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Question Number 210755 Answers: 0 Comments: 0

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Question Number 210737 Answers: 1 Comments: 0

f(x)=(x^2 /(x^2 +1)) then f((1/1))+f((2/1))+.....+f(((100)/1))+f((1/2)) +f((2/2))+...+f(((100)/2))+f((1/(100)))+f((2/(100))) +......+f(((100)/(100)))=?

Question Number 210729 Answers: 3 Comments: 0

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Question Number 210723 Answers: 1 Comments: 0

the volume of the region between the planes x+y+2z=2 and 2x+y+z = 4 in the first octant is

$$\mathrm{the}\:\mathrm{volume}\:\mathrm{of}\:\mathrm{the}\:\mathrm{region}\:\mathrm{between}\:\mathrm{the}\: \\ $$$$\mathrm{planes}\:\mathrm{x}+\mathrm{y}+\mathrm{2z}=\mathrm{2}\:\mathrm{and}\:\mathrm{2x}+\mathrm{y}+\mathrm{z}\:=\:\mathrm{4}\:\mathrm{in}\: \\ $$$$\mathrm{the}\:\mathrm{first}\:\mathrm{octant}\:\mathrm{is} \\ $$

Question Number 210718 Answers: 0 Comments: 1

If sin1° = a (1/(cos1°∙cos2°)) + (1/(cos2°∙cos3°)) +...+ (1/(cos44°∙cos45°)) = ?

$$\mathrm{If}\:\:\:\mathrm{sin1}°\:=\:\mathrm{a} \\ $$$$\frac{\mathrm{1}}{\mathrm{cos1}°\centerdot\mathrm{cos2}°}\:+\:\frac{\mathrm{1}}{\mathrm{cos2}°\centerdot\mathrm{cos3}°}\:+...+\:\frac{\mathrm{1}}{\mathrm{cos44}°\centerdot\mathrm{cos45}°}\:=\:? \\ $$

Question Number 210719 Answers: 2 Comments: 0

find 63!^(36!) mod97 thanks

$${find}\:\mathrm{63}!^{\mathrm{36}!} {mod}\mathrm{97}\:\:\:{thanks} \\ $$

Question Number 210706 Answers: 0 Comments: 0

Question Number 210702 Answers: 2 Comments: 0

How many real solutions does the equation x=sin3x have?

$$\mathrm{How}\:\mathrm{many}\:\mathrm{real}\:\mathrm{solutions}\:\mathrm{does}\:\mathrm{the} \\ $$$$\mathrm{equation}\:{x}=\mathrm{sin3}{x}\:\mathrm{have}? \\ $$

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Question Number 210688 Answers: 0 Comments: 1

In a convex quadrilateral ABCD, diagonals AC and BD intersect at E, while perpendicular bisectors of AB and CD intersect at F, and those of BC and DA intersect at G. Prove: (1) E, F, and G are collinear, (2) AE:EC = BF:FD, and (3) CG:GD = AF:FB.

$$ \\ $$In a convex quadrilateral ABCD, diagonals AC and BD intersect at E, while perpendicular bisectors of AB and CD intersect at F, and those of BC and DA intersect at G. Prove: (1) E, F, and G are collinear, (2) AE:EC = BF:FD, and (3) CG:GD = AF:FB.

Question Number 210687 Answers: 0 Comments: 2