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AllQuestion and Answers: Page 1259

Question Number 90113 Answers: 1 Comments: 0

∫_0 ^∞ e^(−x) ((1/(1−e^(−x) ))−(1/x))dx

$$\int_{\mathrm{0}} ^{\infty} {e}^{−{x}} \left(\frac{\mathrm{1}}{\mathrm{1}−{e}^{−{x}} }−\frac{\mathrm{1}}{{x}}\right){dx} \\ $$

Question Number 90110 Answers: 0 Comments: 2

∫_((2/3)u) ^(2u) (e^(−(x/2)) /(2π (√((u−(1/2)x)(((3x)/2)−u))))) du (u > 0 )

$$\underset{\frac{\mathrm{2}}{\mathrm{3}}\mathrm{u}} {\overset{\mathrm{2u}} {\int}}\:\frac{\mathrm{e}^{−\frac{\mathrm{x}}{\mathrm{2}}} }{\mathrm{2}\pi\:\sqrt{\left(\mathrm{u}−\frac{\mathrm{1}}{\mathrm{2}}\mathrm{x}\right)\left(\frac{\mathrm{3x}}{\mathrm{2}}−\mathrm{u}\right)}}\:\mathrm{du}\: \\ $$$$\left(\mathrm{u}\:>\:\mathrm{0}\:\right) \\ $$

Question Number 90103 Answers: 0 Comments: 1

Question Number 90100 Answers: 1 Comments: 0

Question Number 90099 Answers: 0 Comments: 2

given the polar equation r = a^2 sin2θ show the tangents at the poles of this polar equation is. θ = {(π/4),((3π)/4),((5π)/4),((7π)/4)}

$$\:\mathrm{given}\:\mathrm{the}\:\mathrm{polar}\:\mathrm{equation} \\ $$$$\:{r}\:=\:{a}^{\mathrm{2}} \:\mathrm{sin2}\theta\:\:\mathrm{show}\:\mathrm{the}\:\mathrm{tangents}\:\mathrm{at}\: \\ $$$$\mathrm{the}\:\mathrm{poles}\:\mathrm{of}\:\mathrm{this}\:\mathrm{polar}\:\mathrm{equation}\:\mathrm{is}. \\ $$$$\:\theta\:=\:\left\{\frac{\pi}{\mathrm{4}},\frac{\mathrm{3}\pi}{\mathrm{4}},\frac{\mathrm{5}\pi}{\mathrm{4}},\frac{\mathrm{7}\pi}{\mathrm{4}}\right\} \\ $$

Question Number 90097 Answers: 0 Comments: 1

((√(3+(√8))))^x +((√(3−(√8))))^x = 6

$$\left(\sqrt{\mathrm{3}+\sqrt{\mathrm{8}}}\right)^{\mathrm{x}} \:+\left(\sqrt{\mathrm{3}−\sqrt{\mathrm{8}}}\right)^{\mathrm{x}} \:=\:\mathrm{6} \\ $$

Question Number 90090 Answers: 1 Comments: 0

xy (dy/dx) = y^2 + ((x^3 /(x^2 +1)))

$${xy}\:\frac{{dy}}{{dx}}\:=\:{y}^{\mathrm{2}} \:+\:\left(\frac{{x}^{\mathrm{3}} }{{x}^{\mathrm{2}} +\mathrm{1}}\right) \\ $$

Question Number 90083 Answers: 0 Comments: 0

Question Number 90086 Answers: 0 Comments: 7

Question Number 90087 Answers: 0 Comments: 1

Σ_(k = 1) ^∞ (1/k^k ) = ?

$$\underset{{k}\:=\:\mathrm{1}} {\overset{\infty} {\sum}}\frac{\mathrm{1}}{{k}^{{k}} }\:=\:? \\ $$

Question Number 90080 Answers: 0 Comments: 0

Question Number 90077 Answers: 0 Comments: 3

lim_(x→∞) (sin (x+(1/x))−sin(x))=?

$${lim}_{{x}\rightarrow\infty} \left(\mathrm{sin}\:\left({x}+\frac{\mathrm{1}}{{x}}\right)−{sin}\left({x}\right)\right)=? \\ $$

