Question and Answers Forum

AllQuestion and Answers: Page 1222

Question Number 85776 Answers: 1 Comments: 0

Question Number 85775 Answers: 0 Comments: 0

Question Number 85774 Answers: 0 Comments: 0

(x_(2n) )=2^(2n) ((x/2))_n (((x+1)/2))_n (x)_(m n) =m^(m n) Π_(k=0) ^(m=1) (((x+k)/m))_n , m∈z now if m is relative number such as(3/2) , m∈Q (x)_((3/2)n) =?? help me

$(x_{2 n}) = 2^{2 n} {(\frac{x}{2})}_{n} {(\frac{x + 1}{2})}_{n}$ ${(x)}_{m n} = m^{m n} \underset{k = 0}{\prod^{m = 1}} {(\frac{x + k}{m})}_{n}, m \in z$ $n o w i f m i s r e l a t i v e n u m b e r s u c h a s \frac{3}{2}, m \in Q$ ${(x)}_{\frac{3}{2} n} = ? ?$ $h e l p m e$

Question Number 85766 Answers: 0 Comments: 2

(dy/dx) = 1−sin (x+2y)

$\frac{dy}{dx} = 1 - \sin (x + 2 y)$

Question Number 85762 Answers: 0 Comments: 12

Question Number 85760 Answers: 0 Comments: 0

∫(([cos^(−1) (x){(√(1−x^2 ))}]^(−1) )/(log{((sin(2x(√(1−x^2 ))))/π)})) dx

$\int \frac{{[{c o s}^{- 1} (x) {\sqrt{1 - x^{2}}}]}^{- 1}}{l o g {\frac{s i n (2 x \sqrt{1 - x^{2}})}{π}}} d x$

Question Number 85756 Answers: 0 Comments: 5

Question Number 85739 Answers: 1 Comments: 0

If F (x)=∫_x^2 ^x^3 log t dt (x>0), then F ′(x)=

$If F (x) = \underset{x^{2}}{\int^{x^{3}}} \log t d t (x > 0), then F^{'} (x) =$

Question Number 85729 Answers: 0 Comments: 6

if march 24, 2020 is Tuesday, then march 24, 2032 is the day ?

$if march 24, 2020 is Tuesday,$ $then march 24, 2032 is the day ?$

Question Number 85721 Answers: 1 Comments: 0

show that ∫_0 ^∞ ((e^(−x) ln(x))/(√x))dx=−(√π)(γ+ln(4))

$s h o w t h a t$ $\int_{0}^{\infty} \frac{e^{- x} l n (x)}{\sqrt{x}} d x = - \sqrt{π} (γ + l n (4))$

Question Number 85718 Answers: 1 Comments: 0

∫((sin(x)−cos(3x))/(sin(x)−cos(2x)))dx

$\int \frac{s i n (x) - c o s (3 x)}{s i n (x) - c o s (2 x)} d x$

Question Number 85717 Answers: 1 Comments: 0

∫_0 ^2 x^4 (√(1−x^2 )) dx ∫_0 ^1 x^(10) (1−x^n )dx

$\int_{0}^{2} x^{4} \sqrt{1 - x^{2}} d x$ $\int_{0}^{1} x^{10} (1 - x^{n}) d x$

Question Number 85711 Answers: 0 Comments: 2

∫_(−4) ^2 ((2x + 1)/((x^2 + x + 1)^(3/2) )) dx

$\underset{- 4}{\int^{2}} \frac{2 x + 1}{{(x^{2} + x + 1)}^{3 / 2}} d x$

Question Number 85709 Answers: 1 Comments: 0

Question Number 85708 Answers: 1 Comments: 0

lim_(n−∞) /((U_n +1)/(Un))/ >0 Test for convergence

$l i \underset{n - \infty}{m} / \frac{U_{n} + 1}{U n} / > 0$ $T e s t f o r c o n v e r g e n c e$

Question Number 85706 Answers: 1 Comments: 0

Find the general solution of x^2 (√(y^2 +9)) dx + 5 (√(x^2 −3)) y dy = 0

$F i n d t h e g e n e r a l s o l u t i o n o f$ $x^{2} \sqrt{y^{2} + 9} d x + 5 \sqrt{x^{2} - 3} y d y = 0$

Question Number 85701 Answers: 1 Comments: 3

∫ ((√(3x−1))/(√(2x+1))) dx

$\int \frac{\sqrt{3 x - 1}}{\sqrt{2 x + 1}} dx$

Question Number 85698 Answers: 0 Comments: 0

please any recommendation of a youtube video on General conics??

