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Question Number 94818 Answers: 1 Comments: 7

find such a polynomial if is divided by (x−2) then the remainder is 5, if it isdivided by (x−3) the remainder is 9, if it is divided by (x−4) the remainder is 13, if divide by (x−10) and the remaider becomes 37 and if (x−(3/4)) divided by the remainder becomes zero?

$$\:\mathrm{find}\:\mathrm{such}\:\mathrm{a}\:\mathrm{polynomial}\:\mathrm{if}\:\mathrm{is}\:\mathrm{divided}\:\mathrm{by}\:\left(\mathrm{x}−\mathrm{2}\right)\:\mathrm{then}\:\mathrm{the}\: \\ $$$$\mathrm{remainder}\:\mathrm{is}\:\mathrm{5},\:\mathrm{if}\:\mathrm{it}\:\mathrm{isdivided}\:\mathrm{by}\:\left(\mathrm{x}−\mathrm{3}\right)\:\mathrm{the}\:\mathrm{remainder} \\ $$$$\mathrm{is}\:\mathrm{9},\:\mathrm{if}\:\mathrm{it}\:\mathrm{is}\:\mathrm{divided}\:\mathrm{by}\:\left(\mathrm{x}−\mathrm{4}\right)\:\mathrm{the}\:\mathrm{remainder}\:\mathrm{is}\:\mathrm{13},\:\mathrm{if}\: \\ $$$$\mathrm{divide}\:\mathrm{by}\:\left(\mathrm{x}−\mathrm{10}\right)\:\mathrm{and}\:\mathrm{the}\:\mathrm{remaider}\:\mathrm{becomes}\:\mathrm{37}\:\mathrm{and} \\ $$$$\mathrm{if}\:\left(\mathrm{x}−\frac{\mathrm{3}}{\mathrm{4}}\right)\:\mathrm{divided}\:\mathrm{by}\:\mathrm{the}\:\mathrm{remainder}\:\mathrm{becomes}\:\mathrm{zero}? \\ $$

Question Number 94816 Answers: 1 Comments: 2

Question Number 94811 Answers: 3 Comments: 0

∫(dx/(x+(√x))) (2,3)=?

$$\int\frac{\mathrm{dx}}{\mathrm{x}+\sqrt{\mathrm{x}}}\:\:\:\left(\mathrm{2},\mathrm{3}\right)=? \\ $$

Question Number 94806 Answers: 0 Comments: 2

Question Number 94803 Answers: 1 Comments: 0

Question Number 94801 Answers: 0 Comments: 0

Question Number 94797 Answers: 1 Comments: 0

Question Number 94786 Answers: 0 Comments: 1

x, y ∈N\{0, 1} ∧ x≤y find z∈N with z!=x!y!

$${x},\:{y}\:\in\mathbb{N}\backslash\left\{\mathrm{0},\:\mathrm{1}\right\}\:\wedge\:{x}\leqslant{y} \\ $$$$\mathrm{find}\:{z}\in\mathbb{N}\:\mathrm{with}\:{z}!={x}!{y}! \\ $$

Question Number 94782 Answers: 1 Comments: 0

The velocity of physical quantities is given by v = (√((P + (1/n))/x)) , where P is the pressure. Find the dimention of n and x.

$$\mathrm{The}\:\mathrm{velocity}\:\mathrm{of}\:\mathrm{physical}\:\mathrm{quantities}\:\mathrm{is}\:\mathrm{given}\:\mathrm{by} \\ $$$$\:\:\mathrm{v}\:\:=\:\:\sqrt{\frac{\mathrm{P}\:\:+\:\:\frac{\mathrm{1}}{\mathrm{n}}}{\mathrm{x}}}\:,\:\:\mathrm{where}\:\:\mathrm{P}\:\mathrm{is}\:\mathrm{the}\:\mathrm{pressure}. \\ $$$$\mathrm{Find}\:\mathrm{the}\:\mathrm{dimention}\:\mathrm{of}\:\:\:\mathrm{n}\:\:\mathrm{and}\:\:\mathrm{x}. \\ $$

