +1) dx)/(x+1))

$$\int\:\frac{\mathrm{ln}\left({x}^{\mathrm{2}} +\mathrm{1}\right)\:{dx}}{{x}+\mathrm{1}}\: \\ $$

Question Number 88252 Answers: 0 Comments: 0

Question Number 88251 Answers: 0 Comments: 0

Question Number 88245 Answers: 2 Comments: 0

Question Number 88240 Answers: 1 Comments: 3

Question Number 88239 Answers: 0 Comments: 0

Question Number 88238 Answers: 1 Comments: 0

solve (3x^5 y^4 +4y)dx+(2x^6 y^3 +3x)dy=0

$${solve}\: \\ $$$$\left(\mathrm{3}{x}^{\mathrm{5}} {y}^{\mathrm{4}} +\mathrm{4}{y}\right){dx}+\left(\mathrm{2}{x}^{\mathrm{6}} {y}^{\mathrm{3}} +\mathrm{3}{x}\right){dy}=\mathrm{0} \\ $$

Question Number 88236 Answers: 1 Comments: 0

Evaluate ∫(((27)/(x^3 −6)))^(1/3) dx

$$\:\mathrm{Evaluate}\:\:\int\sqrt[{\mathrm{3}}]{\frac{\mathrm{27}}{{x}^{\mathrm{3}} −\mathrm{6}}}\:{dx}\: \\ $$

Question Number 88235 Answers: 0 Comments: 1

find a maclaurine series solution to the differential equation up to the term in x^4 . (dy/dx) − x = xy if y = 1 when x = 0.

$$\:\mathrm{find}\:\mathrm{a}\:\mathrm{maclaurine}\:\mathrm{series}\:\mathrm{solution}\:\mathrm{to}\:\mathrm{the}\:\mathrm{differential}\:\mathrm{equation} \\ $$$$\mathrm{up}\:\mathrm{to}\:\mathrm{the}\:\mathrm{term}\:\mathrm{in}\:{x}^{\mathrm{4}} . \\ $$$$\:\frac{{dy}}{{dx}}\:−\:{x}\:=\:{xy}\:\:\:\mathrm{if}\:\:{y}\:=\:\mathrm{1}\:\mathrm{when}\:{x}\:=\:\mathrm{0}. \\ $$

Question Number 88232 Answers: 0 Comments: 0

Question Number 88218 Answers: 1 Comments: 2

Question Number 88214 Answers: 2 Comments: 0

Question Number 88212 Answers: 0 Comments: 0

Σ[(e^s^e^s^ −x)^r ]^((s+5)((sin x)/(tan y))) =i s=5 r=2 x=90° y=45° i=?

$$\Sigma\left[\left(\mathrm{e}^{\mathrm{s}^{\mathrm{e}^{\mathrm{s}^{} } } } −\mathrm{x}\right)^{\mathrm{r}} \right]^{\left(\mathrm{s}+\mathrm{5}\right)\frac{\mathrm{sin}\:{x}}{\mathrm{tan}\:{y}}} \:={i} \\ $$$${s}=\mathrm{5} \\ $$$$\mathrm{r}=\mathrm{2} \\ $$$${x}=\mathrm{90}° \\ $$$$ \\ $$$$\mathrm{y}=\mathrm{45}° \\ $$$$\mathrm{i}=? \\ $$$$ \\ $$

Question Number 88211 Answers: 0 Comments: 0

Question Number 88210 Answers: 1 Comments: 0

If f(x)= { ((1−x, 0≤x≤1)),((0, 1≤x≤2 )),(((2−x)^2 , 2≤x≤3)) :} and φ(x)=∫_( 0) ^x f(t) dt. Then for any x ∈ [2, 3], φ(x) =

$$\mathrm{If}\:{f}\left({x}\right)=\begin{cases}{\mathrm{1}−{x},\:\:\:\:\:\:\:\:\:\mathrm{0}\leqslant{x}\leqslant\mathrm{1}}\\{\mathrm{0},\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\mathrm{1}\leqslant{x}\leqslant\mathrm{2}\:\:\:\:}\\{\left(\mathrm{2}−{x}\right)^{\mathrm{2}} ,\:\:\:\mathrm{2}\leqslant{x}\leqslant\mathrm{3}}\end{cases}\:\mathrm{and}\: \\ $$$$\phi\left({x}\right)=\underset{\:\mathrm{0}} {\overset{\mathrm{x}} {\int}}\:{f}\left({t}\right)\:{dt}.\:\mathrm{Then}\:\mathrm{for}\:\mathrm{any}\:{x}\:\in\:\left[\mathrm{2},\:\mathrm{3}\right],\: \\ $$$$\phi\left({x}\right)\:= \\ $$

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