$please any recommendation of a youtube video$ $on General conics ? ?$

Question Number 85696 Answers: 0 Comments: 0

Montrer que: (√5)+(√(30))+(√(50))<(√(10))+(√(20))+(√(60)) {niveau second)

$Montrer que :$ $\sqrt{5} + \sqrt{30} + \sqrt{50} < \sqrt{10} + \sqrt{20} + \sqrt{60}$ ${niveau second)$

Question Number 85695 Answers: 0 Comments: 0

Question Number 85694 Answers: 0 Comments: 1

log_(((x/(x−3)))) (7) < log_(((x/3))) (7)

$\log_{(\frac{x}{x - 3})} (7) < \log_{(\frac{x}{3})} (7)$

Question Number 85677 Answers: 2 Comments: 3

∫_0 ^π ((sin (((21x)/2)))/(sin ((x/2)))) dx

$\underset{0}{\int^{π}} \frac{\sin (\frac{21 x}{2})}{\sin (\frac{x}{2})} d x$

Question Number 85676 Answers: 0 Comments: 15

∫ _0 ^∞ (dx/((x+(√(1+x^2 )))^2 )) let x = tan t ⇒dx=sec^2 t dt ∫_0 ^(π/2) ((sec^2 t dt)/((tan t+sec t)^2 )) = ∫_0 ^(π/2) (dt/((sin t+1)^2 )) = ∫_0 ^(π/2) (dt/((cos (1/2)t+sin (1/2)t)^4 )) = ∫_0 ^(π/2) (dt/(4cos^4 ((1/2)t−(π/4)))) = (1/4)∫_0 ^(π/2) sec^4 ((1/2)t−(π/4)) dt [ let (1/2)t−(π/4)= u] = (1/4)∫_(−(π/4)) ^0 sec^4 u ×2du =(1/2)∫ _(−(π/4)) ^0 (tan^2 u+1) d(tan u) = (1/2) [(1/3)tan^3 u + tan u ]_(−(π/4)) ^0 = (1/2) [ 0−(−(1/3)−1)]= (2/3)

$\int \underset{0}{\overset{\infty}{}} \frac{d x}{{(x + \sqrt{1 + x^{2}})}^{2}}$ $l e t x = \tan t \Rightarrow d x = \sec^{2} t d t$ $\underset{0}{\int^{\frac{π}{2}}} \frac{\sec^{2} t d t}{{(\tan t + \sec t)}^{2}} =$ $\underset{0}{\int^{\frac{π}{2}}} \frac{d t}{{(\sin t + 1)}^{2}} = \underset{0}{\int^{\frac{π}{2}}} \frac{d t}{{(\cos \frac{1}{2} t + \sin \frac{1}{2} t)}^{4}}$ $= \underset{0}{\int^{\frac{π}{2}}} \frac{d t}{{4 \cos}^{4} (\frac{1}{2} t - \frac{π}{4})}$ $= \frac{1}{4} \underset{0}{\int^{\frac{π}{2}}} \sec^{4} (\frac{1}{2} t - \frac{π}{4}) d t$ $[l e t \frac{1}{2} t - \frac{π}{4} = u]$ $= \frac{1}{4} \underset{- \frac{π}{4}}{\int^{0}} \sec^{4} u \times 2 d u$ $= \frac{1}{2} \int \underset{- \frac{π}{4}}{\overset{0}{}} (\tan^{2} u + 1) d (\tan u)$ $= \frac{1}{2} {[\frac{1}{3} \tan^{3} u + \tan u]}_{- \frac{π}{4}}^{0}$ $= \frac{1}{2} [0 - (- \frac{1}{3} - 1)] = \frac{2}{3}$

Question Number 85670 Answers: 0 Comments: 3

Question Number 85669 Answers: 1 Comments: 4

∫ ((√(1+x))/(√(1−x))) dx

$\int \frac{\sqrt{1 + x}}{\sqrt{1 - x}} d x$

Question Number 85668 Answers: 0 Comments: 2

z = 2 + i find arg(z)

$z = 2 + i$ $find \arg (z)$

Pg 1217 Pg 1218 Pg 1219 Pg 1220 Pg 1221 Pg 1222 Pg 1223 Pg 1224 Pg 1225 Pg 1226

Contact: info@tinkutara.com