Question Number 94780 Answers: 0 Comments: 1

x!(x−4)!=12(2x−7)! x=?

$$\mathrm{x}!\left(\mathrm{x}−\mathrm{4}\right)!=\mathrm{12}\left(\mathrm{2x}−\mathrm{7}\right)! \\ $$$$\mathrm{x}=? \\ $$

Question Number 94776 Answers: 0 Comments: 0

Question Number 94774 Answers: 2 Comments: 1

Question Number 94773 Answers: 1 Comments: 0

Question Number 94772 Answers: 0 Comments: 0

Question Number 94769 Answers: 2 Comments: 0

Question Number 94768 Answers: 1 Comments: 0

Question Number 94767 Answers: 1 Comments: 0

Question Number 94764 Answers: 2 Comments: 0

Question Number 94765 Answers: 0 Comments: 0

Question Number 94756 Answers: 0 Comments: 2

solution: Q1)a) n=((ln(m/m_0 ))/(ln0.5)) = ((ln(12/75))/(ln0.5)) =2.64 N=N_0 (0.5)^n = 6.02×10^(23) (0.5)^(2.64) = 9.66×10^(22) A=λN=1.5×10^(−4) × 9.66×10^(22) =1.45×10^(19) Bq

$$\left.{s}\left.{olution}:\:\mathrm{Q1}\right){a}\right)\:{n}=\frac{{ln}\left({m}/{m}_{\mathrm{0}} \right)}{{ln}\mathrm{0}.\mathrm{5}}\:=\:\frac{{ln}\left(\mathrm{12}/\mathrm{75}\right)}{{ln}\mathrm{0}.\mathrm{5}}\:=\mathrm{2}.\mathrm{64} \\ $$$${N}=\mathrm{N}_{\mathrm{0}} \left(\mathrm{0}.\mathrm{5}\right)^{{n}} \:=\:\mathrm{6}.\mathrm{02}×\mathrm{10}^{\mathrm{23}} \left(\mathrm{0}.\mathrm{5}\right)^{\mathrm{2}.\mathrm{64}} =\:\mathrm{9}.\mathrm{66}×\mathrm{10}^{\mathrm{22}} \\ $$$${A}=\lambda{N}=\mathrm{1}.\mathrm{5}×\mathrm{10}^{−\mathrm{4}} \:×\:\mathrm{9}.\mathrm{66}×\mathrm{10}^{\mathrm{22}} =\mathrm{1}.\mathrm{45}×\mathrm{10}^{\mathrm{19}} \:{Bq} \\ $$

Question Number 94752 Answers: 0 Comments: 1

Find the volume of the region bounded above by the surface z=x and below by the region x^2 +y^2 −2y=0 ? pleas sir can you help me becouse im very nedd ?

$${Find}\:{the}\:{volume}\:{of}\:{the}\:{region}\:{bounded}\:{above}\:{by}\:{the}\:{surface}\:{z}={x} \\ $$$${and}\:{below}\:{by}\:{the}\:{region}\:{x}^{\mathrm{2}} +{y}^{\mathrm{2}} −\mathrm{2}{y}=\mathrm{0}\:? \\ $$$${pleas}\:{sir}\:{can}\:{you}\:{help}\:{me}\:{becouse}\:{im}\:{very}\:{nedd}\:? \\ $$

Question Number 94742 Answers: 0 Comments: 1

Question Number 94739 Answers: 2 Comments: 2

Question Number 94735 Answers: 0 Comments: 9

∫((2t)/((1+t^4 )(1+t)))dt=?

$$\int\frac{\mathrm{2t}}{\left(\mathrm{1}+\mathrm{t}^{\mathrm{4}} \right)\left(\mathrm{1}+\mathrm{t}\right)}\mathrm{dt}=? \\ $$

Question Number 94753 Answers: 1 Comments: 0

Question Number 94730 Answers: 2 Comments: 0

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