Question Number 90075 Answers: 0 Comments: 1

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Question Number 90073 Answers: 0 Comments: 0

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Question Number 90092 Answers: 0 Comments: 1

G((√(x+5))) = x G(x^2 ) = x^a −b find a+b

$$\mathrm{G}\left(\sqrt{\mathrm{x}+\mathrm{5}}\right)\:=\:\mathrm{x} \\ $$$$\mathrm{G}\left(\mathrm{x}^{\mathrm{2}} \right)\:=\:\mathrm{x}^{\mathrm{a}} −\mathrm{b} \\ $$$$\mathrm{find}\:\mathrm{a}+\mathrm{b}\: \\ $$

Question Number 90069 Answers: 2 Comments: 3

Question Number 90060 Answers: 0 Comments: 1

lim_(x→0) ((ln (1+sin x))/(((2+x))^(1/(3 )) − ((2+3x))^(1/3) )) = ?

$$\underset{{x}\rightarrow\mathrm{0}} {\mathrm{lim}}\:\frac{\mathrm{ln}\:\left(\mathrm{1}+\mathrm{sin}\:\mathrm{x}\right)}{\sqrt[{\mathrm{3}\:\:}]{\mathrm{2}+\mathrm{x}}\:−\:\sqrt[{\mathrm{3}}]{\mathrm{2}+\mathrm{3x}}}\:=\:? \\ $$

Question Number 90058 Answers: 1 Comments: 1

Question Number 90055 Answers: 0 Comments: 1

Question Number 90049 Answers: 0 Comments: 0

Question Number 90048 Answers: 1 Comments: 0

5^(√x) −5^(x−7) = 100

$$\mathrm{5}^{\sqrt{\mathrm{x}}} \:−\mathrm{5}^{\mathrm{x}−\mathrm{7}} \:=\:\mathrm{100} \\ $$

Question Number 90046 Answers: 0 Comments: 0

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Question Number 90044 Answers: 0 Comments: 2

calculste ∫_0 ^1 sin([2x] −[(1/x)])dx

$${calculste}\:\int_{\mathrm{0}} ^{\mathrm{1}} \:{sin}\left(\left[\mathrm{2}{x}\right]\:−\left[\frac{\mathrm{1}}{{x}}\right]\right){dx} \\ $$

Question Number 90043 Answers: 0 Comments: 0

calculate f(a) =∫_0 ^∞ ((arctan(ax))/(x^2 +a^2 ))dx with a>0

$${calculate}\:{f}\left({a}\right)\:=\int_{\mathrm{0}} ^{\infty} \:\frac{{arctan}\left({ax}\right)}{{x}^{\mathrm{2}} \:+{a}^{\mathrm{2}} }{dx}\:{with}\:{a}>\mathrm{0} \\ $$

Question Number 90042 Answers: 0 Comments: 1

calculste I =∫_0 ^(+∞) ((ch(cos(2x))dx)/(x^2 +4)) and J =∫_0 ^∞ ((cos(2chx)dx)/(x^2 +4)) compare I and J

$${calculste}\:{I}\:=\int_{\mathrm{0}} ^{+\infty} \:\frac{{ch}\left({cos}\left(\mathrm{2}{x}\right)\right){dx}}{{x}^{\mathrm{2}} \:+\mathrm{4}} \\ $$$${and}\:{J}\:=\int_{\mathrm{0}} ^{\infty} \:\frac{{cos}\left(\mathrm{2}{chx}\right){dx}}{{x}^{\mathrm{2}} \:+\mathrm{4}} \\ $$$${compare}\:{I}\:{and}\:{J} \\ $$

Question Number 90041 Answers: 1 Comments: 0

calculste ∫_0 ^∞ ((xarctan(2x))/(9+2x^2 ))dx

$${calculste}\:\int_{\mathrm{0}} ^{\infty} \:\:\frac{{xarctan}\left(\mathrm{2}{x}\right)}{\mathrm{9}+\mathrm{2}{x}^{\mathrm{2}} }{dx}\: \\ $$

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